Electromagnetic Waves Class 12 Notes | CBSE Physics Chapter 8

Chapter summary

Electromagnetic Waves shows how Maxwell completed the laws of electricity and magnetism by adding the displacement current, leading to the prediction that changing electric and magnetic fields sustain each other and travel as a wave at the speed of light even through vacuum. The chapter covers the transverse nature of EM waves, the speed relation c equals 1 over the square root of mu-naught times epsilon-naught, their energy, momentum and radiation pressure, and the full electromagnetic spectrum with the sources and uses of each band. It is a short, high-yield NEET chapter where most questions are direct recall of the spectrum order, key formulas and characteristic uses.

Chapter notes

Key Concepts

1. Displacement Current and Maxwell’s Equations

Maxwell showed that a changing electric field produces a magnetic field, just as a changing magnetic field produces an electric field (Faraday’s law). He introduced the concept of displacement current:

Id = ε₀(dΦE/dt)

This completed Ampere’s law: ∮B·dl = μ₀(Ic + Id), making the equations symmetric.

2. Properties of EM Waves

  • Produced by accelerating charges
  • Do not need a medium - travel through vacuum at speed c = 3 × 10⁸ m/s
  • E and B fields are perpendicular to each other and to the direction of propagation (transverse waves)
  • c = 1/√(μ₀ε₀) = E₀/B₀
  • Carry energy and momentum
  • Follow c = fλ

3. Electromagnetic Spectrum

Wave TypeFrequency RangeWavelength RangeSourceUses
Radio waves< 10⁹ Hz> 0.3 mOscillating circuitsRadio/TV broadcasting, communication
Microwaves10⁹ – 10¹¹ Hz0.3 m – 1 mmKlystron, magnetronMicrowave oven, radar, satellite communication
Infrared10¹¹ – 4×10¹⁴ Hz1 mm – 700 nmHot bodiesNight vision, remote controls, greenhouse effect
Visible light4×10¹⁴ – 8×10¹⁴ Hz700 – 400 nmSun, lampsVision, photosynthesis
Ultraviolet8×10¹⁴ – 10¹⁶ Hz400 – 1 nmSun, mercury lampSterilisation, LASIK, vitamin D production
X-rays10¹⁶ – 10¹⁹ Hz1 nm – 10⁻³ nmX-ray tube (bombarding metal with electrons)Medical imaging, security screening
Gamma rays> 10¹⁹ Hz< 10⁻³ nmRadioactive decay, nuclear reactionsCancer treatment, sterilisation

Order of increasing frequency: Radio < Microwave < IR < Visible < UV < X-ray < Gamma

Order of increasing wavelength: Gamma < X-ray < UV < Visible < IR < Microwave < Radio


Solved Examples

Example 1

An EM wave has frequency 5 × 10¹⁴ Hz. Find its wavelength and identify the type.

Answer: λ = c/f = (3 × 10⁸)/(5 × 10¹⁴) = 6 × 10⁻⁷ m = 600 nm. This is visible light (orange-red).

Example 2

The electric field in an EM wave has amplitude 100 V/m. Find the amplitude of the magnetic field.

Answer: B₀ = E₀/c = 100/(3 × 10⁸) = 3.33 × 10⁻⁷ T


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Important Questions for Board Exams

1-Mark

  1. What is displacement current?
  2. Which EM wave is used in RADAR?

3-Mark

  1. List the electromagnetic spectrum in order of increasing frequency. Give one use of each type.
  2. State the properties of electromagnetic waves.

5-Mark

  1. Describe the electromagnetic spectrum in detail. Give the source, frequency range, and applications for each type of EM wave.

Quick Revision Points

  • EM waves: E ⊥ B ⊥ direction of propagation; travel at c = 3 × 10⁸ m/s in vacuum
  • c = 1/√(μ₀ε₀) = E₀/B₀ = fλ
  • Displacement current Id = ε₀(dΦE/dt) - completes Ampere’s law
  • Spectrum (↑ frequency): Radio → Microwave → IR → Visible → UV → X-ray → Gamma
  • Radio: broadcasting; Microwave: radar, ovens; IR: night vision; UV: sterilisation; X-ray: imaging; Gamma: cancer treatment

Previous: Ch 7 - Alternating Current
Next: Ch 9 - Ray Optics

🃏 Flash Cards: Electromagnetic Waves

Class 12 Physics · Chapter 8 – swipe through all 10 cards to understand the whole chapter.

🧭Start here1/10

The Big Picture

A changing electric field makes a magnetic field and a changing magnetic field makes an electric field, so they sustain each other and travel as a wave even through vacuum.

changing E ⇄ changing B → self-sustaining EM wave

No medium needed; this is why sunlight crosses empty space.

  • Maxwell unified electricity, magnetism and light
  • EM waves carry energy and momentum but no charge
  • Produced only by accelerating (e.g. oscillating) charges
🔌Maxwell’s fix2/10

Displacement Current

Ampere’s law failed for a charging capacitor, so Maxwell added a current due to a changing electric field between the plates.

