Respiration in Plants Class 11 Notes | CBSE Biology Chapter 12

Chapter summary

Respiration in Plants explains how cells break down food, usually glucose, in controlled enzyme-driven steps to trap energy as ATP. It walks through glycolysis, fermentation, pyruvate oxidation, the Krebs cycle, and the electron transport system, plus the respiratory quotient and the amphibolic nature of the pathway. It is a high-yield NEET chapter because the ATP budget, RQ values, and stepwise comparisons are repeatedly tested.

Chapter notes

Table of Contents


Key Concepts

1. Cellular Respiration - The Basics

Cellular respiration is the enzyme-controlled, step-wise oxidation of food (mainly glucose) inside the cell to release energy stored in C–C bonds, trapping it as ATP. Unlike burning, it happens in many small steps so energy is released gradually and safely.

The substrate that is oxidised is called the respiratory substrate - usually carbohydrates, but fats and proteins can also be used. The molecule that supplies energy on demand is ATP (adenosine triphosphate), often called the “energy currency” of the cell.

Overall Equation (aerobic)

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + Energy (ATP + heat)


2. Glycolysis (EMP Pathway)

Glycolysis (“splitting of sugar”) is the breakdown of one glucose molecule into two molecules of pyruvic acid. It was given by Embden, Meyerhof and Parnas, so it is called the EMP pathway.

  • Site: cytoplasm (cytosol) - does NOT need oxygen.
  • It is common to both aerobic and anaerobic respiration.
  • Net products per glucose: 2 pyruvate + 2 ATP (net) + 2 NADH + 2H⁺.

[DIAGRAM: Glucose → glucose-6-phosphate → fructose-1,6-bisphosphate → splits into 2 triose phosphate (PGAL) → 2 pyruvic acid; 2 ATP used in the investment phase, 4 ATP made in the payoff phase, net 2 ATP.]

Key idea: 2 ATP are spent early (priming) and 4 ATP are produced later, giving a net gain of 2 ATP per glucose.


3. Fate of Pyruvate

The fate of pyruvic acid depends on whether oxygen is available and on the type of cell.

  • Aerobic respiration: pyruvate enters the mitochondrion and is completely oxidised to CO₂ and H₂O.
  • Fermentation (anaerobic): pyruvate is incompletely broken down in the cytoplasm without oxygen.

4. Fermentation (Anaerobic Respiration)

Fermentation is the incomplete oxidation of glucose under anaerobic conditions. Only the 2 ATP of glycolysis are gained - most energy stays locked in the products.

Two Common Types

  • Alcoholic fermentation: pyruvate → ethanol + CO₂ (by yeast). Enzymes: pyruvate decarboxylase and alcohol dehydrogenase.
  • Lactic acid fermentation: pyruvate → lactic acid (in some bacteria and in our muscles during heavy exercise). Enzyme: lactate dehydrogenase.

Important: In both, NADH is reoxidised to NAD⁺ so glycolysis can continue. Fermentation yields less than 7% of the energy of glucose and can be dangerous (alcohol/acid accumulation).


5. Aerobic Respiration - Overview

Aerobic respiration is the complete oxidation of pyruvate to CO₂ and H₂O in the presence of oxygen, occurring in the mitochondria. It has two major steps after glycolysis: the Krebs cycle and the electron transport system.

First, pyruvate is converted in the mitochondrial matrix by pyruvate dehydrogenase:

Pyruvic acid + CoA + NAD⁺ → Acetyl CoA + CO₂ + NADH + H⁺


6. Krebs Cycle (TCA / Citric Acid Cycle)

The Krebs cycle, also called the tricarboxylic acid (TCA) cycle or citric acid cycle, was discovered by Hans Krebs. It is the complete oxidation of acetyl CoA.

  • Site: mitochondrial matrix.
  • Acetyl CoA (2C) combines with oxaloacetic acid (4C) to form citric acid (6C).
  • The cycle regenerates oxaloacetic acid, so it turns continuously.

[DIAGRAM: Acetyl CoA + OAA → citrate → isocitrate → α-ketoglutarate → succinyl CoA → succinate → fumarate → malate → OAA; CO₂ released twice, NADH formed thrice, FADH₂ once, GTP/ATP once.]

Yield per turn (per acetyl CoA)

  • 3 NADH + 1 FADH₂ + 1 GTP (≈ 1 ATP) + 2 CO₂.
  • Since one glucose gives 2 acetyl CoA, the cycle turns twice per glucose.

