Coordination Compounds Class 12 Notes - CBSE Chemistry Chapter 9

Chapter summary

Coordination Compounds covers complexes in which a central metal ion is bonded to surrounding ligands inside a coordination sphere, explained through Werner’s theory, ligand denticity, IUPAC naming, oxidation states, and isomerism. It then builds the bonding picture with Valence Bond Theory and Crystal Field Theory to predict geometry, magnetic behaviour, and colour. It is one of the highest weightage inorganic chapters in NEET, typically worth 2 to 3 marks every year and heavy on naming, isomer counting, and spin or magnetic moment problems.

Chapter notes

Table of Contents

Key Concepts

1. What Is a Coordination Compound?

Take a bottle of copper sulphate and add ammonia. The pale blue solution turns deep royal blue because a new species, [Cu(NH₃)₃]²⁺, has formed. That coloured ion is a coordination compound - a compound in which a central metal atom or ion is bonded to a fixed number of surrounding ions or molecules by coordinate (dative) bonds.

These molecules or ions do not lose their identity even in solution. That is the key difference from a double salt. A double salt such as Mohr's salt, FeSO₄·(NH₄)₂SO₄·6H₂O, breaks up completely into all its ions in water (Fe²⁺, NH₄⁺, SO₄²⁻). A complex salt such as K₄[Fe(CN)₆] gives K⁺ and the intact complex ion [Fe(CN)₆]⁴⁻, which does not give the test for Fe²⁺ or CN⁻ ions.

Coordination compounds are everywhere: the haemoglobin that carries oxygen in your blood, the chlorophyll that lets plants make food, and the medicines and catalysts used in industry are all complexes.

2. Werner's Coordination Theory

Alfred Werner (Nobel Prize, 1913) was the first to explain the bonding and shapes of these compounds. His main ideas are still used today.

  • Metals show two kinds of valency. The primary valency is ionisable and is satisfied by negative ions - it is basically the oxidation state of the metal. The secondary valency is non-ionisable and is satisfied by ligands - it is the coordination number.
  • The primary valency is non-directional, but the secondary valency is directional: it fixes the geometry (shape) of the complex.
  • Every metal tries to satisfy both its primary and its secondary valencies.

For example, in CoCl₃·6NH₃ (that is, [Co(NH₃)₆]Cl₃), cobalt has a primary valency of 3 (satisfied by three Cl⁻) and a secondary valency of 6 (satisfied by six NH₃ ligands). All three chloride ions are ionisable, so adding AgNO₃ precipitates all three as AgCl. In CoCl₃·5NH₃ ([Co(NH₃)₅Cl]Cl₂), only two chlorides are ionisable, so only two are precipitated - exactly as Werner predicted.

3. Important Terms You Must Know

  • Central atom / ion: the metal atom or ion (usually a transition metal) to which the ligands are bonded, for example Fe²⁺ in [Fe(CN)₆]⁴⁻. It behaves as a Lewis acid (electron-pair acceptor).
  • Ligand: the ion or molecule bound to the central atom. It has at least one lone pair to donate, so it is a Lewis base (for example NH₃, H₂O, Cl⁻, CN⁻).
  • Donor atom: the exact atom of the ligand that donates the lone pair (the N in NH₃, the C in CN⁻).
  • Coordination number (CN): the number of donor atoms directly bonded to the central metal - that is, the number of coordinate bonds. In [PtCl₆]²⁻ the CN is 6; in [Ni(CN)₄]²⁻ it is 4. Note: for a bidentate ligand each donor atom counts separately, so [Co(en)₃]³⁺ has CN 6, not 3.
  • Coordination sphere: the central metal plus its ligands, written together inside square brackets. Everything inside the bracket is non-ionisable; the counter ions written outside are ionisable.
  • Coordination polyhedron: the spatial shape formed by the ligands around the metal (octahedral, tetrahedral, square planar, and so on).
  • Oxidation number of the metal: the charge the central atom would carry if all ligands were removed with their lone pairs. In K₄[Fe(CN)₆], iron is +2.

4. Ligands and Their Denticity

Ligands are classified by how many donor atoms they use to grip the metal - this is called denticity.

