The p-Block Elements Class 11 Notes | CBSE Chemistry Chapter 10

Chapter summary

The p-Block Elements Groups 13 and 14 covers boron, aluminium, carbon, silicon and their heavier family members, studying how their ns2 np1 and ns2 np2 configurations drive periodic trends, the inert pair effect, and key compounds like borax, diborane, alums, carbon allotropes, silica and silicones. It explains why lower oxidation states win down the group (Tl plus and Pb 2 plus) and why only carbon shows strong catenation and multiple bonding. It is a high-yield inorganic chemistry chapter for NEET, with reliable questions on the inert pair effect, diborane bonding, boron and aluminium compounds, and carbon group trends.

Chapter notes

Table of Contents


Key Concepts

1. General Introduction to the p-Block

The p-block contains elements in which the last electron enters one of the three p-orbitals of their outermost shell. It spans Groups 13 to 18 of the periodic table, and its general outer electronic configuration is ns²np¹⁻⁶.

This block is special because it holds metals, non-metals, and metalloids all together - the only block where all three appear. The non-metallic character is strongest at the top-right and metallic character increases as you go down and to the left.

The Inert Pair Effect

As we move down a group, the tendency of the two ns electrons to remain paired and not participate in bonding increases. This is called the inert pair effect, and it explains why the lower oxidation state becomes more stable down a group (e.g., Tl⁺ is more stable than Tl³⁺, and Pb²⁺ more stable than Pb⁴⁺).


2. Group 13 - The Boron Family

Group 13 consists of boron (B), aluminium (Al), gallium (Ga), indium (In), and thallium (Tl). Their general outer electronic configuration is ns²np¹.

Boron is a non-metal (a metalloid); all the others are metals. The common oxidation state is +3, but due to the inert pair effect the +1 state becomes increasingly stable down the group.

Trends in Group 13

  • Atomic radius: increases down the group, but Ga is slightly smaller than Al (poor shielding by 3d electrons).
  • Ionisation enthalpy: decreases down the group overall (with minor irregularities).
  • Metallic character: increases down the group - B is a metalloid, Tl is a soft metal.
  • Oxidation state: +3 dominates at the top; +1 stability rises down the group due to inert pair effect.
  • Nature of oxides: B₂O₃ is acidic, Al₂O₃ and Ga₂O₃ are amphoteric, In₂O₃ and Tl₂O₃ are basic.

3. Anomalous Behaviour of Boron

Boron, the first member of Group 13, differs sharply from the rest of its family. This is due to its small size, high ionisation enthalpy, high electronegativity, and the absence of d-orbitals in its valence shell.

  • Boron is a non-metal (metalloid); the rest are metals.
  • Boron is never found as a B³⁺ ion - it forms only covalent compounds, while others can form ionic compounds.
  • The maximum covalency of boron is 4 (no d-orbitals), whereas heavier members can expand their covalency beyond 4.
  • Boron forms electron-deficient compounds like BF₃ and diborane (B₂H₆).

Diagonal relationship: Boron resembles silicon (the diagonally placed element of Group 14) more than it resembles aluminium - for example, both B and Si form covalent, polymeric, acidic oxides.


4. Important Compounds of Boron

Borax (Na₂B₄O₇·10H₂O)

Borax is sodium tetraborate decahydrate, a white crystalline solid. Its correct structural formula is Na₂[B₄O₅(OH)₄]·8H₂O, containing two triangular (BO₃) and two tetrahedral (BO₄) units.

  • An aqueous solution of borax is alkaline (it hydrolyses), so it acts as a buffer.
  • Borax bead test: on heating, borax swells and then melts to a transparent glassy bead of sodium metaborate and boric anhydride (NaBO₂ + B₂O₃), used to identify coloured metal ions.
  • Reaction on heating: Na₂B₄O₇·10H₂O → 2NaBO₂ + B₂O₃ + 10H₂O.

Orthoboric Acid (H₃BO₃)

Boric acid is a white, soft, soapy solid with a layered structure in which planar BO₃ units are joined by hydrogen bonds.

