Electromagnetic Waves is Chapter 8 of CBSE Class 12 Physics. This chapter covers the nature of electromagnetic waves, Maxwell’s equations (qualitative), the electromagnetic spectrum, and the properties and uses of different types of EM waves — from radio waves to gamma rays.
This chapter carries 3–5 marks. The EM spectrum, properties of different waves, and displacement current concept are commonly tested.
Key Concepts
1. Displacement Current and Maxwell’s Equations
Maxwell showed that a changing electric field produces a magnetic field, just as a changing magnetic field produces an electric field (Faraday’s law). He introduced the concept of displacement current:
Id = ε₀(dΦE/dt)
This completed Ampere’s law: ∮B·dl = μ₀(Ic + Id), making the equations symmetric.
2. Properties of EM Waves
- Produced by accelerating charges
- Do not need a medium — travel through vacuum at speed c = 3 × 10⁸ m/s
- E and B fields are perpendicular to each other and to the direction of propagation (transverse waves)
- c = 1/√(μ₀ε₀) = E₀/B₀
- Carry energy and momentum
- Follow c = fλ
3. Electromagnetic Spectrum
| Wave Type | Frequency Range | Wavelength Range | Source | Uses |
|---|---|---|---|---|
| Radio waves | < 10⁹ Hz | > 0.3 m | Oscillating circuits | Radio/TV broadcasting, communication |
| Microwaves | 10⁹ – 10¹¹ Hz | 0.3 m – 1 mm | Klystron, magnetron | Microwave oven, radar, satellite communication |
| Infrared | 10¹¹ – 4×10¹⁴ Hz | 1 mm – 700 nm | Hot bodies | Night vision, remote controls, greenhouse effect |
| Visible light | 4×10¹⁴ – 8×10¹⁴ Hz | 700 – 400 nm | Sun, lamps | Vision, photosynthesis |
| Ultraviolet | 8×10¹⁴ – 10¹⁶ Hz | 400 – 1 nm | Sun, mercury lamp | Sterilisation, LASIK, vitamin D production |
| X-rays | 10¹⁶ – 10¹⁹ Hz | 1 nm – 10⁻³ nm | X-ray tube (bombarding metal with electrons) | Medical imaging, security screening |
| Gamma rays | > 10¹⁹ Hz | < 10⁻³ nm | Radioactive decay, nuclear reactions | Cancer treatment, sterilisation |
Order of increasing frequency: Radio < Microwave < IR < Visible < UV < X-ray < Gamma
Order of increasing wavelength: Gamma < X-ray < UV < Visible < IR < Microwave < Radio
Solved Examples
Example 1
An EM wave has frequency 5 × 10¹⁴ Hz. Find its wavelength and identify the type.
Answer: λ = c/f = (3 × 10⁸)/(5 × 10¹⁴) = 6 × 10⁻⁷ m = 600 nm. This is visible light (orange-red).
Example 2
The electric field in an EM wave has amplitude 100 V/m. Find the amplitude of the magnetic field.
Answer: B₀ = E₀/c = 100/(3 × 10⁸) = 3.33 × 10⁻⁷ T
Important Questions for Board Exams
1-Mark
- What is displacement current?
- Which EM wave is used in RADAR?
3-Mark
- List the electromagnetic spectrum in order of increasing frequency. Give one use of each type.
- State the properties of electromagnetic waves.
5-Mark
- Describe the electromagnetic spectrum in detail. Give the source, frequency range, and applications for each type of EM wave.
Quick Revision Points
- EM waves: E ⊥ B ⊥ direction of propagation; travel at c = 3 × 10⁸ m/s in vacuum
- c = 1/√(μ₀ε₀) = E₀/B₀ = fλ
- Displacement current Id = ε₀(dΦE/dt) — completes Ampere’s law
- Spectrum (↑ frequency): Radio → Microwave → IR → Visible → UV → X-ray → Gamma
- Radio: broadcasting; Microwave: radar, ovens; IR: night vision; UV: sterilisation; X-ray: imaging; Gamma: cancer treatment
Previous: Ch 7 — Alternating Current
Next: Ch 9 — Ray Optics
Chapter Navigation
Previous: Alternating Current Class 12 Notes
Next: Ray Optics and Optical Instruments Class 12 Notes
Related Chapters in Class 12 Physics
- Alternating Current Class 12 Notes
- Ray Optics and Optical Instruments Class 12 Notes
- Wave Optics Class 12 Notes
Practice What You Learned
Test yourself with our JEE Main Mock Test Set 1 to see how well you’ve mastered the concepts.