  • Monodentate: one donor atom (Cl⁻, H₂O, NH₃, CN⁻, CO).
  • Bidentate: two donor atoms, for example ethane-1,2-diamine (en, two N atoms) and oxalate (ox, two O atoms).
  • Polydentate: several donor atoms. EDTA⁴⁻ is hexadentate - it grips the metal with two N and four O atoms.
  • Chelate ligand: a bi- or polydentate ligand that forms a ring with the metal (a chelate). Chelate rings make a complex much more stable - the chelate effect.
  • Ambidentate ligand: a monodentate ligand that can bind through either of two different donor atoms, for example NO₂⁻ (through N as nitro, or through O as nitrito) and SCN⁻ (through S as thiocyanato, or through N as isothiocyanato).

Ligands are also classified by charge: neutral (H₂O, NH₃, CO), anionic (Cl⁻, CN⁻, OH⁻), or cationic (NO⁺, nitrosonium).

LigandFormulaDenticityCharge
AquaH₂OMonodentateNeutral
AmmineNH₃MonodentateNeutral
CarbonylCOMonodentateNeutral
ChloridoCl⁻MonodentateAnionic
CyanidoCN⁻Monodentate (ambidentate)Anionic
Ethane-1,2-diamine (en)H₂N-CH₂-CH₂-NH₂BidentateNeutral
Oxalato (ox)C₂O₄²⁻BidentateAnionic
EDTA(OOCCH₂)₂N(CH₂)₂N(CH₂COO)₂⁴⁻HexadentateAnionic

5. Coordination Number and Shape

The coordination number decides the shape of the complex. The three shapes you must know for the board and NEET are shown below.

LLLLLLMOctahedralCN 6 · 90°LLLLMTetrahedralCN 4 · 109.5°LLLLMSquare planarCN 4 · 90°
The three most common shapes in coordination chemistry. The pink M is the central metal ion and the purple L are the donor atoms of the ligands. Coordination number 6 is octahedral; CN 4 can be tetrahedral or square planar.
  • CN 2 → linear, for example [Ag(NH₃)₂]⁺ and [CuCl₂]⁻.
  • CN 4 → tetrahedral or square planar. Tetrahedral: [NiCl₄]²⁻, [Ni(CO)₄]. Square planar: [Ni(CN)₄]²⁻, [Pt(NH₃)₂Cl₂]. Square planar is common for d⁸ metals such as Ni²⁺, Pd²⁺, Pt²⁺.
  • CN 6 → octahedral, the most common of all, for example [Co(NH₃)₆]³⁺ and [Fe(CN)₆]⁴⁻.

6. IUPAC Nomenclature of Coordination Compounds

Naming complexes looks scary but follows a short set of rules. Learn the rules once and you can name any complex.

  • Cation is named first, then the anion - just like any ionic compound.
  • Within the complex ion, ligands are named first (in alphabetical order), then the metal.
  • Anionic ligands end in ‑o (chlorido, cyanido, hydroxido, oxalato); neutral ligands keep their name, with special names aqua (H₂O), ammine (NH₃), carbonyl (CO) and nitrosyl (NO).
  • The number of each ligand is shown by di-, tri-, tetra- for simple ligands, and by bis-, tris-, tetrakis- for ligands that already contain a prefix (like ethane-1,2-diamine → bis(ethane-1,2-diamine)).
  • The oxidation state of the metal is written in Roman numerals in brackets right after its name.
  • If the complex ion is an anion, the metal name ends in ‑ate (ferrate, cuprate, cobaltate, argentate, plumbate).
FormulaIUPAC name
[Co(NH₃)₆]Cl₃Hexaamminecobalt(III) chloride
[Cr(H₂O)₆]Cl₃Hexaaquachromium(III) chloride
[Co(NH₃)₅Cl]Cl₂Pentaamminechloridocobalt(III) chloride
K₄[Fe(CN)₆]Potassium hexacyanidoferrate(II)
K₃[Fe(CN)₆]Potassium hexacyanidoferrate(III)
[Ni(CO)₄]Tetracarbonylnickel(0)
[Pt(NH₃)₂Cl₂]Diamminedichloridoplatinum(II)
K₂[PtCl₆]Potassium hexachloridoplatinate(IV)

7. Isomerism in Coordination Compounds

Two complexes can have the same formula yet a different arrangement of atoms - they are isomers. Isomerism is split into structural isomerism (different bonds) and stereoisomerism (same bonds, different arrangement in space).

