Alcohols, Phenols and Ethers Class 12 Notes - CBSE Chemistry Chapter 11

Chapter summary

Alcohols, Phenols and Ethers studies three oxygen-bearing families, how to name and classify them, how they are prepared (hydration, reduction, Grignard, cumene process, Williamson synthesis), and the reactions that define each. The chapter also explains hydrogen bonding behind their physical properties and the acidity order phenol greater than water greater than alcohol. It is a high-yield Class 12 Organic chapter for NEET, with reliable questions on Lucas test, the cumene process, phenol reactions like Kolbe and Reimer-Tiemann, and ether cleavage by HX.

Chapter notes
🃏 Flash Cards: Alcohols, Phenols and Ethers

Class 12 Chemistry · Chapter 7 – swipe through all 9 cards to understand the whole chapter.

🧪Start here1/9

Three Oxygen Families

Alcohols, phenols and ethers all hold an oxygen, but the oxygen sits in a different neighbourhood in each.

Alcohol R–OH · Phenol C6H5–OH (ring) · Ether R–O–R′

Phenol = –OH directly on a benzene ring; benzyl/allyl –OH on a side chain is still an alcohol.

  • Alcohol: –OH on an sp3 carbon (e.g. ethanol)
  • Phenol: –OH bolted onto the aromatic ring carbon
  • Ether: O bridges two carbons, no O–H at all
🔢Classify & name2/9

1° / 2° / 3° and IUPAC Names

Count the carbons on the –OH carbon to classify; that one number predicts most reactions.

alkane –e + –ol · CH3CH2CH2OH = propan-1-ol

Ethers: larger group = parent alkane, smaller –OR = alkoxy; CH3–O–C2H5 = methoxyethane.

  • 0–1 other C → 1°, two → 2°, three → 3° (count carbons, not H)
  • Number the chain so –OH gets the lowest locant
  • Glycols are dihydric (two –OH groups)
🏗️Make alcohols3/9

Preparing Alcohols

Build alcohols from alkenes or carbonyls, choosing the route by the class you need.

Grignard: HCHO→1° · other RCHO→2° · ketone→3°

LiAlH4 reduces –COOH to 1° alcohol; mild NaBH4 will not touch a carboxylic acid.

  • Acid hydration of alkene → Markovnikov (OH on more substituted C)
  • Hydroboration–oxidation → anti-Markovnikov 1° alcohol
  • Aldehyde→1°, ketone→2° on reduction
⚗️Make phenol & ethers4/9

Cumene Process & Williamson

Phenol comes from cumene industrially; ethers from an alkoxide plus a halide.

R–O⁻Na⁺ + R′–X → R–O–R′ + NaX (Sₙ2)

Cumene process gives phenol + acetone (not methanol). Diethyl ether: ethanol + conc. H2SO4 at 413 K.

  • Williamson is Sₙ2 → use a 1° halide; 3° halides eliminate to alkene
  • Unsymmetrical ether: hindered group as alkoxide, simple as 1° halide
  • Cumene → cumene hydroperoxide → H⁺ → phenol + acetone
🌡️Physical props5/9

Boiling Points & H-Bonding

Hydrogen bonding decides who boils high and who boils low.

B.p.: alcohol/phenol ≫ ether ≈ alkane (similar mass)

Ethers have no O–H → cannot self H-bond; b.p. rises with chain length, falls with branching.

  • Alcohols/phenols self H-bond → high boiling points
  • Diethyl ether b.p. ~35°C vs butan-1-ol ~118°C (similar mass)
  • Branching = compact shape = less contact = lower b.p.
🧬Acidity6/9

Acidic Character

Acidity is set by how stable the leftover –O⁻ ion is after losing H⁺.

Acidity: phenol > water > alcohol

Among alcohols 1° > 2° > 3° (alkyl +I destabilises alkoxide). This is opposite to the carbocation order.

  • Phenol strongest: phenoxide resonance-stabilised into the ring
  • EWG (–NO2, o/p) raise phenol acidity; EDG (–CH3, –OCH3) lower it
  • Both react with Na→H2; only phenol reacts with NaOH
🔥Alcohol reactions7/9

What Alcohols Do

Sort every reaction by which bond breaks: the O–H or the C–O.

