Aldehydes, Ketones and Carboxylic Acids Class 12 Notes — CBSE Chemistry Chapter 12

Chapter 12 — Aldehydes, Ketones and Carboxylic Acids — is one of the most reaction-rich and important chapters for 8-10 marks in Board exams. This chapter covers the carbonyl group (C=O), its reactions, and the chemistry of carboxylic acids. Focus on nucleophilic addition, named reactions (Aldol, Cannizzaro, Clemmensen), and distinction tests.

Key Concepts

Aldehydes and Ketones

Preparation

1. Oxidation of Alcohols:
1° alcohol + PCC → Aldehyde (mild, stops at aldehyde)
1° alcohol + K₂Cr₂O₇/H⁺ → Carboxylic acid (strong, goes all the way)
2° alcohol + K₂Cr₂O₇/H⁺ → Ketone

2. Ozonolysis of Alkenes: R₂C=CR₂ + O₃ → ozonide →(Zn/H₂O) aldehydes + ketones

3. Rosenmund Reduction: RCOCl + H₂/Pd-BaSO₄ → RCHO + HCl (acyl chloride → aldehyde)

4. Stephen Reduction: RCN + SnCl₂/HCl → RCHO (nitrile → aldehyde)

5. Gattermann-Koch: C₆H₆ + CO + HCl →(AlCl₃) C₆H₅CHO (benzaldehyde)

6. Friedel-Crafts Acylation: C₆H₆ + RCOCl →(AlCl₃) C₆H₅COR (aromatic ketone)

Nucleophilic Addition Reactions

The C=O group is polar (C^δ⁺=O^δ⁻). Nucleophiles attack the electrophilic carbon.

NucleophileReagentProduct
HCNHCN/KCNCyanohydrin (R−CH(OH)CN)
NaHSO₃Sodium bisulphiteBisulphite adduct (used for purification)
NH₂OHHydroxylamineOxime (C=NOH)
NH₂−NH₂HydrazineHydrazone (C=N−NH₂)
C₆H₅NH−NH₂PhenylhydrazinePhenylhydrazone
2,4-DNP2,4-dinitrophenylhydrazine2,4-DNP derivative (yellow/orange ppt — TEST!)
NH₂−CO−NH−NH₂SemicarbazideSemicarbazone
2,4-DNP Test: Both aldehydes AND ketones give yellow/orange precipitate with 2,4-dinitrophenylhydrazine. This confirms the presence of C=O group.
Reactivity order for nucleophilic addition:
HCHO > CH₃CHO > C₂H₅CHO > (CH₃)₂CO
(More alkyl groups → more steric hindrance + electron donation → less electrophilic carbon → slower)

Oxidation Reactions

Tollen’s Test (Silver Mirror Test): RCHO + 2[Ag(NH₃)₂]⁺ + 2OH⁻ → RCOO⁻ + 2Ag↓ + 4NH₃ + H₂O
(Silver mirror deposited — works for aldehydes ONLY, not ketones)

Fehling’s Test: RCHO + 2Cu²⁺ + 5OH⁻ → RCOO⁻ + Cu₂O↓(red ppt) + 3H₂O
(Works for aliphatic aldehydes; aromatic aldehydes don’t respond)

Reduction Reactions

To Alcohol: R−CHO + NaBH₄ or LiAlH₄ → R−CH₂OH
Clemmensen Reduction: R−CO−R’ + Zn-Hg/conc. HCl → R−CH₂−R’ (C=O → CH₂, acidic)
Wolff-Kishner Reduction: R−CO−R’ + NH₂NH₂/KOH/ethylene glycol → R−CH₂−R’ (C=O → CH₂, basic)

Important Named Reactions

Aldol Condensation: 2CH₃CHO →(dilute NaOH) CH₃CH(OH)CH₂CHO (β-hydroxy aldehyde)
On heating: → CH₃CH=CHCHO + H₂O (α,β-unsaturated aldehyde)
Requires: α-hydrogen on the aldehyde/ketone

Cross Aldol: HCHO + CH₃CHO → HOCH₂CH₂CHO

Cannizzaro Reaction: 2HCHO →(conc. NaOH) HCOO⁻Na⁺ + CH₃OH
(Self-oxidation-reduction — one molecule oxidised to acid, one reduced to alcohol)
Requires: NO α-hydrogen (HCHO, C₆H₅CHO, (CH₃)₃CCHO)

Key Rule: If α-H present → Aldol; If no α-H → Cannizzaro
Haloform Reaction: CH₃CO−R + 3X₂ + 4NaOH → RCOONa + CHX₃
With I₂/NaOH: gives yellow precipitate of CHI₃ (iodoform) — Iodoform Test
Works for: CH₃CHO, methyl ketones (CH₃COR), ethanol, 2° alcohols (CH₃CHOH−R)

Carboxylic Acids (R−COOH)

Preparation

1. Oxidation: 1° alcohol/aldehyde + KMnO₄ or K₂Cr₂O₇/H⁺ → RCOOH
2. From Grignard: RMgX + CO₂ →(dry ether) RCOOMgX →(H₃O⁺) RCOOH
3. Hydrolysis of Nitriles: RCN + H₃O⁺ → RCOOH + NH₄⁺
4. Hydrolysis of Esters: RCOOR’ + NaOH → RCOONa + R’OH (saponification)

Acidity of Carboxylic Acids

Carboxylic acids > Phenols > Alcohols > Water (in acidity)

Reason: RCOO⁻ is stabilised by resonance — negative charge delocalised over two equivalent oxygen atoms. This makes it exceptionally stable compared to alkoxide or phenoxide.