TypeWhat differsExample
Ionisation (structural)Ion inside vs outside the coordination sphere swap places[Co(NH₃)₅SO₄]Br and [Co(NH₃)₅Br]SO₄
Hydrate / solvate (structural)Water inside the sphere vs water of crystallisation[Cr(H₂O)₆]Cl₃ and [Cr(H₂O)₅Cl]Cl₂·H₂O
Linkage (structural)An ambidentate ligand binds through a different donor atom[Co(NH₃)₅(NO₂)]²⁺ (nitro, N-bonded) vs [Co(NH₃)₅(ONO)]²⁺ (nitrito, O-bonded)
Coordination (structural)Ligands are swapped between a complex cation and a complex anion[Co(NH₃)₆][Cr(CN)₆] vs [Cr(NH₃)₆][Co(CN)₆]
Geometrical (stereo)cis vs trans arrangement of ligandscis- and trans-[Pt(NH₃)₂Cl₂]
Optical (stereo)Non-superimposable mirror images (d and l forms)d- and l-[Co(en)₃]³⁺

Geometrical isomerism is shown by square planar MA₂B₂ complexes and by octahedral complexes. In the cis form the like ligands are next to each other; in the trans form they are opposite.

ClNH₃NH₃ClPtcistwo Cl adjacent (90°)ClClNH₃NH₃Pttranstwo Cl opposite (180°)
Geometrical isomerism in a square planar MA₂B₂ complex, using cisplatin [Pt(NH₃)₂Cl₂]. In the cis form the two Cl ligands sit next to each other (90°); in the trans form they sit opposite (180°). Only cis-platin is an anti-cancer drug.

This is not just theory. The cis isomer of [Pt(NH₃)₂Cl₂], called cisplatin, is a powerful anti-cancer drug, while the trans isomer is medically useless. The shape decides the biology.

Optical isomerism appears when a complex has no plane of symmetry, so it exists as two mirror-image forms that rotate plane-polarised light in opposite directions. Complexes with bidentate ligands such as [Co(en)₃]³⁺ and cis-[Co(en)₂Cl₂]⁺ are classic optical isomers.

8. Valence Bond Theory (VBT) and Hybridisation

Linus Pauling's Valence Bond Theory explains bonding as follows: the ligand lone pairs are donated into empty hybrid orbitals of the metal ion. The type of hybridisation fixes the geometry.

Coordination numberHybridisationGeometry
2spLinear
4sp³Tetrahedral
4dsp²Square planar
5sp³dTrigonal bipyramidal
6d²sp³ (inner orbital)Octahedral
6sp³d² (outer orbital)Octahedral

For octahedral complexes there are two possibilities:

  • Inner-orbital (low-spin) complex: a strong-field ligand forces the d electrons to pair up, freeing inner (n−1)d orbitals. Hybridisation is d²sp³. Fewer unpaired electrons → usually diamagnetic or weakly paramagnetic. Example: [Co(NH₃)₆]³⁺ is d²sp³, diamagnetic.
  • Outer-orbital (high-spin) complex: a weak-field ligand does not pair the electrons, so the metal uses outer nd orbitals. Hybridisation is sp³d². More unpaired electrons → more paramagnetic. Example: [CoF₆]³⁻ is sp³d², paramagnetic (4 unpaired electrons).

Similarly, for CN 4: [Ni(CN)₄]²⁻ is dsp² (square planar, diamagnetic), while [NiCl₄]²⁻ is sp³ (tetrahedral, paramagnetic). Magnetic moment µ = √[n(n+2)] BM, where n is the number of unpaired electrons, lets you predict or check these structures.

VBT has limits: it explains geometry and magnetism but does not explain the colour of complexes or give a quantitative order of ligand strength. For that we need Crystal Field Theory.

9. Crystal Field Theory (CFT)

Crystal Field Theory treats the metal-ligand bond as purely electrostatic (ionic). The ligands are seen as point negative charges that repel the metal's d electrons. In a free metal ion the five d orbitals are degenerate (equal energy), but when ligands approach, the d orbitals that point towards the ligands are raised in energy more than those that point between them. The d orbitals therefore split.

Energy →free ionbarycentreegd(x²−y²), d(z²)+0.6 Δₒt2gd(xy), d(yz), d(xz)−0.4 ΔₒΔₒOctahedral fieldt2eΔₜTetrahedral fieldΔₜ ≈ 4/9 Δₒ
Crystal field splitting. In an octahedral field the five d orbitals split into a lower t2g set (3 orbitals) and a higher eg set (2 orbitals) separated by the crystal field splitting energy Δₒ. In a tetrahedral field the order is inverted and the split (Δₜ) is only about 4/9 of Δₒ.

