General Principles of Isolation of Elements Class 12 Notes - CBSE Chemistry Chapter 6

Chapter summary

This chapter covers metallurgy, the science of extracting pure metals from their ores through a common four-step pipeline of concentration, conversion to oxide, reduction and refining. It builds the core vocabulary (mineral, ore, gangue, flux, slag), the methods for each step, and the thermodynamic reasoning behind reduction using the Ellingham diagram. It matters for NEET because it blends pure-recall ore formulae with concept-based questions on calcination versus roasting, reducing agents and refining techniques that appear almost every year.

Chapter notes
🃏 Flash Cards: General Principles and Processes of Isolation of Elements

Class 12 Chemistry – swipe through all 9 cards to understand the whole chapter.

⛏️Start here1/9

The Metallurgy Pipeline

Every metal extraction, whatever the ore, follows the same four-step route.

Concentration → Conversion to oxide → Reduction → Refining

The more reactive the metal, the more energy-intensive (usually electrical) its extraction.

  • Unreactive metals (Au, Pt) occur native; reactive ones stay trapped as compounds
  • Oxides are the easiest form to reduce, so ores are turned into oxides first
  • Memorising this sequence organises the whole chapter
🪨Core terms2/9

Minerals, Ores, Gangue, Flux, Slag

Five words unlock the chapter; an ore is a mineral that pays.

flux + gangue → slag

Every ore is a mineral (TRUE); every mineral is an ore (FALSE).

  • Mineral = any natural form of a metal; Ore = mineral extractable profitably & conveniently
  • Gangue = earthy impurity; Flux added on purpose to form fusible slag
  • Acidic gangue (SiO2) needs basic flux (CaO); CaO + SiO2 → CaSiO3 (slag)
📒Must recall3/9

Important Ores

Pure-recall ore formulae that NEET asks directly.

Bauxite Al2O3·xH2O · Haematite Fe2O3 · Chalcopyrite CuFeS2 · Zinc blende ZnS

Cryolite Na3AlF6 is a flux/solvent, NOT the ore of Al.

  • Iron: Haematite Fe2O3, Magnetite Fe3O4
  • Zinc: Zinc blende ZnS, Calamine ZnCO3; Silver: Argentite Ag2S
  • Watch lookalikes: Cu2S (copper glance) vs CuFeS2 (chalcopyrite)
🪣Step 14/9

Concentration of Ores

Remove gangue by exploiting one physical property where ore and gangue differ.

4Au + 8CN⁻ + 2H2O + O2 → 4[Au(CN)2]⁻ + 4OH⁻ (cyanide leaching)

Froth flotation is for sulphide ores ONLY; leaching is the chemical method.

  • Hydraulic washing = density; Magnetic separation = magnetism (Fe3O4, FeWO4)
  • Froth flotation: pine oil + air; sulphides go hydrophobic and rise as froth
  • Depressant NaCN holds ZnS down to separate it from PbS
🔥Step 25/9

Calcination vs Roasting

Convert the concentrated ore to its oxide before reduction.

ZnCO3 → ZnO + CO2 (calcination) · 2ZnS + 3O2 → 2ZnO + 2SO2 (roasting)

Calcination = limited/no air; Roasting = excess air, below melting point.

  • Carbonate/hydrated ore → calcination (drives off CO2 / H2O, no O2 added)
  • Sulphide ore → roasting (excess O2 burns S off as SO2)
  • Both steps end at an oxide, the easiest form to reduce
⚖️Step 36/9

Reduction of the Oxide

Pull oxygen off the oxide using C, CO, or a more reactive metal.

Fe2O3 + 3CO → 2Fe + 3CO2 · Cr2O3 + 2Al → 2Cr + Al2O3 (thermite)

Reduction is feasible only when net ΔG° is negative.