7. Electron Transport System (ETS) and Oxidative Phosphorylation

The electron transport system is a chain of carriers on the inner mitochondrial membrane that passes electrons from NADH and FADH₂ to oxygen, the final electron acceptor.

  • Electrons flow through Complex I → ubiquinone → Complex III → cytochrome c → Complex IV → O₂.
  • Oxygen accepts electrons and protons to form water (H₂O) - this is why O₂ is vital.

Oxidative phosphorylation is the synthesis of ATP using the energy of this electron flow. As electrons move, protons are pumped into the intermembrane space, creating a gradient. Protons flow back through ATP synthase (F₀–F₁ particle), driving ATP formation - the chemiosmotic hypothesis (Peter Mitchell).

  • 1 NADH → 3 ATP
  • 1 FADH₂ → 2 ATP

8. The Respiratory Balance Sheet (ATP Yield)

Adding up every step gives the total ATP from one glucose under ideal aerobic conditions.

StageATP (direct)NADHFADH₂ATP via ETS
Glycolysis2 (net)2 - 6
Pyruvate → Acetyl CoA (×2) - 2 - 6
Krebs cycle (×2 turns)2 (GTP)6222
Total410234

Net = 4 + 34 = 38 ATP per glucose. In eukaryotic cells, glycolytic NADH must be shuttled into the mitochondrion, costing energy, so the practical yield is often quoted as 36 ATP.

Note: These assumptions are theoretical (one substrate metabolised at a time, perfect functioning). Real values vary, so always state the assumptions in answers.


9. Amphibolic Pathway

The respiratory pathway is described as amphibolic because it works in both directions - it is catabolic (breaking molecules down) and anabolic (building molecules up).

  • Intermediates like acetyl CoA and α-ketoglutarate are withdrawn to synthesise fatty acids and amino acids.
  • Fats are broken into glycerol and fatty acids; proteins into amino acids - these feed into respiration at various points.

Key idea: Because the pathway both breaks down and builds up substrates, it is amphibolic, not purely catabolic.


10. Respiratory Quotient (RQ)

The respiratory quotient (RQ) is the ratio of the volume of CO₂ evolved to the volume of O₂ consumed during respiration.

RQ = Volume of CO₂ released / Volume of O₂ consumed

Respiratory SubstrateRQ Value
Carbohydrates1 (e.g. glucose)
FatsLess than 1 (≈ 0.7)
ProteinsAbout 0.9
Organic acidsMore than 1

Note: In anaerobic respiration of carbohydrates (no O₂ consumed), RQ is infinite (∞).


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Weightage in Board & Entrance Exams

ExamTypical WeightageMost-Tested Areas
CBSE Board (Class 11)5–6 marksGlycolysis steps, Krebs cycle, ATP balance sheet, RQ
NEET / AIIMS1–2 questionsATP yield, ETS, fermentation, RQ of substrates
State CETs1–2 questionsSite of each step, net products, amphibolic pathway

[TABLE: Question-type split - VSA (1 mark): definitions, sites, RQ values; SA (2–3 marks): glycolysis vs fermentation, ETS, amphibolic pathway; LA (5 marks): full aerobic respiration with the ATP balance sheet.]


Important Definitions

TermDefinition
Cellular respirationStep-wise enzymatic oxidation of food to release energy as ATP
Respiratory substrateThe molecule oxidised in respiration (carbohydrate, fat or protein)
Glycolysis (EMP)Breakdown of glucose to 2 pyruvate in the cytoplasm; net 2 ATP + 2 NADH
FermentationIncomplete anaerobic oxidation of glucose to ethanol or lactic acid
Krebs cycle (TCA)Complete oxidation of acetyl CoA in the mitochondrial matrix
Electron transport systemChain on inner mitochondrial membrane passing electrons to O₂
Oxidative phosphorylationATP synthesis driven by the proton gradient (chemiosmosis)
Amphibolic pathwayA pathway involved in both breakdown (catabolism) and synthesis (anabolism)
Respiratory quotient (RQ)Ratio of CO₂ released to O₂ consumed during respiration
ATP synthaseF₀–F₁ enzyme that makes ATP as protons flow back across the membrane

Solved Examples

Example 1

How many ATP molecules are gained (net) during glycolysis of one glucose molecule, and where does it occur?

Answer: 2 ATP are used and 4 are produced, so the net gain is 2 ATP. It occurs in the cytoplasm and needs no oxygen.

Example 2

Calculate the total ATP produced via the ETS from the NADH and FADH₂ of one Krebs cycle turn.