In an octahedral field the d orbitals split into a lower set of three (t2g: dₓₙ, dₙₔ, dₓₔ type) and an upper set of two (eg: dₓ²−ₙ², dₔ² type). The energy gap is the crystal field splitting energy, Δₒ. The t2g set is lowered by 0.4Δₒ and the eg set is raised by 0.6Δₒ relative to the average (barycentre). In a tetrahedral field the order is reversed (e lower, t2 higher) and the split is smaller, Δₜ ≈ (4/9)Δₒ, so tetrahedral complexes are almost always high spin.

The size of Δₒ depends on the ligand. Arranging ligands by increasing field strength gives the spectrochemical series:

I⁻ < Br⁻ < Cl⁻ < F⁻ < OH⁻ < C₂O₄²⁻ < H₂O < NH₃ < en < NO₂⁻ < CN⁻ < CO

  • Weak-field ligands (I⁻, Br⁻, Cl⁻, F⁻, H₂O) give a small Δₒ. If Δₒ is less than the electron pairing energy P, electrons stay unpaired and spread into eg → high-spin complex.
  • Strong-field ligands (CN⁻, CO, NH₃, en) give a large Δₒ. If Δₒ is greater than P, electrons pair up in the lower t2g set before filling eg → low-spin complex.

Origin of colour: most transition-metal complexes are coloured because of a d-d transition. When white light falls on the complex, an electron in the t2g set absorbs the exact energy Δₒ and jumps to the eg set. The colour we see is the complementary colour of the light absorbed. This is why [Ti(H₂O)₆]³⁺ is purple. Complexes of ions with no d electrons (Sc³⁺, d⁰) or a full d subshell (Zn²⁺, d¹⁰) cannot undergo a d-d transition and are colourless.

10. Stability of Coordination Compounds

The stability of a complex in solution is measured by its stability constant (formation constant), K₌. A large K₌ means the complex forms readily and does not fall apart. Stability rises with:

  • a higher charge and smaller size of the central metal ion (greater charge density);
  • a higher basicity (donor strength) of the ligand - CN⁻ and NH₃ form more stable complexes than Cl⁻ or H₂O;
  • the chelate effect - complexes with chelating (bidentate/polydentate) ligands such as en and EDTA are far more stable than those with the same number of monodentate ligands.

11. Importance and Applications

  • In biology: haemoglobin (an iron-porphyrin complex) carries oxygen in blood; chlorophyll (a magnesium complex) drives photosynthesis; vitamin B₁₂ is a cobalt complex.
  • In medicine: cisplatin and related platinum complexes treat cancer; EDTA is used to treat lead poisoning by chelating the Pb²⁺ ions.
  • In metallurgy: silver and gold are extracted as their cyanido complexes [Ag(CN)₂]⁻ and [Au(CN)₂]⁻; nickel is purified through [Ni(CO)₄] in the Mond process.
  • In analysis: EDTA is used to estimate the hardness of water (Ca²⁺ and Mg²⁺); many metal ions are detected as coloured complexes.
  • In industry: Wilkinson's catalyst and many other complexes speed up important reactions; complexes are used in electroplating, dyes and photography.

Weightage in Board & Entrance Exams

ExamTypical WeightageMost-Tested Areas
CBSE Board (Class 12)5–7 marksIUPAC naming, isomerism, VBT hybridisation & magnetism, Werner's theory
NEET1–2 questionsHybridisation & geometry, CFT (high/low spin, colour), spectrochemical series, EAN
JEE Main / Advanced2–3 questionsIsomer counting, CFSE calculations, magnetic moment, nomenclature

Important Definitions

  • Coordination compound: a compound in which a central metal is bonded to ligands by coordinate bonds and which retains its identity in solution.
  • Ligand: an ion or molecule with a lone pair that binds to the central metal (a Lewis base).
  • Coordination number: the number of donor atoms directly bonded to the central metal.
  • Chelate: a ring complex formed when a bidentate or polydentate ligand binds the same metal.
  • Ambidentate ligand: a monodentate ligand that can attach through either of two different donor atoms (e.g. NO₂⁻, SCN⁻).
  • Crystal field splitting energy (Δ): the energy gap between the split d-orbital sets in a complex.
  • Spectrochemical series: ligands arranged in order of increasing crystal field strength.
  • Stability constant (K₌): the equilibrium constant for the formation of a complex from the metal ion and its ligands.