  • Common reducing agents: carbon, carbon monoxide, aluminium (thermite)
  • ZnO + C → Zn + CO is a standard carbon reduction
  • Very reactive metals (Na, Mg, Ca, Al) need electrolysis instead
📉Key principle7/9

Ellingham Diagram

A plot of ΔG° of oxide formation vs temperature that tells you which reductant works.

ΔG° = ΔH° − TΔS°

Gives only thermodynamic feasibility, NOT the rate (kinetics).

  • Metal-oxide lines slope UP (O2 consumed, ΔS negative)
  • C → CO line slopes DOWN, so hot carbon can reduce almost any oxide
  • Lower line (more negative ΔG°) reduces the oxide of the higher line
Special methods8/9

Electrolytic Reduction & Self-Reduction

Reactive metals need electricity; some sulphides reduce themselves.

Al3⁺ + 3e⁻ → Al · 2Cu2O + Cu2S → 6Cu + SO2

Reactive metals are reduced from MOLTEN salts, never aqueous (water reduces first).

  • Hall–Héroult: Al2O3 in molten cryolite (Na3AlF6) lowers m.p. & raises conductivity
  • Carbon anode burns away as CO/CO2; Al collects at the cathode
  • Self-reduction is special to Cu, Pb, Hg sulphides (no external reductant)
🧼Final step9/9

Refining the Crude Metal

Match the metal’s standout property to the right purification method.

Mond: Ni + 4CO → Ni(CO)4 → Ni + 4CO · van Arkel: Ti + 2I2 → TiI4 → Ti + 2I2

Electrolytic refining: impure metal = ANODE, pure metal = CATHODE.

  • Distillation: low-boiling Zn, Hg; Liquation: low-melting Sn, Pb
  • Zone refining gives ultra-pure Si, Ge, Ga (impurities prefer the molten zone)
  • Anode mud collects valuable Ag, Au, Pt during electrolytic refining
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📝 Practice General Principles and Processes of Isolation of Elements — 10 NEET PYQs
Real previous-year questions · with answers & solutions
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Tap an option to check your answer and see the worked solution. Every question is a real NEET previous-year question.
Q1NEET 2021
The maximum temperature that can be achieved in a blast furnace is:
Correct answer: B. In a blast furnace hot air is blown in from the bottom; the bottom region reaches a maximum temperature of about 2200 K. This is enough to reduce iron oxides and can also be used to extract metals like Pb from PbO.
🔎 See the full step-by-step solution in the app →
Q2NEET 2021
Which one of the following methods can be used to obtain a highly pure metal that is liquid at room temperature?
Correct answer: C. The metal liquid at room temperature is mercury. Impure mercury is heated to vaporise it; the vapour is condensed to give pure mercury (distillate), leaving non-volatile impurities behind. So distillation is used.
🔎 See the full step-by-step solution in the app →
Q3NEET 2019
Identify the incorrect statement among the following (metallurgy terms):
Correct answer: D. Gangue (matrix) is the earthy/rocky IMPURITY (sand, clay, rock) associated with an ore, not ‘an ore contaminated with undesired materials’. The ore is the valuable mineral; gangue is what must be removed. The other three statements are correct definitions, so (D) is the incorrect one.
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Q4NEET 2019
Which one of the following is malachite?
Correct answer: C. Malachite is a basic carbonate ore of copper, CuCO₃·Cu(OH)₂. Cu(OH)₂/Cu(OH)₂-based azurite differs, Fe₃O₄ is magnetite (iron), and CuFeS₂ is copper pyrites (chalcopyrite).
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Q5NEET 2018
Considering the Ellingham diagram, which of the following metals can be used to reduce alumina (Al₂O₃)?
Correct answer: A. A metal can reduce alumina only if its own oxide-formation line lies BELOW (more negative ΔG°) that of Al₂O₃. Among the options only Mg forms a more stable oxide than Al at the relevant temperature (MgO line lies below the Al₂O₃ line), so Mg can reduce Al₂O₃. Zn, Fe and Cu have higher (less negative) lines and cannot.
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Q6NEET 2017
Extraction of gold and silver involves leaching the metal with CN⁻ ion. The silver is subsequently recovered from the cyanide complex by:
Correct answer: D. After cyanide leaching the metal is present as a soluble dicyanido complex, e.g. [Ag(CN)₂]⁻. It is recovered by displacement with the more reactive metal zinc: 2[Ag(CN)₂]⁻ + Zn arrow [Zn(CN)₄]²⁻ + 2Ag (Mac-Arthur Forrest cyanide process).
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Q7NEET 2015
In the extraction of copper from its sulphide ore, the metal is finally obtained by the reduction of cuprous oxide (Cu₂O) with:
Correct answer: A. Copper extraction is a self-reduction: part of the Cu₂S is roasted to Cu₂O, then the remaining Cu₂S reduces it: 2Cu₂O + Cu₂S arrow 6Cu + SO₂. So Cu₂O is reduced by Cu₂S (the sulphide is its own reducing agent), not by external C/CO.
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Q8NEET 2013
Roasting of sulphides gives a colourless gas X with a choking smell of burnt sulphur, whose acidic aqueous solution acts as a reducing agent and causes acid rain. Gas X is:
Correct answer: B. Roasting any sulphide ore in air gives sulphur dioxide: 2MS + 3O₂ arrow 2MO + 2SO₂. SO₂ is colourless with a choking smell, its aqueous solution (H₂SO₃) is acidic and reducing, and it contributes to acid rain. Hence X = SO₂.
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Q9NEET 2007
Sulphide ores are usually concentrated by froth flotation. Which one of the following sulphide ores is an EXCEPTION and is concentrated by chemical leaching instead?
Correct answer: D. Sphalerite/zinc blende (ZnS) is concentrated by chemical (cyanide/acid) leaching rather than ordinary froth flotation in this classic question, whereas galena (PbS), copper pyrites (CuFeS₂) and argentite (Ag₂S) are taken as the froth-floated sulphides. Hence the exception is sphalerite.
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Q10NEET 2007
Regarding the advantage of roasting a sulphide ore to its oxide before reduction, which statement is NOT true?
Correct answer: A. Carbon and hydrogen are NOT suitable reducing agents for metal sulphides, because the ΔfG° of CS₂ and H₂S is higher (less favourable) than that of the metal sulphide, so C/H₂ cannot pull sulphur away. That is precisely WHY the sulphide is first roasted to the oxide (a feasible, ΔG°-negative step) and then reduced. Hence statement (A) is the false one.
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Frequently Asked Questions