HX / dehydration / Lucas reactivity: 3° > 2° > 1°

Lucas (conc. HCl + ZnCl2): 3° turbid at once, 2° in ~5 min, 1° no reaction at RT.

  • O–H cleavage: esterification (reversible) and Na → alkoxide + H2
  • Oxidation: 1°→aldehyde→acid, 2°→ketone, 3° resists; PCC stops 1° at aldehyde
  • Dehydration (conc. H2SO4) follows Saytzeff → more substituted alkene
🟣Phenol reactions8/9

What Phenols Do

–OH activates the ring strongly and directs incoming groups to ortho/para.

Br2 water → 2,4,6-tribromophenol (white ppt)

Phenol’s strong C–O bond means no Lucas/HX substitution like alcohols. FeCl3 gives a violet colour.

  • Kolbe: phenoxide + CO2 then H⁺ → salicylic acid (2-OH-benzoic acid)
  • Reimer-Tiemann: phenol + CHCl3 + NaOH → salicylaldehyde
  • Conc. HNO3 → picric acid (2,4,6-trinitrophenol); oxidation → benzoquinone
🌉Ether reactions9/9

What Ethers Do

Ethers are inert solvents; only HX cleavage and aromatic substitution matter for NEET.

R–O–R′ + HX → R–X + R′–OH (HI > HBr > HCl)

Sₙ2 default: iodide hits the less-hindered carbon. If a group is 3°/allyl/benzyl → Sₙ1, stable cation takes the halide.

  • CH3–O–C2H5 + HI → CH3I + C2H5OH (methyl less hindered)
  • Anisole + HI → phenol + CH3I (aryl C–O never cleaves)
  • –OR is activating, o/p-directing in aromatic ethers
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📝 Practice Alcohols, Phenols and Ethers — 10 NEET PYQs
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Q1NEET 2021
Among C2H6 (I), C3H8O (II) and C4H10O (III), which can show METAMERISM?
Correct answer: B. Metamerism arises from different alkyl groups attached on either side of a functional group (e.g. the O of an ether). C2H6 has no functional group. C3H8O as an ether is only CH3-O-C2H5 (one arrangement, no metamers). C4H10O ethers can be CH3-O-C3H7 and C2H5-O-C2H5, two different alkyl distributions, so only C4H10O shows metamerism.
🔎 See the full step-by-step solution in the app →
Q2NEET 2021
The major product formed in the dehydrohalogenation of 2-bromopentane is pent-2-ene. This preference is based on:
Correct answer: A. Saytzeff’s rule states that the more substituted (more stable) alkene is the major elimination product. From 2-bromopentane, pent-2-ene (disubstituted) is more substituted than pent-1-ene (monosubstituted), so it predominates.
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Q3NEET 2020
But-1-ene, CH3CH2CH=CH2, is treated with B2H6 followed by H2O2/OH-. The product Z is:
Correct answer: A. Hydroboration-oxidation adds water in an anti-Markovnikov manner: -OH goes to the LESS substituted (terminal) carbon. For but-1-ene the OH lands on C1, giving the primary alcohol butan-1-ol, CH₃CH₂CH₂CH₂OH.
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Q4NEET 2020
Which substituted phenol is the STRONGEST acid: p-nitrophenol, p-methoxyphenol, p-ethylphenol or p-cresol (p-methylphenol)?
Correct answer: A. An electron-withdrawing group (-R, -I) increases phenol acidity by stabilising the phenoxide ion; an electron-donating group decreases it. -NO2 at the para position is strongly electron-withdrawing, so p-nitrophenol is the strongest acid; -OCH3, -C2H5 and -CH3 are electron-donating and weaken the acid.
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Q5NEET 2019
Ethers are readily cleaved by heating with halogen acids. For an unsymmetrical ether (with only simple primary/methyl groups) treated with limited HI, the halogen preferentially attaches to:
Correct answer: B. With simple groups the cleavage is SN2: iodide attacks the LESS hindered (smaller) carbon, which becomes the alkyl iodide, while the larger group leaves as the alcohol. (Only when a 3deg/allyl/benzyl group is present does it switch to SN1 and the bulky group take the halide.)
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Q6NEET 2019
The intermediate A in the cumene process, cumene –(O2)–> A –(H+/H2O)–> phenol + acetone, is:
Correct answer: A. Cumene (isopropylbenzene) is air-oxidised to cumene hydroperoxide, C₆H₅C(CH₃)₂-O-O-H. Treatment with dilute acid then rearranges it to phenol plus acetone.
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Q7NEET 2019
When the vapours of a secondary alcohol are passed over heated copper at 573 K, the product formed is:
Correct answer: C. Over heated Cu at 573 K, primary and secondary alcohols undergo dehydrogenation: 1deg -> aldehyde, 2deg -> ketone. So a secondary alcohol such as propan-2-ol gives a ketone (propanone). Tertiary alcohols instead dehydrate to alkenes.
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Q8NEET 2017
Which is the MOST acidic compound: p-cresol (4-methylphenol) or phenol?
Correct answer: B. The -CH3 group in p-cresol is electron-donating (+I, hyperconjugation), which destabilises the phenoxide ion and decreases acidity. Phenol, lacking this donor, gives a more stable phenoxide and is therefore more acidic than p-cresol.
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Q9NEET 2015
Reaction of phenol with chloroform in the presence of dilute sodium hydroxide finally introduces which functional group onto the ring?
Correct answer: D. This is the Reimer-Tiemann reaction. Dichlorocarbene attacks the ortho position; the resulting benzal chloride is hydrolysed by the base to a -CHO group, giving salicylaldehyde. The net new functional group is -CHO.
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Q10NEET 2006
The general molecular formula that represents the homologous series of alkanols (saturated monohydric alcohols) is:
Correct answer: D. Alkanols are derived from alkanes (CₙH₂ₙ₊₂) by replacing one H with -OH, i.e. CₙH₂ₙ₊₁-OH = CₙH₂ₙ₊₂O. For example methanol CH4O, ethanol C2H6O both fit CₙH₂ₙ₊₂O.
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Frequently Asked Questions