Answer: One turn gives 3 NADH and 1 FADH₂. ATP = (3 × 3) + (1 × 2) = 9 + 2 = 11 ATP via ETS (plus 1 GTP directly).

Example 3

Write the equation for alcoholic fermentation and name the enzymes involved.

Answer: Pyruvic acid → CO₂ + Ethanol. Enzymes: pyruvate decarboxylase (removes CO₂) and alcohol dehydrogenase (forms ethanol).

Example 4

A germinating seed rich in fats is used in an experiment. What will be its RQ, and why?

Answer: RQ will be less than 1 (≈ 0.7) because fats need more O₂ for complete oxidation than the CO₂ they release.

Example 5

Why is the total theoretical ATP yield often quoted as 36 instead of 38 in eukaryotes?

Answer: The 2 NADH made in glycolysis (cytoplasm) must be shuttled into the mitochondrion. This transport costs energy, reducing the net yield from 38 to about 36 ATP.

Example 6

Name the final electron acceptor in the ETS and the product formed.

Answer: The final electron acceptor is oxygen (O₂); it combines with electrons and protons to form water (H₂O).


Important Questions for Board Exams

1-Mark Questions (VSA)

  1. Where in the cell does glycolysis take place?
  2. What is the RQ of a carbohydrate respiratory substrate?
  3. Name the common metabolite at which glycolysis ends.
  4. Which enzyme synthesises ATP during oxidative phosphorylation?
  5. Name the final hydrogen/electron acceptor in aerobic respiration.

2–3-Mark Questions (SA)

  1. Differentiate between aerobic respiration and fermentation with respect to site, oxygen and ATP yield.
  2. Explain why the respiratory pathway is called an amphibolic pathway.
  3. Describe the role of the electron transport system in ATP synthesis.
  4. What is the respiratory quotient? Give RQ values for carbohydrates, fats and organic acids.

5-Mark Questions (LA)

  1. Describe the Krebs cycle and state its net products per turn.
  2. Prepare the respiratory balance sheet showing how 38 ATP are produced from one glucose molecule. State the assumptions made.
  3. Explain the chemiosmotic hypothesis of ATP synthesis in mitochondria.

Quick Revision Points

  • Glycolysis: glucose → 2 pyruvate in cytoplasm; net 2 ATP + 2 NADH; no O₂ needed
  • Fermentation: anaerobic; ethanol + CO₂ (yeast) or lactic acid (muscle); only 2 ATP
  • Link reaction: pyruvate → acetyl CoA + CO₂ + NADH (matrix)
  • Krebs cycle: complete oxidation of acetyl CoA in matrix; 3 NADH + 1 FADH₂ + 1 GTP + 2 CO₂ per turn
  • ETS: on inner mitochondrial membrane; O₂ is the final electron acceptor → forms water
  • 1 NADH = 3 ATP; 1 FADH₂ = 2 ATP (oxidative phosphorylation)
  • Balance sheet: 38 ATP total (36 ATP in eukaryotes due to NADH shuttle)
  • ATP synthase (F₀–F₁) makes ATP via the proton gradient - chemiosmotic hypothesis
  • Amphibolic pathway: respiration is both catabolic and anabolic
  • RQ = CO₂ released / O₂ consumed; carbohydrate = 1, fat < 1, protein ≈ 0.9, organic acid > 1

Next Chapter: Chapter 13 - Plant Growth and Development

🃏 Flash Cards: Respiration in Plants

Class 11 Biology · Botany – swipe through all 8 cards to understand the whole chapter.

🔥Start here1/8

What Respiration Is

Respiration breaks C-C bonds of food stepwise to trap energy as ATP.

C6H12O6 + 6O2 → 6CO2 + 6H2O + energy

Energy released gradually over many enzyme steps, not one burst.

  • Molecule broken = respiratory substrate (usually glucose)
  • Energy currency produced = ATP
  • Plants have no respiratory organs; each cell exchanges gas by diffusion
📊Key ratio2/8

Respiratory Quotient (RQ)

RQ tells which substrate a cell is burning.

RQ = CO2 released / O2 used

CO2 is on top — not O2/CO2.

  • Carbohydrates RQ = 1; Proteins ≈ 0.9
  • Fats RQ ≈ 0.7 (H-rich, need extra O2)
  • Organic acids RQ > 1 (malic acid ≈ 1.33)
🍬First step3/8

Glycolysis (EMP Pathway)

Glucose (6C) is partially oxidised to two pyruvate (3C) in the cytoplasm, no O2 needed.

