Alcohols, Phenols and Ethers Class 12 Notes — CBSE Chemistry Chapter 11

Chapter 11 — Alcohols, Phenols and Ethers — covers three important classes of oxygen-containing organic compounds. This chapter carries 6-8 marks in Board exams and is rich in reactions and conversions. Master the distinction tests, oxidation reactions, and the acidity comparison between alcohols and phenols.

Key Concepts

Alcohols (R−OH)

Classification and Preparation

1. From Alkenes (Hydration): CH₂=CH₂ + H₂O →(H₂SO₄) CH₃CH₂OH (Markovnikov)
2. From Grignard Reagent:
HCHO + RMgX → 1° alcohol
RCHO + R’MgX → 2° alcohol
R₂CO + R’MgX → 3° alcohol
3. Reduction of Aldehydes/Ketones: RCHO + H₂/Ni → RCH₂OH (or NaBH₄, LiAlH₄)
4. Hydrolysis of Haloalkanes: RX + aq. KOH → ROH + KX

Reactions of Alcohols

ReactionReagentProduct
DehydrationConc. H₂SO₄, 443 KAlkene (Saytzeff’s rule)
Oxidation (1° alcohol)PCC or mild oxidantAldehyde
Oxidation (1° alcohol)KMnO₄ or K₂Cr₂O₇/H⁺Carboxylic acid
Oxidation (2° alcohol)K₂Cr₂O₇/H⁺Ketone
Oxidation (3° alcohol)Strong oxidantCleaves to smaller molecules
EsterificationR’COOH + H₂SO₄Ester (R’COOR) + H₂O
With Na metalNaAlkoxide (R−ONa) + H₂↑
With HBrHBrR−Br + H₂O
Lucas Test (distinguishes 1°, 2°, 3° alcohols): Add anhydrous ZnCl₂ + conc. HCl.
3° → immediate turbidity | 2° → turbidity in 5 min | 1° → no turbidity at room temperature

Dehydration Order

Ease of dehydration: 3° > 2° > 1° (follows carbocation stability)
Temperature: 1° needs 443 K, 2° needs ~400 K, 3° needs ~350 K

Phenols (ArOH)

Preparation

1. Cumene Process (Industrial):
C₆H₅CH(CH₃)₂ + O₂ → C₆H₅C(CH₃)₂OOH →(H₂SO₄) C₆H₅OH + (CH₃)₂CO
(Phenol + Acetone — both useful products!)

2. From Diazonium Salt: ArN₂⁺Cl⁻ + H₂O →(warm) ArOH + N₂ + HCl
3. Dow Process: C₆H₅Cl + NaOH →(623 K, 300 atm) C₆H₅ONa →(HCl) C₆H₅OH

Acidity of Phenols

Phenol is more acidic than alcohol because phenoxide ion (C₆H₅O⁻) is stabilised by resonance with the benzene ring. The negative charge delocalises over the ring.

Acidity order: Water (pKa 15.7) < Ethanol (15.9) < Phenol (10.0)
Phenol reacts with NaOH but NOT with NaHCO₃ (unlike carboxylic acids)

Reactions of Phenols

Kolbe Reaction: C₆H₅ONa + CO₂ →(125°C, 4-7 atm) sodium salicylate →(HCl) salicylic acid
Reimer-Tiemann Reaction: C₆H₅OH + CHCl₃ + NaOH → salicylaldehyde (ortho-hydroxybenzaldehyde)
Coupling with Diazonium Salt: C₆H₅OH + C₆H₅N₂⁺Cl⁻ → p-hydroxyazobenzene (orange dye)

Phenol undergoes electrophilic substitution easily (−OH is activating, ortho-para directing):

  • Bromination: C₆H₅OH + 3Br₂(aq) → 2,4,6-tribromophenol↓ (white ppt) — used as a test!
  • Nitration: With dilute HNO₃ → o- and p-nitrophenol

Ethers (R−O−R’)

Preparation — Williamson Synthesis

R−ONa + R’−X → R−O−R’ + NaX
Best with primary alkyl halides (SN2). Tertiary halides give elimination (alkene) instead!