Solved Examples

Example 1

Q. Write the IUPAC name of K₃[Fe(CN)₆] and give the oxidation state and coordination number of iron.

A. The complex ion is an anion, so iron becomes ferrate. Six cyanido ligands and three K⁺ outside mean the ion is [Fe(CN)₆]³⁻, so iron is +3. Name: Potassium hexacyanidoferrate(III). Coordination number = 6.

Example 2

Q. [Co(NH₃)₆]³⁺ is diamagnetic while [CoF₆]³⁻ is paramagnetic. Explain using VBT.

A. Co³⁺ is d⁶. NH₃ is a strong-field ligand, so it pairs the electrons, freeing two inner 3d orbitals → d²sp³ (inner orbital), no unpaired electrons → diamagnetic. F⁻ is a weak-field ligand, so it cannot pair them; the metal uses outer 4d orbitals → sp³d² (outer orbital) with 4 unpaired electrons → paramagnetic.

Example 3

Q. Calculate the spin-only magnetic moment of [NiCl₄]²⁻.

A. Ni²⁺ is d⁸. Cl⁻ is a weak-field ligand giving a tetrahedral sp³ complex with 2 unpaired electrons. µ = √[n(n+2)] = √[2(2+2)] = √8 = 2.83 BM.

Example 4

Q. How many ionisable chloride ions are present in [Co(NH₃)₅Cl]Cl₂, and how many moles of AgCl will 1 mole of it give with excess AgNO₃?

A. Only the two Cl⁻ outside the square bracket are ionisable; the one inside is bonded to cobalt. So it gives 2 moles of AgCl.

Example 5

Q. Why is [Ti(H₂O)₆]³⁺ coloured but [Sc(H₂O)₆]³⁺ colourless?

A. Ti³⁺ is d¹: its single d electron can absorb light and undergo a t2g → eg (d-d) transition, so the complex is purple. Sc³⁺ is d⁰: it has no d electron to promote, so no d-d transition and no colour.

Example 6

Q. Give one example each of linkage, ionisation and coordination isomerism.

A. Linkage: [Co(NH₃)₅(NO₂)]²⁺ vs [Co(NH₃)₅(ONO)]²⁺. Ionisation: [Co(NH₃)₅SO₄]Br vs [Co(NH₃)₅Br]SO₄. Coordination: [Co(NH₃)₆][Cr(CN)₆] vs [Cr(NH₃)₆][Co(CN)₆].

Important Questions for Board Exams

1-Mark Questions (VSA)

  • What is a ligand? Give one example of a bidentate ligand.
  • Define coordination number. State the CN of cobalt in [Co(en)₃]³⁺.
  • What is an ambidentate ligand? Give one example.
  • Why is [Zn(NH₃)₄]²⁺ colourless?

2–3-Mark Questions (SA)

  • State the postulates of Werner's coordination theory.
  • Write the IUPAC names of [Cr(H₂O)₆]Cl₃ and [Pt(NH₃)₂Cl₂].
  • Explain the difference between a double salt and a complex salt with one example each.
  • Using VBT, explain why [Ni(CN)₄]²⁻ is square planar and diamagnetic while [NiCl₄]²⁻ is tetrahedral and paramagnetic.

5-Mark Questions (LA)

  • Discuss crystal field splitting in octahedral complexes. Explain high-spin and low-spin complexes using the spectrochemical series.
  • Describe the types of isomerism shown by coordination compounds with one example of each.
  • What is the crystal field theory explanation for the colour of transition-metal complexes?

Quick Revision Points

  • Complex salts keep their identity in solution (K₄[Fe(CN)₆]); double salts break up fully (Mohr's salt).
  • Werner: primary valency = oxidation state (ionisable); secondary valency = coordination number (directional, fixes shape).
  • Coordination number counts donor atoms; a bidentate ligand contributes 2 (so [Co(en)₃]³⁺ has CN 6).
  • Naming: ligands alphabetically then metal; anionic complex → metal name ends in ‑ate; oxidation state in Roman numerals.
  • Structural isomers: ionisation, hydrate, linkage, coordination. Stereoisomers: geometrical (cis/trans) and optical (d/l).
  • VBT: d²sp³ = inner orbital / low spin; sp³d² = outer orbital / high spin; dsp² = square planar; sp³ = tetrahedral.
  • µ = √[n(n+2)] BM gives the spin-only magnetic moment from the number of unpaired electrons.
  • CFT: octahedral splits d into lower t2g and upper eg by Δₒ (t2g −0.4Δₒ, eg +0.6Δₒ); tetrahedral is inverted, Δₜ ≈ 4/9 Δₒ.
  • Spectrochemical series (weak → strong): I⁻ < Br⁻ < Cl⁻ < F⁻ < H₂O < NH₃ < en < CN⁻ < CO. Strong field → low spin.
  • Colour comes from a d-d transition; d⁰ and d¹⁰ ions are colourless.
  • Chelate complexes (en, EDTA) are extra stable - the chelate effect. Haemoglobin (Fe) and chlorophyll (Mg) are natural complexes.
🃏 Flash Cards: Coordination Compounds