Glucose + 2NAD⁺ + 2ADP + 2Pi → 2 Pyruvate + 2NADH + 2ATP

Named after Embden, Meyerhof, Parnas; happens in ALL living cells.

  • 2 ATP invested, 4 ATP made → net gain 2 ATP
  • ATP made by substrate-level phosphorylation
  • In plants, invertase splits sucrose → glucose + fructose first
🍺No oxygen4/8

Fermentation

Without O2, electrons go to pyruvate to regenerate NAD⁺ so glycolysis continues.

Pyruvate → Ethanol + CO2 (alcoholic) · Pyruvate → Lactic acid (lactic)

Alcoholic enzymes: pyruvate decarboxylase + alcohol dehydrogenase.

  • Net yield only 2 ATP/glucose (all from glycolysis)
  • Releases < 7% of glucose energy; rest locked in product
  • Lactic acid fermentation releases NO CO2; yeast dies above ~13% alcohol
🔗Link step5/8

Pyruvate Oxidation (Link Reaction)

In the mitochondrial matrix, pyruvate is decarboxylated to acetyl CoA.

Pyruvate + CoA + NAD⁺ → Acetyl CoA + CO2 + NADH

Catalysed by pyruvate dehydrogenase; needs Mg2⁺.

  • Acetyl CoA is 2C; one CO2 released per pyruvate
  • 1 NADH made per pyruvate (2 per glucose)
  • Connects glycolysis to the Krebs cycle
🔄Core cycle6/8

Krebs Cycle (TCA)

Acetyl CoA joins OAA to form citrate; the cycle fully oxidises it in the matrix.

Acetyl CoA (2C) + OAA (4C) → Citrate (6C) [citrate synthase]

OAA is regenerated, so it acts catalytically.

  • Per acetyl CoA: 3 NADH, 1 FADH2, 1 GTP, 2 CO2
  • Double all values per glucose (2 acetyl CoA)
  • Exhaled CO2 comes from link reaction + Krebs, NOT the ETS
ATP factory7/8

ETS & Oxidative Phosphorylation

NADH and FADH2 are oxidised on the inner membrane to make the bulk of ATP.

NADH → 3 ATP · FADH2 → 2 ATP

O2 is the terminal electron acceptor → forms water.

  • Path: NADH→Complex I→Q→III→cyt c→IV→O2 (FADH2 enters at II)
  • Protons return through ATP synthase (Complex V) = chemiosmosis (Peter Mitchell)
  • FADH2 gives only 2 ATP as it skips the first proton pump
🧮Final tally8/8

ATP Budget & Amphibolic Pathway

Aerobic oxidation of one glucose gives a theoretical maximum of 38 ATP (NCERT).

2 + 6 + 6 + 18 + 4 + 2 = 38 ATP

Real yield is lower as intermediates are siphoned for biosynthesis.