I_d = ε0 (dΦ_E / dt)

No charge crosses the gap; it is a time-varying electric flux Φ_E.

  • In a capacitor, I_d between plates = conduction current I_c in wire
  • Exists wherever E changes with time, not only in capacitors
  • Makes B continuous across the plate gap
⚖️Core law3/10

Ampere–Maxwell Law

The corrected circuital law adds the displacement-current term to the real conduction current.

∮ B·dl = μ0 ( I_c + ε0 dΦ_E/dt )

The added term is what predicts electromagnetic waves.

  • Symmetric with Faraday: changing E makes B, changing B makes E
  • Same B whether the loop sits in the wire or the gap
  • Whole set of Maxwell’s equations now self-consistent
〰️Key feature4/10

Nature of EM Waves

EM waves are transverse: E and B are perpendicular to each other and to the direction of travel, oscillating in phase.

E_y = E0 sin(kx − ωt), B_z = B0 sin(kx − ωt)

E and B peak together and vanish together (in phase).

  • Wave travels along E × B (right-handed set)
  • Not deflected by electric or magnetic fields (no charge)
  • Energy shared equally between E and B fields
💡Core constant5/10

Speed of EM Waves

In vacuum the speed depends only on two properties of free space and equals the speed of light.

c = 1 / √(μ0ε0) ≈ 3 × 108 m s⁻1

In a medium v = c / n < c; never write c = √(μ0ε0).

  • All EM waves travel at c in vacuum
  • In glass the wave slows to c/n: λ shrinks, f stays fixed
  • Light is just one kind of EM wave
🔗Field link6/10

E0 and B0 Locked Together

At every instant the electric field strength is c times the magnetic field strength.

E0 / B0 = c (so E = cB at every instant)

This is why E (V m⁻1) is numerically far larger than B (T).

  • The factor between them is c ≈ 3 × 108
  • E and B amplitudes rise and fall together
  • Use it to convert between the two amplitudes
🔋Energy7/10

Energy Density

Both fields store energy, and on average each carries exactly half the total.

u_E = ½ ε0 E2, u_B = B2 / (2μ0), u_E = u_B

For averages use rms values: E_rms = E0 / √2.

  • Energy split 50-50 between E and B
  • Intensity I = ½ ε0 E02 c (energy per area per second)
  • The ½ in average formulas comes from using rms fields
☀️Momentum8/10

Radiation Pressure

EM waves carry momentum, so absorbing or reflecting light delivers a tiny push.

p = U / c (absorbed); p = 2U / c (fully reflected)

Reflection doubles the momentum transfer and pressure vs absorption.

  • Force on absorber F = P/c (P = power)
  • Perfect reflector feels twice the force, F = 2P/c
  • This is how solar sails work
🌈Key fact9/10

The EM Spectrum

All EM waves are the same phenomenon; they differ only in frequency and wavelength.

Radio < Micro < IR < Visible < UV < X-ray < Gamma (↑ frequency)

VIBGYOR: Violet highest f, Red lowest f within visible light.

  • c = fλ, so higher f ⇒ shorter λ ⇒ more energetic photons (E = hf)
  • Ozone absorbs UV; IR is the ‘heat wave’
  • X-rays: fast electrons on metal; Gamma: nuclei / radioactive decay
📡Sources & uses10/10

Spectrum at a Glance

Each band has a characteristic source and everyday use worth memorising for NEET.

λ = c / f (e.g. 5 × 1014 Hz → 600 nm, visible)

Visible light spans roughly 400–700 nm.