Class 12 Chemistry – swipe through all 9 cards to understand the whole chapter.

🧲Start here1/9

Werner’s Theory & Basic Terms

A central metal ion gripped by ligands inside square brackets is a coordination compound.

[Co(NH3)6]Cl3 : Co3⁺ · 6 NH3 · CN = 6 · 3 Cl⁻ outside

Two valencies: primary = ionisable = oxidation state; secondary = fixed/directional = coordination number.

  • Coordination number = donor atoms sigma-bonded to the metal (count atoms, not molecules)
  • Coordination sphere = metal + ligands inside [ ]; it reacts as one unit
  • Only counter ions OUTSIDE [ ] ionise and precipitate with AgNO3
🦀Core idea2/9

Ligands & Denticity

A ligand donates a lone pair; denticity counts how many donor atoms one ligand uses.

mono (Cl⁻, NH3) · bi (en, C2O42⁻) · hexadentate (EDTA4⁻) · ambidentate (NO2⁻, SCN⁻)

A chelating ligand must be at least bidentate; CO & CN⁻ bind through one atom only → monodentate.

  • Chelate effect: ring-forming ligands give extra (entropy-driven) stability; more rings → more stable
  • Ambidentate ligands (NO2⁻ via N or O, SCN⁻ via S or N) cause linkage isomerism
  • Denticity sets CN: 3 en in [Co(en)3]3⁺ give CN = 6, not 3
🏷️Key skill3/9

IUPAC Nomenclature

Name cation then anion; inside the complex list ligands alphabetically, then the metal.

K4[Fe(CN)6] → potassium hexacyanidoferrate(II)

Anionic ligands end in -o (chlorido, cyanido); neutral: aqua, ammine (double m), carbonyl, nitrosyl.

  • Use di/tri/tetra normally; bis/tris/tetrakis for en, EDTA (ligand in brackets)
  • Anionic complex → metal takes -ate suffix (ferrate, cuprate, argentate, plumbate)
  • Oxidation state in Roman numerals right after the metal name
🧮Must know4/9

Finding Oxidation State

The charge on the complex equals the metal’s oxidation state plus the sum of ligand charges.

charge on complex = (metal OS) + Σ(ligand charges)

Neutral ligands (NH3, H2O, CO) add 0; sign the anionic charges correctly (oxalate = −2).

  • K4[Fe(CN)6]: complex = −4, 6 CN⁻ = −6 → Fe = +2
  • [Co(NH3)5Cl]Cl2: inner Cl = −1, complex = +2 → Co = +3
  • Complex charge is NOT the metal charge alone — add all ligand charges
🔀High yield5/9

Structural Isomerism

Same formula, different bonds — an ion or atom is connected in a different place.

ionisation · hydrate · linkage · coordination

Linkage isomerism needs an ambidentate ligand; ionisation needs an ion that swaps inside/outside.

  • Ionisation: [Co(NH3)5Br]SO4 vs [Co(NH3)5SO4]Br (different ions in solution)
  • Hydrate: [Cr(H2O)6]Cl3 vs [Cr(H2O)5Cl]Cl2·H2O (different free Cl⁻)
  • Linkage: nitro (–NO2, via N) vs nitrito (–ONO, via O)
🪞High yield6/9

Stereoisomerism

Same bonds, different arrangement in space — geometrical (cis/trans) and optical.

cis/trans: square planar & octahedral · optical: [Co(en)3]3⁺ chiral

Tetrahedral complexes show NO cis–trans; optical activity needs no plane and no centre of symmetry.