What is the difference between a mineral and an ore?

A mineral is any naturally occurring form in which a metal is found, while an ore is a mineral from which the metal can be extracted profitably and conveniently. So every ore is a mineral, but not every mineral is an ore.

What is the basic sequence of steps in extracting a metal from its ore?

Metallurgy follows four steps: concentration of the ore to remove gangue, conversion of the concentrated ore to its oxide by calcination or roasting, reduction of the oxide to the metal, and finally refining or purification of the crude metal. The more reactive the metal, the more energy-intensive its extraction, often needing electrolysis.

What is the difference between calcination and roasting?

Calcination is heating an ore in limited or no air to drive off volatile matter like carbon dioxide or water, used mainly for carbonate and hydrated ores. Roasting is heating a sulphide ore in excess air below its melting point so that sulphur is removed as sulphur dioxide; both steps end at the oxide.

What does the Ellingham diagram tell us?

It is a plot of the standard free energy change of oxide formation against temperature, and it tells us which reducing agent can reduce a given oxide. A metal whose line lies lower (more negative free energy) can reduce the oxide of a metal whose line lies above it, but the diagram gives only thermodynamic feasibility and not the rate of reaction.

Is this chapter important for NEET and what type of questions are asked?

Yes, it is part of the NEET inorganic chemistry syllabus and usually contributes one or two questions. Expect direct recall of ore names and formulae, comparisons such as calcination versus roasting, choice of reducing agent, and the Hall and Heroult process for aluminium.

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