Haloalkanes and Haloarenes Class 12 Notes — CBSE Chemistry Chapter 10

Chapter 10 — Haloalkanes and Haloarenes — is the gateway to organic reactions. This chapter introduces substitution and elimination reactions, which form the basis of organic chemistry. It carries 6-8 marks in Board exams. Master the SN1/SN2 mechanisms and named reactions like Wurtz, Fittig, and Sandmeyer.

Key Concepts

Classification

TypeStructureExample
Primary (1°)−CH₂XCH₃CH₂Cl (ethyl chloride)
Secondary (2°)−CHX−(CH₃)₂CHBr (isopropyl bromide)
Tertiary (3°)−CX−(CH₃)₃CCl (tert-butyl chloride)
HaloareneX on benzene ringC₆H₅Cl (chlorobenzene)

Preparation Methods

1. From Alcohols:
R−OH + HX → R−X + H₂O (reactivity: HI > HBr > HCl)
R−OH + PCl₅ → R−Cl + POCl₃ + HCl
3R−OH + PCl₃ → 3R−Cl + H₃PO₃
R−OH + SOCl₂ → R−Cl + SO₂↑ + HCl↑ (best method — byproducts are gases!)

2. From Alkenes (Markovnikov’s addition):
CH₂=CH₂ + HBr → CH₃CH₂Br

3. Halogenation of Alkanes (free radical):
CH₄ + Cl₂ →(UV/hv) CH₃Cl + HCl

4. Sandmeyer Reaction (for ArX):
ArN₂⁺Cl⁻ + CuCl/HCl → ArCl + N₂
ArN₂⁺Cl⁻ + CuBr/HBr → ArBr + N₂

Nucleophilic Substitution Reactions

The C−X bond in haloalkanes is polar (C^δ⁺−X^δ⁻), making carbon susceptible to nucleophilic attack.

SN2 Mechanism (Substitution Nucleophilic Bimolecular)

Rate = k[R−X][Nu⁻] (depends on BOTH reactant and nucleophile)
One-step mechanism: nucleophile attacks from the back side (180° to leaving group)
Transition state: pentacoordinate carbon
Result: Walden inversion (configuration inverts — like an umbrella flipping)
Reactivity order: 1° > 2° > 3° (steric hindrance increases)

SN1 Mechanism (Substitution Nucleophilic Unimolecular)

Rate = k[R−X] (depends only on substrate)
Two steps: (1) Ionisation: R−X → R⁺ + X⁻ (slow, rate-determining)
(2) Nucleophilic attack: R⁺ + Nu⁻ → R−Nu (fast)
Carbocation intermediate: planar → nucleophile attacks from both sides
Result: Racemisation (mixture of d and l forms)
Reactivity order: 3° > 2° > 1° (more stable carbocation → faster ionisation)
Quick Summary: SN2 = one step, back-side attack, inversion, favoured by 1° substrates and strong nucleophiles. SN1 = two steps, carbocation, racemisation, favoured by 3° substrates and polar protic solvents.

Elimination Reactions

Dehydrohalogenation (β-elimination):
R−CH₂−CH₂−X + alc. KOH → R−CH=CH₂ + KX + H₂O

Saytzeff’s Rule: The more substituted alkene is the major product
CH₃CH₂CHBrCH₃ + alc. KOH → CH₃CH=CHCH₃ (major, more substituted) + CH₃CH₂CH=CH₂ (minor)

Reactions of Haloalkanes

NucleophileReagentProduct
OH⁻aq. KOH / NaOHAlcohol (R−OH)
OR⁻NaOR (Williamson)Ether (R−O−R’)
CN⁻KCNNitrile (R−CN) — carbon chain increases by 1!
NC⁻AgCNIsocyanide (R−NC)
NH₃excess NH₃Amines (R−NH₂, R₂NH, R₃N, R₄N⁺)
NO₂⁻KNO₂Nitroalkane (R−NO₂) — via N
NO₂⁻AgNO₂Alkyl nitrite (R−O−N=O) — via O
KCN vs AgCN: KCN is ionic → CN⁻ attacks through C → cyanide (R−CN). AgCN is covalent → attacks through N → isocyanide (R−NC). Similarly: KNO₂ → nitro, AgNO₂ → nitrite.