  • Glycolysis 2 ATP + 2 NADH; link 2 NADH; Krebs 6 NADH + 2 FADH2 + 2 GTP
  • Amphibolic: intermediates (acetyl CoA, OAA, α-ketoglutarate) build fats & amino acids
  • Aerobic ~38 ATP vs fermentation only 2 ATP per glucose
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📝 Practice Respiration in Plants — 10 NEET PYQs
Real previous-year questions · with answers & solutions
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Q1NEET 2021
Which one of the following statements about aerobic respiration is INCORRECT? (NEET 2021)
Correct answer: B. The yields are reversed in option B: one NADH gives 3 ATP and one FADH2 gives 2 ATP (FADH2 enters at Complex II, skipping the first proton pump), so B is the incorrect statement. Oxygen does act only at the terminal stage (A correct), ATP synthase is Complex V (C correct), and redox reactions do build the proton gradient (D correct).
🔎 See the full step-by-step solution in the app →
Q2NEET 2020
Pyruvate dehydrogenase activity during aerobic respiration requires which metal ion as a cofactor?
Correct answer: D. The pyruvate dehydrogenase complex, which oxidatively decarboxylates pyruvate to acetyl CoA, needs Mg2+ as a cofactor (along with coenzymes such as TPP, lipoic acid and NAD+). Calcium, iron and cobalt are not the required cofactor for this step.
🔎 See the full step-by-step solution in the app →
Q3NEET 2020
The number of substrate-level phosphorylation events in one turn of the citric acid (Krebs) cycle is:
Correct answer: A. In one turn of the Krebs cycle there is exactly one substrate-level phosphorylation, at the succinyl-CoA to succinate step, which makes one GTP (or ATP). The other energy is captured as NADH and FADH2, not by substrate-level phosphorylation.
🔎 See the full step-by-step solution in the app →
Q4NEET 2019
The Respiratory Quotient (RQ) value of tripalmitin (a fat) is approximately:
Correct answer: A. For the fat tripalmitin the balanced equation 2 C51H98O6 + 145 O2 -> 102 CO2 + 98 H2O gives RQ = 102/145 = approximately 0.7. Fats are H-rich and O-poor, so they consume more O2 than the CO2 they release, making RQ less than 1.
🔎 See the full step-by-step solution in the app →
Q5NEET 2019
The conversion of glucose to glucose-6-phosphate, the first irreversible reaction of glycolysis, is catalysed by:
Correct answer: A. The very first step of glycolysis phosphorylates glucose to glucose-6-phosphate using ATP, catalysed by hexokinase. Phosphofructokinase acts later (fructose-6-P to fructose-1,6-bisphosphate), enolase converts 2-phosphoglycerate to PEP, and aldolase splits fructose-1,6-bisphosphate; none catalyses the first step.
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Q6NEET 2014
In which one of the following processes is CO2 NOT released?
Correct answer: D. Lactic acid fermentation reduces pyruvate directly to lactate with no decarboxylation, so no CO2 is released. Aerobic respiration releases CO2 in the link reaction and Krebs cycle, and alcoholic fermentation releases CO2 when pyruvate is decarboxylated to acetaldehyde.
🔎 See the full step-by-step solution in the app →
Q7NEET 2013
Which one of the following metabolites is common to the respiration-mediated breakdown of fats, carbohydrates and proteins?
Correct answer: D. Carbohydrates, fats and proteins are all eventually converted to acetyl CoA, which then enters the Krebs cycle; acetyl CoA is therefore the common entry metabolite. Glucose-6-phosphate, fructose-1,6-bisphosphate and pyruvic acid are intermediates only of carbohydrate breakdown.
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Q8NEET 2010
The energy-releasing metabolic process in which a substrate is oxidised without an external electron acceptor is called:
Correct answer: B. Fermentation oxidises the substrate without any external electron acceptor such as oxygen; instead pyruvate (or its derivative) accepts the electrons, regenerating NAD+. Aerobic respiration uses oxygen as the external acceptor, and glycolysis is only the first common step.
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Q9NEET 2007
The overall goal of glycolysis, the Krebs cycle and the electron transport system together is the formation of:
Correct answer: A. All three stages exist to trap the energy of glucose as ATP, the cell’s energy currency, releasing it gradually in many small enzyme-controlled steps rather than one explosive burst, so the energy can be captured efficiently.
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Q10NEET 1995
The Respiratory Quotient (RQ) for a fatty acid being respired is:
Correct answer: B. Fats (fatty acids) are rich in hydrogen and poor in oxygen, so a large amount of O2 must be consumed to oxidise them while comparatively less CO2 is released. RQ = CO2/O2 therefore falls below 1 (typically ~0.7).
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Frequently Asked Questions

What is respiration in plants?

Respiration is the controlled, stepwise breaking of carbon-carbon bonds in food molecules, usually glucose, by enzymes to release energy that is trapped as ATP. Plants have no special respiratory organs, so every cell exchanges gases directly by diffusion.

What is the respiratory quotient (RQ) and what are its values?

RQ is the ratio of carbon dioxide released to oxygen consumed during respiration, written as CO2 released divided by O2 used. It is 1 for carbohydrates, about 0.9 for proteins, about 0.7 for fats, and greater than 1 for organic acids such as malic acid.

How much ATP is produced from one glucose molecule in aerobic respiration?

NCERT gives a theoretical maximum of 38 ATP per glucose under aerobic conditions. The actual yield is lower because intermediates are siphoned off for biosynthesis, whereas fermentation gives only 2 ATP per glucose.

Is Respiration in Plants important for NEET?

Yes, it is part of the NEET Biology syllabus and a frequently tested chapter. Questions commonly target the ATP budget, RQ values, the site of each stage, and the products of glycolysis, the Krebs cycle, and the ETS.

What is the difference between glycolysis and fermentation?

Glycolysis is the universal first step that partially oxidises glucose to two pyruvate molecules in the cytoplasm, giving a net 2 ATP and 2 NADH without needing oxygen. Fermentation is what follows in the absence of oxygen, converting pyruvate to ethanol and carbon dioxide or to lactic acid to regenerate NAD+, with no extra ATP gained beyond glycolysis.

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