Test: Carboxylic acids react with NaHCO₃ → CO₂↑ (effervescence)
Phenols do NOT give this test!

Effect of Substituents on Acidity

  • Electron-withdrawing groups (−Cl, −NO₂, −CF₃): Increase acidity (stabilise COO⁻)
  • Electron-donating groups (−CH₃, −OCH₃, −NH₂): Decrease acidity (destabilise COO⁻)
  • Cl₃CCOOH > Cl₂CHCOOH > ClCH₂COOH > CH₃COOH (more Cl → more acidic)

Reactions of Carboxylic Acids

With SOCl₂: RCOOH + SOCl₂ → RCOCl + SO₂ + HCl (acyl chloride)
With NH₃: RCOOH + NH₃ → RCOONH₄ →(Δ) RCONH₂ (amide)
Esterification: RCOOH + R’OH →(H₂SO₄) RCOOR’ + H₂O
Decarboxylation: RCOONa + NaOH →(CaO, Δ) RH + Na₂CO₃ (loses CO₂)
Hell-Volhard-Zelinsky (HVZ): RCOOH + Br₂/P → α-bromoacid (halogenation at α-carbon)

Important Definitions

TermDefinition
Nucleophilic AdditionAddition of a nucleophile to the electrophilic C of C=O
Aldol CondensationSelf-condensation of aldehydes/ketones with α-H in dilute base
Cannizzaro ReactionSelf-redox of aldehydes without α-H in conc. NaOH
Iodoform TestYellow ppt of CHI₃ with I₂/NaOH — tests for CH₃CO− or CH₃CHOH−
Tollen’s TestSilver mirror test for aldehydes using ammoniacal AgNO₃
SaponificationAlkaline hydrolysis of ester to give soap (sodium carboxylate)

Solved Examples — NCERT Based

Example 1: Distinguishing Aldehyde from Ketone

Q: How do you distinguish between ethanal and propanone?

Solution:

Tollen’s test: Ethanal (CH₃CHO) gives silver mirror. Propanone (CH₃COCH₃) does not.

Fehling’s test: Ethanal gives red precipitate of Cu₂O. Propanone does not.

Iodoform test: Both give positive iodoform test (both have CH₃CO−). So this test cannot distinguish them.

Example 2: Aldol Condensation

Q: Write the products of aldol condensation of acetaldehyde (CH₃CHO).

Solution:

2CH₃CHO →(dil. NaOH) CH₃CH(OH)CH₂CHO (3-hydroxybutanal — aldol)

On heating: CH₃CH(OH)CH₂CHO → CH₃CH=CHCHO + H₂O (crotonaldehyde)

Example 3: Acidity Order

Q: Arrange in increasing acidity: CH₃COOH, HCOOH, ClCH₂COOH, FCH₂COOH

Solution:

−I effect: F > Cl (F is more electronegative). HCOOH has no alkyl group → more acidic than CH₃COOH.

Order: CH₃COOH < HCOOH < ClCH₂COOH < FCH₂COOH

Example 4: Identifying Reactions

Q: Which reaction will formaldehyde (HCHO) undergo: Aldol or Cannizzaro? Write the products.

Solution:

HCHO has no α-hydrogen → undergoes Cannizzaro reaction.

2HCHO + conc. NaOH → HCOONa (sodium formate) + CH₃OH (methanol)

One molecule is oxidised to formate, the other is reduced to methanol.

Important Questions for Board Exams

1 Mark Questions

  1. What is the reagent for Tollen’s test?
  2. Which compound gives both Aldol and Cannizzaro? (None — they’re mutually exclusive!)
  3. Name the product when acetic acid reacts with SOCl₂.
  4. Why is HCOOH stronger acid than CH₃COOH?

2 Mark Questions

  1. Explain why aldehydes are more reactive than ketones towards nucleophilic addition.
  2. Write the mechanism of Cannizzaro reaction of formaldehyde.
  3. Give the iodoform test. What structural feature does it detect?
  4. How do you convert: (a) benzaldehyde → benzoic acid (b) acetone → 2-propanol?

3 Mark Questions

  1. What is aldol condensation? Give its mechanism. Can ketones undergo aldol condensation?
  2. Distinguish between: (a) ethanal and propanal (b) acetaldehyde and benzaldehyde (c) pentan-2-one and pentan-3-one.
  3. Compare the acidity of acetic acid, formic acid, chloroacetic acid and phenol with reasons.

5 Mark Questions

  1. Discuss the nucleophilic addition reactions of aldehydes and ketones. Why are aldehydes more reactive? Explain with 5 reactions.
  2. What are carboxylic acids? Discuss their preparation (any 3 methods), acidic character, and important reactions (esterification, SOCl₂, HVZ).

Quick Revision Points

  • Nucleophilic addition: HCHO > other aldehydes > ketones (steric + electronic)
  • Tollen’s test: Ag mirror (aldehyde only); Fehling’s: Cu₂O red ppt (aliphatic aldehyde only)
  • 2,4-DNP test: confirms C=O group (both aldehyde and ketone)
  • Iodoform: CH₃CHO, CH₃COR, CH₃CHOH-R give yellow CHI₃
  • α-H present → Aldol; no α-H → Cannizzaro
  • Clemmensen: Zn-Hg/HCl (acidic) | Wolff-Kishner: NH₂NH₂/KOH (basic) — both reduce C=O to CH₂
  • Acidity: RCOOH > PhOH > H₂O > ROH
  • EWG increases acidity (−Cl, −NO₂), EDG decreases (−CH₃)
  • NaHCO₃ test: carboxylic acids give CO₂, phenols don’t
  • HVZ: α-halogenation of carboxylic acids using Br₂/P

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