Reactions of Ethers

Cleavage by HI (excess): R−O−R’ + 2HI → R−I + R’−I + H₂O
(HI is used because I⁻ is the best nucleophile)

For ArOCH₃ (anisole): ArOCH₃ + HI → ArOH + CH₃I
(C−O bond of aryl group doesn’t break — phenol is formed, not aryl halide)

Important Definitions

TermDefinition
AlcoholOrganic compound with −OH group on saturated carbon
PhenolOrganic compound with −OH group directly on benzene ring
EtherOrganic compound with C−O−C linkage
DehydrationRemoval of water from alcohol to form alkene
Williamson SynthesisPreparation of ether from alkoxide and alkyl halide
Kolbe ReactionCarboxylation of sodium phenoxide to form salicylic acid

Solved Examples — NCERT Based

Example 1: Grignard Synthesis

Q: How would you prepare propan-1-ol using a Grignard reagent?

Solution:

React ethanal (CH₃CHO) with methylmagnesium bromide (CH₃MgBr):

CH₃CHO + CH₃MgBr → CH₃CH(OMgBr)CH₃ →(H₃O⁺) CH₃CH(OH)CH₃

Wait — this gives propan-2-ol (secondary). For propan-1-ol:

Use HCHO + C₂H₅MgBr → C₂H₅CH₂OH (propan-1-ol, primary)

Example 2: Acidity Comparison

Q: Arrange in increasing acidity: ethanol, phenol, p-nitrophenol, p-methylphenol

Solution:

Electron-withdrawing groups (−NO₂) increase acidity; electron-donating groups (−CH₃) decrease it.

Ethanol < p-methylphenol < phenol < p-nitrophenol

(Most acidic is p-nitrophenol — −NO₂ stabilises the phenoxide ion by delocalisation)

Example 3: Distinction Test

Q: How will you distinguish between ethanol and phenol?

Solution:

Test 1 — FeCl₃ test: Phenol gives violet/purple colour with neutral FeCl₃. Ethanol does not.

Test 2 — Bromine water: Phenol gives white precipitate of 2,4,6-tribromophenol. Ethanol does not react.

Example 4: Williamson Synthesis

Q: Prepare methyl tert-butyl ether (MTBE) using Williamson synthesis. Which alkoxide and which halide should you use?

Solution:

Use sodium methoxide + tert-butyl chloride? NO — 3° halide will give elimination!

Correct method: (CH₃)₃CONa + CH₃I → (CH₃)₃COCH₃

Use tert-butoxide (bulky is fine for alkoxide) + methyl iodide (primary halide → SN2)

Important Questions for Board Exams

1 Mark Questions

  1. Why is phenol more acidic than ethanol?
  2. What is Lucas reagent?
  3. Write the product of Kolbe’s reaction.
  4. What happens when phenol reacts with bromine water?

2 Mark Questions

  1. Write the mechanism of acid-catalysed dehydration of ethanol.
  2. How will you distinguish between 1°, 2° and 3° alcohols?
  3. What is Williamson ether synthesis? Why should tertiary halides not be used?
  4. Give the Reimer-Tiemann reaction with equation.

3 Mark Questions

  1. Explain the preparation of phenol by cumene process. What is the co-product?
  2. How do you convert: (a) ethanol → ethene (b) phenol → salicylic acid (c) phenol → aspirin?
  3. Compare the acidity of ethanol, phenol, and p-nitrophenol with reasons.

5 Mark Questions

  1. Discuss the preparation and chemical reactions of alcohols. Include oxidation, dehydration, esterification, and reaction with Na.
  2. What are phenols? How are they prepared? Discuss their electrophilic substitution reactions and the Kolbe and Reimer-Tiemann reactions.

Quick Revision Points

  • Alcohols: 1° → aldehyde → acid; 2° → ketone; 3° → resistant to oxidation
  • Dehydration ease: 3° > 2° > 1° (conc. H₂SO₄)
  • Lucas test: 3° immediate, 2° in 5 min, 1° no reaction at RT
  • Phenol: acidic (resonance-stabilised phenoxide), reacts with NaOH but not NaHCO₃
  • Cumene process: benzene → cumene → phenol + acetone (industrial)
  • Kolbe: PhONa + CO₂ → salicylic acid
  • Reimer-Tiemann: PhOH + CHCl₃/NaOH → salicylaldehyde
  • Williamson: RONa + R’X → ROR’ (use 1° halide to avoid elimination)
  • Ether cleavage: R−O−R + HI → 2R−I
  • Distinction: phenol → violet with FeCl₃, white ppt with Br₂ water

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