  • It is a weak monobasic acid - but not a protonic acid. It acts as a Lewis acid by accepting OH⁻ from water: B(OH)₃ + 2H₂O → [B(OH)₄]⁻ + H₃O⁺.
  • On heating, it loses water in steps: H₃BO₃ → HBO₂ (metaboric acid) → B₂O₃ (boric anhydride).
  • Used as a mild antiseptic and in the glass/ceramics industry.

Diborane (B₂H₆)

Diborane is the simplest boron hydride, a colourless, toxic gas that catches fire spontaneously in air. It is an electron-deficient molecule.

[DIAGRAM: B₂H₆ structure - two boron atoms each bonded to two terminal H atoms by normal covalent bonds, and bridged by two H atoms through three-centre two-electron (banana) bonds.]

  • It contains four terminal B–H bonds (normal 2-centre 2-electron bonds) and two bridging B–H–B bonds (3-centre 2-electron “banana” bonds).
  • Combustion: B₂H₆ + 3O₂ → B₂O₃ + 3H₂O (highly exothermic).
  • With ammonia it gives borazine (B₃N₆H₆), called “inorganic benzene”.

5. Aluminium

Aluminium is the most abundant metal in the Earth’s crust. It is a silvery-white, light, malleable metal showing the +3 oxidation state, and it is the most important member of Group 13 commercially.

  • Amphoteric nature: aluminium and its oxide react with both acids and alkalis.
    2Al + 6HCl → 2AlCl₃ + 3H₂; 2Al + 2NaOH + 2H₂O → 2NaAlO₂ + 3H₂.
  • Passivity: a thin, tough oxide layer protects aluminium from further corrosion, so concentrated HNO₃ renders it passive.
  • AlCl₃ exists as a dimer (Al₂Cl₆) in the vapour and non-polar solvents, completing aluminium’s octet.
  • Used in alloys (duralumin), electrical cables, packaging, and as a reducing agent in the thermite process.

6. Group 14 - The Carbon Family

Group 14 consists of carbon (C), silicon (Si), germanium (Ge), tin (Sn), and lead (Pb). Their general outer electronic configuration is ns²np².

The group shows a clear shift from non-metal to metal: carbon is a non-metal, silicon and germanium are metalloids, and tin and lead are metals. The common oxidation states are +4 and +2.

Trends in Group 14

  • Atomic radius: increases down the group; the increase from C to Si is large, then small thereafter.
  • Metallic character: increases down the group (C → non-metal, Sn, Pb → metals).
  • Oxidation state: +4 is stable at the top; +2 stability rises down the group (Pb²⁺ > Pb⁴⁺) due to the inert pair effect.
  • Catenation: the self-linking ability decreases down the group: C ≫ Si > Ge ≈ Sn ≫ Pb. The strong C–C bond explains the millions of carbon compounds.
  • Nature of oxides: CO₂ and SiO₂ are acidic, GeO₂ is weakly acidic, SnO₂ and PbO₂ are amphoteric.

7. Anomalous Behaviour of Carbon & Allotropes

Carbon, like boron, differs from the rest of its group because of its small size, high electronegativity, high ionisation enthalpy, and the absence of d-orbitals. Two unique features stand out: its maximum covalency is 4, and it has an exceptional ability for catenation and pπ–pπ multiple bonding.

Allotropes of Carbon

  • Diamond: each carbon is sp³ hybridised and bonded tetrahedrally to four others, forming a rigid 3-D network. It is the hardest natural substance and does not conduct electricity.
  • Graphite: each carbon is sp² hybridised, forming planar hexagonal layers held by weak van der Waals forces. The delocalised electrons make it a good conductor and a lubricant.
  • Fullerenes (e.g., C₆₀): cage-like molecules (“buckyballs”) with both 5- and 6-membered rings; the only pure, neat allotrope.

[TABLE: Diamond is sp³, 3-D, hard, insulator; Graphite is sp², 2-D layers, soft, conductor; Fullerene is sp², spherical cage, molecular solid.]


8. Oxides of Carbon - CO and CO₂

Carbon Monoxide (CO)

Carbon monoxide is a colourless, odourless, highly poisonous gas formed by the incomplete combustion of carbon. It is neutral and a powerful reducing agent.