  • Geometrical: cis = adjacent, trans = opposite (square planar MA2B2, octahedral MA4B2)
  • Optical: non-superimposable mirror images — cis-[CoCl2(en)2]⁺ active, trans inactive
  • Octahedral [Ma3b3] gives fac (one face) and mer (meridian) isomers
🔗Bonding theory7/9

Valence Bond Theory & Hybridisation

The metal supplies empty hybrid orbitals that accept ligand lone pairs; hybridisation fixes the geometry.

octahedral d2sp3 (inner) / sp3d2 (outer) · square planar dsp2 · tetrahedral sp3

Strong-field ligands (CO, CN⁻, NH3) → inner/low spin; weak-field (H2O, F⁻, Cl⁻) → outer/high spin.

  • Inner orbital (d2sp3) uses inner (n−1)d → low spin, fewer/zero unpaired e⁻
  • Strong-field d8 (Ni2⁺, Pt2⁺) go square planar dsp2, not tetrahedral
  • [Ni(CO)4]: Ni in 0 state → sp3, tetrahedral, diamagnetic
🧭Key formula8/9

Magnetic Moment (Spin-Only)

The number of unpaired electrons sets the magnetic moment of a complex.

μ = √(n(n+2)) BM (n = unpaired electrons)

n = 0 → diamagnetic; plug in only UNPAIRED electrons, never the total.

  • [Fe(CN)6]3⁻: Fe3⁺ d5, CN⁻ strong → low spin, n = 1 → μ ≈ 1.73 BM
  • [FeF6]3⁻: Fe3⁺ d5, F⁻ weak → high spin, n = 5 → μ ≈ 5.92 BM
  • Same metal & oxidation state can give opposite spin — the ligand decides
🌈Advanced9/9

Crystal Field Theory: Splitting, Colour, Magnetism

Ligands approaching electrostatically split the five d-orbitals into two energy sets.

octahedral: t2g (−0.4Δ0) < e_g (+0.6Δ0) · tetrahedral Δ_t = (4/9)Δ0

CFSE = [n(t2g)·(−0.4) + n(e_g)·(+0.6)] Δ0; Δ_t is too small to pair → tetrahedral almost always high spin.