What is the difference between an alcohol, a phenol and an ether?

An alcohol has an -OH group bonded to an sp3 carbon, a phenol has an -OH bonded directly to a carbon of an aromatic ring, and an ether has an oxygen bridging two carbon groups (R-O-R’) with no O-H bond at all. So a benzene ring with -OH on a side-chain carbon is still an alcohol, not a phenol.

What is the Lucas test and what does it tell you?

The Lucas reagent is concentrated HCl plus anhydrous ZnCl2, used to distinguish primary, secondary and tertiary alcohols. A tertiary alcohol turns turbid immediately, a secondary alcohol in about 5 minutes, and a primary alcohol shows no reaction at room temperature, because reactivity toward HX follows 3 degree greater than 2 degree greater than 1 degree (SN1 carbocation stability).

How is phenol prepared industrially?

Phenol is made on a large scale by the cumene process: cumene (isopropylbenzene) is oxidised by air to cumene hydroperoxide, which on treatment with dilute acid gives phenol and acetone as the byproduct. Acetone, not methanol, is the coproduct, which is a common exam trap.

Why is phenol more acidic than alcohols and water?

Acidity depends on the stability of the conjugate base left after losing H+. The phenoxide ion is resonance-stabilised because its negative charge is delocalised into the aromatic ring, while the alkoxide from an alcohol is not, so the order is phenol greater than water greater than alcohol. Electron-withdrawing groups like -NO2 increase phenol acidity and electron-donating groups decrease it.

Is Alcohols, Phenols and Ethers important for NEET?

Yes, it is a scoring Class 12 Organic Chemistry chapter that regularly contributes NEET questions. High-frequency areas are the Lucas test, the cumene process, distinguishing reactions of phenol such as Kolbe and Reimer-Tiemann and bromination, the acidity order, and cleavage of ethers by HX (HI greater than HBr greater than HCl).

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