  • It is toxic because it binds to haemoglobin about 300 times more strongly than oxygen, forming carboxyhaemoglobin and blocking oxygen transport.
  • It is a good reducing agent, used in metallurgy: Fe₂O₃ + 3CO → 2Fe + 3CO₂.

Carbon Dioxide (CO₂)

Carbon dioxide is a colourless, odourless acidic gas. It is a linear, non-polar molecule (O=C=O) and the main greenhouse gas responsible for global warming.

  • It dissolves in water to form weak carbonic acid: CO₂ + H₂O ⇌ H₂CO₃.
  • Solid CO₂ (“dry ice”) sublimes directly and is used as a refrigerant.
  • Essential for photosynthesis, which keeps the carbon cycle balanced.

9. Silicones

Silicones are synthetic organosilicon polymers containing repeating R₂SiO units, with a backbone of alternating silicon and oxygen atoms (–Si–O–Si–O–) and organic groups attached to silicon.

  • They are prepared by the hydrolysis of dialkyl/diaryl dichlorosilanes (R₂SiCl₂) followed by polymerisation.
  • They are water-repellent (hydrophobic), heat-resistant, and chemically inert.
  • Uses: water-proofing fabrics, lubricants, sealants, electrical insulators, and biomedical implants.

10. Silicates and Zeolites

Silicates

Silicates are compounds in which the basic structural unit is the SiO₄⁴⁻ tetrahedron. These tetrahedra link by sharing oxygen corners to form chains, sheets, or three-dimensional networks.

  • When all four corner oxygens are shared, the neutral, giant covalent solid silica (SiO₂) results.
  • Examples include feldspar, asbestos, mica, and zeolites.

Zeolites

Zeolites are three-dimensional aluminosilicates with a porous, cage-like structure, formed when some silicon atoms in SiO₄ are replaced by aluminium (giving an AlO₄ unit and a negative charge balanced by cations).

  • Used as ion-exchangers to soften hard water (Permutit process).
  • ZSM-5 is used as a catalyst to convert alcohols directly into petrol (gasoline).
  • Used as molecular sieves and as catalysts in the petrochemical industry.

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Weightage in Board & Entrance Exams

ExamTypical WeightageMost-Tested Areas
CBSE Board (Class 11)6–8 marksAnomalous behaviour, borax/boric acid, diborane structure, allotropes, silicones
JEE Main / Advanced1–2 questionsInert pair effect, structure of diborane & borax, catenation trend
NEET1–2 questionsProperties of CO/CO₂, oxides’ acidic-basic nature, uses of zeolites & silicones

[TABLE: Question-type split - VSA (1 mark): definitions & formulae; SA (2–3 marks): anomalous behaviour, diborane bonding, CO toxicity; LA (5 marks): borax structure & bead test, allotropes comparison, silicones preparation.]


Important Definitions

TermDefinition
p-Block elementElement in which the last electron enters a p-orbital; configuration ns²np¹⁻⁶
Inert pair effectReluctance of the ns² electron pair to bond, stabilising lower oxidation states down a group
Diagonal relationshipSimilarity between an element and the one placed diagonally to it (e.g., B and Si)
Electron-deficient compoundA molecule with fewer electrons than needed for normal bonds, e.g., B₂H₆, BF₃
Three-centre two-electron bondA “banana” bond where two electrons bind three atoms, as in the B–H–B bridge of diborane
CatenationSelf-linking of like atoms into chains/rings; strongest in carbon
AllotropyExistence of an element in two or more forms differing in physical properties
SiliconesOrganosilicon polymers with an –Si–O–Si– backbone and organic side groups
ZeolitePorous three-dimensional aluminosilicate used as ion-exchanger and catalyst
Amphoteric oxideAn oxide that reacts with both acids and bases, e.g., Al₂O₃

Solved Examples

Example 1

Why does boron form only covalent compounds and never the B³⁺ ion?

Answer: Boron has a very small size and very high ionisation enthalpy. Removing three electrons to form B³⁺ needs more energy than is released by lattice/hydration, so it is energetically unfavourable. Hence boron shares electrons and forms only covalent compounds.