Important Named Reactions

Wurtz Reaction: 2R−X + 2Na →(dry ether) R−R + 2NaX
(Used to increase carbon chain — makes symmetric alkanes)

Fittig Reaction: 2ArX + 2Na → Ar−Ar + 2NaX
Wurtz-Fittig: ArX + RX + 2Na → Ar−R + 2NaX

Finkelstein Reaction: R−Cl + NaI →(acetone) R−I + NaCl↓
(NaCl precipitates in acetone → drives reaction forward)

Swarts Reaction: R−Cl + AgF → R−F + AgCl↓
(Used to prepare fluoroalkanes)

Haloarenes — Why C−X Bond is Less Reactive

Chlorobenzene is much less reactive towards nucleophilic substitution than chloroalkanes because:

  1. Resonance: Lone pair of Cl delocalises into the ring → C−Cl gets partial double bond character → stronger, shorter bond
  2. sp² carbon: The carbon attached to Cl is sp² hybridised → more electronegative → holds electrons tighter
  3. Instability of phenyl cation: C₆H₅⁺ is very unstable → SN1 doesn’t occur easily

Reactions of Haloarenes

  • Electrophilic substitution: Cl is ortho-para directing (due to +M effect) but deactivating (due to −I effect)
  • Dow process: C₆H₅Cl + NaOH →(623 K, 300 atm) C₆H₅OH + NaCl
  • Ullmann reaction: 2C₆H₅Cl + 2Cu →(Δ) C₆H₅−C₆H₅ (biphenyl)

Important Definitions

TermDefinition
Nucleophilic SubstitutionReaction where a nucleophile replaces the leaving group
SN1Unimolecular nucleophilic substitution — rate depends on substrate only
SN2Bimolecular nucleophilic substitution — rate depends on both substrate and nucleophile
Walden InversionInversion of configuration at the chiral centre during SN2
RacemisationFormation of equal amounts of d and l isomers (during SN1)
EliminationLoss of HX from adjacent carbons to form a double bond

Solved Examples — NCERT Based

Example 1: SN1 vs SN2

Q: Predict the mechanism (SN1 or SN2) for: (a) CH₃Br + OH⁻ (b) (CH₃)₃CBr + H₂O

Solution:

(a) CH₃Br is primary → SN2 (strong nucleophile OH⁻, no steric hindrance)

(b) (CH₃)₃CBr is tertiary → SN1 (stable 3° carbocation, weak nucleophile H₂O)

Example 2: Wurtz Reaction

Q: How would you prepare butane from ethyl bromide using Wurtz reaction?

Solution:

2CH₃CH₂Br + 2Na →(dry ether) CH₃CH₂−CH₂CH₃ + 2NaBr

Two ethyl groups couple to form butane (C₄H₁₀).

Example 3: Reactivity Order

Q: Arrange in decreasing order of SN2 reactivity: CH₃Cl, CH₃Br, CH₃I, CH₃F

Solution:

SN2 reactivity depends on the C−X bond strength (weaker bond = better leaving group):

C−I weakest → C−Br → C−Cl → C−F strongest

Order: CH₃I > CH₃Br > CH₃Cl > CH₃F

Example 4: Product Prediction

Q: What happens when chlorobenzene is treated with (a) Na in dry ether (b) NaOH at 623 K, 300 atm?

Solution:

(a) Fittig reaction: 2C₆H₅Cl + 2Na → C₆H₅−C₆H₅ (biphenyl) + 2NaCl

(b) Dow process: C₆H₅Cl + NaOH → C₆H₅OH (phenol) + NaCl

Important Questions for Board Exams

1 Mark Questions

  1. What is Walden inversion?
  2. Which is a better nucleophile: I⁻ or Cl⁻?
  3. Write the product of Finkelstein reaction of CH₃Cl with NaI.
  4. Why is chlorobenzene less reactive towards nucleophilic substitution?

2 Mark Questions

  1. Distinguish between SN1 and SN2 mechanisms (any 4 points).
  2. What is Saytzeff’s rule? Give an example.
  3. Why does KCN give cyanide but AgCN gives isocyanide?
  4. Write the Williamson ether synthesis reaction.

3 Mark Questions

  1. Explain the SN2 mechanism with an energy diagram. Why does it cause inversion?
  2. How do you convert: (a) ethanol to ethyl bromide (b) benzene to chlorobenzene (c) chlorobenzene to phenol?
  3. Give reasons: (a) Haloalkanes are more reactive than haloarenes (b) Allyl chloride is more reactive than n-propyl chloride towards SN1

5 Mark Questions

  1. Compare SN1 and SN2 reactions. Explain with mechanism, stereochemistry, and examples. What factors favour each?
  2. Discuss the preparation, properties and reactions of haloalkanes. Write any 4 nucleophilic substitution reactions with equations.

Quick Revision Points

  • Best prep of R−Cl: R−OH + SOCl₂ (byproducts are gases)
  • SN2: one step, back-attack, inversion, 1° best, strong nucleophile, aprotic solvent
  • SN1: two steps, carbocation, racemisation, 3° best, weak nucleophile, protic solvent
  • Elimination: alc. KOH → alkene (Saytzeff’s rule — more substituted product)
  • Substitution: aq. KOH → alcohol
  • KCN → R−CN; AgCN → R−NC (covalent silver salt → attacks through N)
  • Wurtz: 2RX + 2Na → R−R; Fittig: 2ArX + 2Na → Ar−Ar
  • Haloarenes: less reactive due to resonance (C−Cl partial double bond), ortho-para directing
  • Finkelstein: R−Cl + NaI → R−I; Swarts: R−Cl + AgF → R−F

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