  • Radio: antennas/circuits → TV, mobile; Microwave: magnetron → radar, ovens
  • IR: hot bodies → remotes, thermography; UV: Sun → sterilisation, sunburn
  • X-ray: medical imaging; Gamma: cancer therapy
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📝 Practice Electromagnetic Waves — 10 NEET PYQs
Real previous-year questions · with answers & solutions
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Q1NEET 2021
A capacitor of capacitance C is connected across an AC source of voltage V = V₀sinω t. The displacement current between the plates of the capacitor is:
Correct answer: A. Charge on the plate Q = CV = CV₀sinω t. The displacement current equals the conduction current, I_d = (dQ)/(dt) = CV₀ ωcosω t = V₀ ω Ccosω t.
🔎 See the full step-by-step solution in the app →
Q2NEET 2021
For a plane electromagnetic wave propagating in the +x-direction, which combination gives a correct possible pair of directions for the electric field vec E and magnetic field vec B respectively?
Correct answer: B. For an EM wave vec E and vec B must be perpendicular (vec E·vec B = 0) and vec E×vec B must point along propagation (+x). For (B): (-hat j+hat k)·(-hat j-hat k) = 1-1 = 0 (perpendicular), and (-hat j+hat k)×(-hat j-hat k) = 2hat i (along +x). Both conditions hold.
🔎 See the full step-by-step solution in the app →
Q3NEET 2020
The ratio of the contributions made by the electric field and the magnetic field components to the intensity of an electromagnetic wave is (c = speed of light):
Correct answer: A. In an EM wave the energy is shared equally between the electric and magnetic fields (u_E = u_B on average, since (1)/(2)ε₀ E₀² = (B₀²)/(2μ₀)). Hence each contributes equally to the intensity, ratio 1 : 1.
🔎 See the full step-by-step solution in the app →
Q4NEET 2020
The electromagnetic wave with the shortest wavelength among the following is:
Correct answer: C. Wavelength decreases (frequency increases) in the order: microwaves > UV-rays > X-rays > γ-rays. Gamma rays have the highest frequency and hence the shortest wavelength.
🔎 See the full step-by-step solution in the app →
Q5NEET 2020
The magnetic field in a plane electromagnetic wave is given by B_y = 2×10⁻⁷sin(π×10³x + 3π×10¹¹t) T. The wavelength of the wave is:
Correct answer: B. Comparing with B_y = B₀sin(kx – ω t), the wave number k = π×10³ m⁻¹. Since k = (2π)/(λ), λ = (2π)/(k) = (2π)/(π×10³) = 2×10⁻³ m.
🔎 See the full step-by-step solution in the app →
Q6NEET 2020
Light with an average flux of 20 W/cm² falls on a non-reflecting surface at normal incidence having surface area 20 cm². The energy received by the surface during a time span of 1 minute is:
Correct answer: B. Energy = flux × area × time = 20 W/cm² × 20 cm² × 60 s = 24000 = 24×10³ J (the surface is non-reflecting, so it absorbs all the incident energy).
🔎 See the full step-by-step solution in the app →
Q7NEET 2019
A parallel plate capacitor of capacitance 20 μF is being charged by a voltage source whose potential is changing at the rate of 3 V/s. The conduction current through the connecting wires and the displacement current through the plates are respectively:
Correct answer: A. Displacement current I_d = C(dV)/(dt) = 20×10⁻⁶×3 = 60×10⁻⁶ A = 60 μA. The conduction current in the wires equals the displacement current between the plates, so both are 60 μA.
🔎 See the full step-by-step solution in the app →
Q8NEET 2018
An EM wave is propagating in a medium with velocity vec v = v hat i. The instantaneous oscillating electric field of this wave is along the +y-axis. Then the direction of the oscillating magnetic field of the wave is along:
Correct answer: B. Propagation is along vec E×vec B. With vec v along +hat i and vec E along +hat j, we need hat j×hat B = hat i. Since hat j×hat k = hat i, vec B must be along +hat k, i.e. the +z-direction.
🔎 See the full step-by-step solution in the app →
Q9NEET 2015
The energy of an electromagnetic wave is of the order of 15 keV. To which part of the spectrum does it belong? (Take h = 6.6×10⁻³⁴ J·s)
Correct answer: A. E = 15 keV = 15×10³×1.6×10⁻¹⁹ J. λ = (hc)/(E) = (6.6×10⁻³⁴×3×10⁸)/(2.4×10⁻¹⁵) ≈ 0.83×10⁻¹⁰ m = 0.83 Å. Wavelengths of order 0.1 to 100 Å lie in the X-ray region.
🔎 See the full step-by-step solution in the app →
Q10NEET 2015
A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (c = velocity of light):
Correct answer: B. Incident momentum = (E)/(c). On perfect reflection the radiation reverses direction, so the reflected momentum is -(E)/(c). The change in the radiation’s momentum is (2E)/(c), which is the momentum transferred to the surface.
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Frequently Asked Questions

What is displacement current and why did Maxwell introduce it?

Displacement current is the current associated with a changing electric field, given by I_d equals epsilon-naught times the rate of change of electric flux. Maxwell added it because Ampere’s law gave no magnetic field between the plates of a charging capacitor, where no conduction current flows, even though a magnetic field clearly exists there.

What is the speed of an electromagnetic wave and which formula gives it?

In vacuum every EM wave travels at the speed of light, c equals 1 over the square root of mu-naught times epsilon-naught, which is about 3 times 10 to the power 8 metres per second. In a medium the speed drops to v equals c divided by the refractive index n, so it is always less than c.

How are the electric and magnetic field amplitudes of an EM wave related?

At every instant the electric field is c times the magnetic field, so E-naught divided by B-naught equals c and E equals cB. The E and B fields are perpendicular to each other and to the direction of travel, and they oscillate in phase, peaking and vanishing together.

What is the correct increasing-frequency order of the electromagnetic spectrum for NEET?

In order of increasing frequency and decreasing wavelength it is radio waves, microwaves, infrared, visible light, ultraviolet, X-rays and gamma rays. Useful tags to remember are infrared as heat waves, ozone absorbing UV, X-rays from fast electrons hitting metal and gamma rays from nuclei.

What is the difference between the radiation pressure of an absorbing and a reflecting surface?

An EM wave carries momentum p equals U divided by c for energy U, so a fully absorbing surface receives momentum U over c, but a perfectly reflecting surface receives twice that, 2U over c, because the wave reverses direction. This is why a perfect reflector feels double the force and pressure compared with a perfect absorber.

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