Example 2

Explain why diborane (B₂H₆) is called an electron-deficient molecule.

Answer: B₂H₆ has 12 valence electrons but needs more to form eight normal 2-electron bonds. It has four normal terminal B–H bonds and two three-centre two-electron B–H–B bridge bonds. Since there are not enough electrons for all conventional bonds, it is electron-deficient.

Example 3

Why does the +1 oxidation state become more stable than +3 down Group 13?

Answer: Down the group the inert pair effect increases - the ns² electrons become reluctant to participate in bonding. So Tl prefers the +1 state, making Tl⁺ more stable than Tl³⁺.

Example 4

Why is carbon monoxide poisonous?

Answer: CO binds to the haemoglobin of blood about 300 times more strongly than O₂, forming carboxyhaemoglobin. This blocks oxygen transport to the tissues, which can be fatal.

Example 5

Why does carbon show the maximum tendency for catenation in Group 14?

Answer: The C–C bond is exceptionally strong (about 348 kJ/mol) because of carbon’s small size and effective orbital overlap. Bond strength falls down the group (Si–Si, Ge–Ge weaker), so catenation is greatest in carbon - explaining its millions of compounds.

Example 6

What happens when borax is heated strongly? Write the reaction.

Answer: Borax first loses water of crystallisation, swells, and then melts to a clear glassy bead: Na₂B₄O₇·10H₂O → 2NaBO₂ + B₂O₃ + 10H₂O. The bead (sodium metaborate + boric anhydride) is the basis of the borax bead test for coloured metal ions.


Important Questions for Board Exams

1-Mark Questions (VSA)

  1. Write the general outer electronic configuration of p-block elements.
  2. What is the inert pair effect?
  3. Why is boric acid considered a weak monobasic acid?
  4. Name the hardest allotrope of carbon and give the hybridisation of its carbon atoms.
  5. Give one important use of zeolites.

2–3-Mark Questions (SA)

  1. Explain the anomalous behaviour of boron with any three points.
  2. Describe the structure of diborane and explain the bonding in it.
  3. Compare the structures and properties of diamond and graphite.
  4. What are silicones? How are they prepared, and give two uses.

5-Mark Questions (LA)

  1. Discuss the trends in oxidation state and the nature of oxides down Group 13, explaining them in terms of the inert pair effect.
  2. Explain the structure of borax and describe the borax bead test with relevant reactions.
  3. Discuss catenation in Group 14 and explain why carbon shows it to the greatest extent. Compare the acidic/basic nature of the oxides of the group.

Quick Revision Points

  • p-block: Groups 13–18; general configuration ns²np¹⁻⁶; holds metals, non-metals, metalloids
  • Inert pair effect → lower oxidation state more stable down a group (Tl⁺, Pb²⁺)
  • Group 13 (ns²np¹): +3 common; oxide nature B₂O₃ acidic → Al₂O₃ amphoteric → Tl₂O₃ basic
  • Boron is anomalous - small size, no d-orbitals, max covalency 4, only covalent compounds; diagonal with Si
  • Borax: Na₂B₄O₇·10H₂O → 2NaBO₂ + B₂O₃ on heating; basis of bead test
  • Boric acid H₃BO₃ - weak monobasic Lewis acid; layered, H-bonded structure
  • Diborane B₂H₆ - electron-deficient; 4 terminal B–H + 2 bridging 3c–2e bonds
  • Aluminium - amphoteric, made passive by conc. HNO₃; AlCl₃ dimerises to Al₂Cl₆
  • Group 14 (ns²np²): +4 and +2; catenation C ≫ Si > Ge ≈ Sn ≫ Pb
  • Carbon allotropes: diamond (sp³, hard, insulator), graphite (sp², conductor, lubricant), fullerene (C₆₀)
  • CO - neutral, poisonous (carboxyhaemoglobin), reducing agent; CO₂ - acidic, greenhouse gas
  • Silicones - –Si–O–Si– polymers, water-repellent; zeolites - porous aluminosilicates, ion-exchangers/catalysts

Next Chapter: Chapter 11 - Organic Chemistry: Some Basic Principles and Techniques

🃏 Flash Cards: The p-Block Elements (Groups 13 & 14)

Class 11 Chemistry – swipe through all 9 cards to understand the whole chapter.