  • Spectrochemical series: I⁻2O32⁻
  • Strong field (large Δ0 > pairing energy) → low spin; weak field → high spin
  • Colour from d–d jump (t2g→e_g); observed = complement of absorbed; d0 & d10 are colourless
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📝 Practice Coordination Compounds — 10 NEET PYQs
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Q1NEET 2021
The ethylenediaminetetraacetate (EDTA) ion is a:
Correct answer: A. EDTA⁴⁻ binds through its two amine nitrogen atoms and four carboxylate oxygen atoms, a total of six donor atoms — it is hexadentate (4 O + 2 N).
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Q2NEET 2021
Match the complexes with their spin-only magnetic moments: A) [Fe(CN)₆]³⁻, B) [Fe(H₂O)₆]³⁺, C) [Fe(CN)₆]⁴⁻, D) [Fe(H₂O)₆]²⁺ with 1) 5.92 BM, 2) 0 BM, 3) 4.90 BM, 4) 1.73 BM.
Correct answer: D. A: Fe³⁺ d⁵ + strong CN⁻ → 1 unpaired → 1.73 BM (4). B: Fe³⁺ d⁵ + weak H₂O → 5 unpaired → 5.92 BM (1). C: Fe²⁺ d⁶ + strong CN⁻ → 0 unpaired → 0 BM (2). D: Fe²⁺ d⁶ + weak H₂O → 4 unpaired → 4.90 BM (3). So A→4, B→1, C→2, D→3.
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Q3NEET 2018
The type of isomerism shown by the complex [CoCl₂(en)₂] is:
Correct answer: C. [CoCl₂(en)₂] is an octahedral M(AA)₂B₂ complex (en bidentate, Cl monodentate). The two Cl can be adjacent (cis) or opposite (trans), so it shows geometrical (cis–trans) isomerism.
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Q4NEET 2018
Iron carbonyl, Fe(CO)₅, is:
Correct answer: B. Fe(CO)₅ contains a single iron atom, so it is a mononuclear carbonyl. (Nuclearity = number of metal atoms; e.g. Fe₂(CO)₉ is dinuclear, Fe₃(CO)₁₂ is trinuclear.)
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Q5NEET 2017
The correct order of the number of moles of AgCl formed when excess AgNO₃ is treated with the complexes CoCl₃·6NH₃, CoCl₃·5NH₃ and CoCl₃·4NH₃ respectively is:
Correct answer: C. These are [Co(NH₃)₆]Cl₃ (3 free Cl⁻ → 3 AgCl), [Co(NH₃)₅Cl]Cl₂ (2 free Cl⁻ → 2 AgCl) and [Co(NH₃)₄Cl₂]Cl (1 free Cl⁻ → 1 AgCl). Only the counter ions outside the sphere precipitate. Order: 3, 2, 1.
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Q6NEET 2016
Which of the following has the longest C–O bond length? (Free C–O bond length in CO is 1.128 Å.)
Correct answer: B. More negative charge on the metal carbonyl means more metal→CO π back-donation into the CO π* orbital, which weakens (lengthens) the C–O bond while strengthening the M–C bond. The most negative species, [Fe(CO)₄]²⁻, has the greatest back-bonding and hence the longest C–O bond.
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Q7NEET 2015
The sum of the coordination number and the oxidation number of the metal M in the complex [M(en)₂(C₂O₄)]Cl (en = ethylenediamine) is:
Correct answer: A. en is neutral bidentate and oxalate (C₂O₄²⁻) is bidentate. Coordination number = 2(en) × 2 + 2(oxalate) = 6. Oxidation state: x + 2(0) + (−2) = +1 (one Cl⁻ outside) ⟹ x = +3. Sum = 6 + 3 = 9.
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Q8NEET 2015
Cobalt(III) chloride forms several octahedral complexes with ammonia. Which of the following will NOT give a test for chloride ions with silver nitrate at 25°C?
Correct answer: A. Only chloride OUTSIDE the coordination sphere ionises and precipitates with AgNO₃. CoCl₃·3NH₃ is [Co(NH₃)₃Cl₃] — all three Cl⁻ are coordinated (inside the sphere) and none ionise, so it gives no test for free Cl⁻. (·4NH₃ gives 1, ·5NH₃ gives 2, ·6NH₃ gives 3 AgCl.)
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Q9NEET 2015
The IUPAC name of the complex ion [Fe(CN)₆]³⁻ is:
Correct answer: D. Six cyanido ligands (CN⁻) → ‘hexacyanido’. The complex is an anion, so the metal takes the -ate suffix (ferrate). Fe is +3 (x + 6(−1) = −3 ⟹ x = +3). Name: hexacyanidoferrate(III) ion.
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Q10NEET 2014
Which one of the following is used as an anticancer agent?
Correct answer: B. cis-[PtCl₂(NH₃)₂] (cisplatin) is the well-known anticancer (antitumour) drug. Only the cis geometrical isomer is active; transplatin is not.
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Frequently Asked Questions

What is a coordination compound?

A coordination compound is a species in which a central metal atom or ion is bonded to surrounding ions or molecules called ligands, written inside square brackets as the coordination sphere, for example [Co(NH3)6]Cl3. According to Werner the metal shows a primary valency equal to its oxidation state and a secondary valency equal to its coordination number.

How do I find the oxidation state of the metal in a complex?

The charge on the whole complex ion equals the oxidation state of the metal plus the sum of all ligand charges, so metal oxidation state equals complex charge minus the sum of ligand charges. For example in K4[Fe(CN)6] the complex is minus 4 and six cyanide ligands give minus 6, so iron is plus 2; neutral ligands like NH3, H2O, and CO contribute zero.

How is the magnetic moment of a complex calculated?

Use the spin-only formula, magnetic moment equals the square root of n times (n plus 2) in Bohr magnetons, where n is the number of unpaired electrons. The ligand decides n through the spectrochemical series, so [Fe(CN)6] cubed minus is low spin with n equal to 1 (about 1.73 BM) while [FeF6] cubed minus is high spin with n equal to 5 (about 5.92 BM).

What is the difference between structural isomerism and stereoisomerism here?

Structural isomers have the same formula but different bonds or connectivity, such as ionisation, hydrate, linkage, and coordination isomerism. Stereoisomers have the same bonds but a different arrangement in space, namely geometrical (cis and trans) and optical (non-superimposable mirror image) isomers.

Is Coordination Compounds important for NEET and how much weightage does it carry?

Yes, it is part of the NEET Class 12 inorganic chemistry syllabus and is one of the most scoring chapters, usually contributing around 2 to 3 questions every year. High yield areas are IUPAC naming, finding oxidation state, counting isomers, and predicting hybridisation, spin, and colour using VBT and Crystal Field Theory.

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