🧭Start here1/9

Meet Groups 13 & 14

Two p-block families that share an outer-shell pattern but turn more metallic as you go down.

Group 13: ns2 np1 (B, Al, Ga, In, Tl) · Group 14: ns2 np2 (C, Si, Ge, Sn, Pb)

First members B and C are anomalous: small, electronegative, no d-orbitals.

  • Group 13 has 3 valence electrons, Group 14 has 4.
  • Metallic character rises down each group (B metalloid → Tl metal; C non-metal → Pb metal).
  • B and C have a maximum covalency of 4 (no valence d-orbitals).
📏Periodic trends2/9

Size, IE & the Ga Anomaly

Atoms grow larger down a group, but poor 3d shielding makes gallium smaller than aluminium.

Ga < Al < In (radius) · IE1 (Gp 13): B > Tl > Ga ≈ Al > In

Group 13 IE1 is lower than the Group 2 neighbour (easy np1 vs stable ns2).

  • Radius increases down a group, but Ga < Al due to poor 3d-shielding.
  • Ionisation enthalpy generally falls down a group, with d-/f-shielding wobbles.
  • Tl sits high in the IE1 order because bad 4f/5d shielding grips the 6s pair tightly.
🪙Core idea3/9

Inert Pair Effect

The outer ns2 pair becomes reluctant to bond, so the lower oxidation state wins down the group.

Group 13: +3 → +1 (Tl⁺ > Tl3⁺) · Group 14: +4 → +2 (Pb2⁺ > Pb4⁺)

It is the ns2 pair (not np or d) that turns inert; effect grows down the group.

  • Heavy ns2 pair is held tightly and costs too much energy to unpair for weak bonds.
  • PbO2 and Tl3⁺ are strong oxidisers; SnCl2 and Ge2⁺ are strong reducers.
  • Stability: Tl⁺ > Tl3⁺, Pb2⁺ > Pb4⁺, but Sn4⁺ > Pb4⁺ and Pb2⁺ > Sn2⁺.
💎Key compound4/9

Borax & Boric Acid

Borax is an alkaline borate; orthoboric acid is a weak Lewis acid, not a proton donor.

Na2B4O7·10H2O ≡ Na2[B4O5(OH)4]·8H2O · B(OH)3 + 2H2O → [B(OH)4]⁻ + H3O⁺

Borax has 2 sp2 + 2 sp3 boron atoms; its aqueous solution is alkaline.

  • Bead test: Na2B4O7 → 2NaBO2 + B2O3 gives coloured metaborates with metal salts.
  • H3BO3 is weak, monobasic and a Lewis acid (it accepts OH⁻, not donates H⁺).
  • Solid H3BO3 is a layered, hydrogen-bonded sheet structure.
🍌Bonding5/9

Diborane: Banana Bonds

B2H6 has too few electrons for normal bonds, so it bridges with three-centre, two-electron bonds.

B2H6: 4 terminal H + 2 bridging H · two 3c-2e B–H–B bonds · 12 valence e⁻

Electron-deficient: 8 ordinary B–H bonds would need 16 e⁻ but only 12 exist.

  • Two bridge bonds use 2 pairs; the remaining 4 pairs make the 4 terminal B–H bonds.
  • Each banana bond glues three atoms (B–H–B) with a single electron pair.
  • Boron never exceeds a covalency of 4 (no d-orbitals).
🧱Key element6/9

Aluminium & Its Compounds

Aluminium is amphoteric, goes passive in conc. HNO3, and its chloride dimerises to complete the octet.

2Al + 6HCl → 2AlCl3 + 3H2 · 2Al + 2NaOH + 6H2O → 2Na[Al(OH)4] + 3H2

Both acid and alkali liberate H2; conc. HNO3 forms a passivating Al2O3 layer.

  • Anhydrous AlCl3 exists as Cl-bridged dimer Al2Cl6; strong Lewis acid (Friedel–Crafts).
  • Boron halide Lewis acidity: BF3 < BCl3 < BBr3 (back-bonding weakest in BBr3).
  • Alums are M⁺M3⁺(SO4)2·12H2O, e.g. potash alum KAl(SO4)2·12H2O for water purification.
🔷Allotropes7/9

Carbon’s Three Faces

Pure carbon takes three forms whose properties come entirely from how the atoms are bonded.

Diamond: sp3 3D network · Graphite: sp2 sheets · Fullerene C60: 20 six- + 12 five-rings

Graphite is the thermodynamically most stable allotrope of carbon.

  • Diamond is sp3, the hardest natural substance and an insulator.
  • Graphite is sp2, conducts electricity (delocalised e⁻) and is a lubricant (sliding sheets).
  • Fullerene C60 is the only pure allotrope with no dangling bonds.
🔗Core idea8/9

Catenation & pπ–pπ Bonds

Carbon’s strong C–C bond gives it unmatched self-linking, and only carbon makes good multiple bonds.

C–C > Si–Si > Ge–Ge > Sn–Sn · C–C ≈ 348 kJ/mol

Heavier Group 14 atoms cannot form effective pπ–pπ multiple bonds.

  • Catenation order C > Si > Ge > Sn falls as element–element bonds weaken.
  • Carbon forms strong C=C, C≡C and C=O via pπ–pπ overlap.
  • Why CO2 is a gas (O=C=O) but SiO2 is a giant 3D solid (no Si=O).
🧪Compounds9/9

Oxides, Silicates & Silicones

Group 14 oxides shift acidic→amphoteric down the group, and silicon builds networks and polymers.

Acidic: CO2, SiO2 · Amphoteric: GeO2, SnO2, PbO2 · Silicate unit: SiO44⁻ · Silicone: (R2SiO)ₙ

CO is neutral and toxic (binds haemoglobin ~300× stronger than O2); CO2 is acidic, linear.

  • SiO2 is a giant covalent network reacting only with NaOH and HF.
  • Silicates are corner-sharing SiO44⁻ tetrahedra; all four shared gives quartz.
  • Silicones come from hydrolysing R2SiCl2; producer gas = CO + N2, water gas = CO + H2.
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📝 Practice The p-Block Elements (Groups 13 & 14) — 10 NEET PYQs
Real previous-year questions · with answers & solutions
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Q1NEET 2020
Consider the statements: (1) CO₂(g) is used as a refrigerant for ice-cream and frozen food. (2) C₆₀ contains twelve six-carbon rings and twenty five-carbon rings. (3) ZSM-5, a type of zeolite, is used to convert alcohols into gasoline. (4) CO is a colourless and odourless gas. The correct statements are:
Correct answer: C. Statement 1 is wrong — it is solid CO₂ (dry ice), not gaseous CO₂, that refrigerates. Statement 2 is wrong — C₆₀ has 20 six-membered and 12 five-membered rings (not 12 and 25). Statements 3 (ZSM-5 converts alcohols to gasoline) and 4 (CO is colourless and odourless) are correct, so the answer is (3) and (4).
🔎 See the full step-by-step solution in the app →
Q2NEET 2020
Which of the following Group 14 dioxides is amphoteric in nature?
Correct answer: A. Down Group 14 the dioxides change from acidic (CO₂, SiO₂) to amphoteric (SnO₂, PbO₂). SnO₂ reacts with both acids and bases, so it is amphoteric, whereas SiO₂ and CO₂ are acidic and CO is neutral.
🔎 See the full step-by-step solution in the app →
Q3NEET 2018
Which one of the following elements is unable to form an MF₆³⁻ ion?
Correct answer: A. Boron is a second-period element with configuration 1s² 2s² 2p¹ and has no vacant d-orbitals, so it cannot expand its covalence beyond 4 and cannot form BF₆³⁻. Al, Ga and In have empty d-orbitals and can form MF₆³⁻ ions.
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Q4NEET 2016
AlF₃ is soluble in HF only in the presence of KF. This is due to the formation of:
Correct answer: B. Al³⁺ shows a maximum coordination number of 6, so with excess fluoride from KF it forms the hexafluoroaluminate complex: AlF₃ + 3KF arrow K₃[AlF₆]. This complex formation is what makes AlF₃ dissolve in HF when KF is present.
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Q5NEET 2016
Boric acid (H₃BO₃) behaves as an acid because its molecule:
Correct answer: C. H₃BO₃ is a weak monobasic Lewis acid. The electron-deficient boron accepts an OH⁻ from water: B(OH)₃ + 2H₂O arrow [B(OH)₄]⁻ + H₃O⁺. It does not donate its own proton, so option C is the correct description.
🔎 See the full step-by-step solution in the app →
Q6NEET 2015
The stability of the +1 oxidation state among the Group 13 elements Al, Ga, In and Tl increases in the sequence:
Correct answer: B. The inert pair effect strengthens down the group, so the stability of the lower (+1) oxidation state increases from Al to Tl: Al < Ga < In < Tl. Thallium most strongly favours the +1 state.
🔎 See the full step-by-step solution in the app →
Q7NEET 2013
Which of the following structures is similar to that of graphite?
Correct answer: A. Boron nitride (BN)ₓ has a layered hexagonal sheet structure isoelectronic with and structurally analogous to graphite (B and N together supply the same electron count as two carbons), so it is often called ‘inorganic graphite’.
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Q8NEET 2007
The most characteristic oxidation states of lead and tin, respectively, are:
Correct answer: B. Because the inert pair effect strengthens down the group, lead (heavier) favours +2 while tin (lighter) is stable in +4. Hence the characteristic states are Pb: +2 and Sn: +4, i.e. +2, +4 respectively.
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Q9NEET 2006
Anhydrous AlCl₃ is prepared on a large scale by:
Correct answer: C. Anhydrous AlCl₃ cannot be made by simply heating the hydrate (it hydrolyses). It is obtained by heating a mixture of Al₂O₃ and carbon (coke) in dry chlorine: Al₂O₃ + 3C + 3Cl₂ arrow 2AlCl₃ + 3CO. Carbon removes oxygen as CO, driving the reaction.
🔎 See the full step-by-step solution in the app →
Q10NEET 1999
The percentage of lead present in a lead pencil is:
Correct answer: A. A ‘lead’ pencil contains no lead at all — its core is graphite (a carbon allotrope) mixed with clay. The name is historical, so the percentage of lead is zero.
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Frequently Asked Questions

What is the inert pair effect?

The inert pair effect is the reluctance of the outer ns2 electron pair to take part in bonding for heavier p-block elements, so the lower oxidation state becomes more stable down the group. This is why Tl plus is more stable than Tl 3 plus in Group 13 and Pb 2 plus is more stable than Pb 4 plus in Group 14.

Why is diborane (B2H6) called an electron-deficient molecule?

Diborane has only 12 valence electrons but would need 16 to form eight ordinary two-centre B-H bonds, so it is electron deficient. It uses two three-centre two-electron bonds (banana bonds) where one electron pair bridges three atoms in a B-H-B bridge, alongside four normal terminal B-H bonds.

Is the p-Block Groups 13 and 14 chapter important for NEET?

Yes, it is a high-yield part of inorganic chemistry and almost always contributes questions to NEET. Common favourites are the inert pair effect, diborane and boric acid, properties of aluminium and AlCl3, and carbon group trends like catenation and oxide acidity.

What is the difference between graphite and diamond?

In diamond each carbon is sp3 hybridised in a rigid 3D tetrahedral network, making it the hardest natural substance and an electrical insulator. In graphite each carbon is sp2 in layered hexagonal sheets with delocalised electrons, so it conducts electricity and acts as a lubricant, and it is the thermodynamically most stable allotrope of carbon.

Why is orthoboric acid (H3BO3) a weak monobasic acid?

Orthoboric acid does not donate its own protons; instead it acts as a Lewis acid by accepting a hydroxide ion from water, B(OH)3 plus 2H2O gives [B(OH)4] minus plus H3O plus, releasing only one H3O plus. Because it supplies just one hydronium ion and does so weakly, it is classed as a weak monobasic acid.

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