Biomolecules Class 12 Notes - CBSE Chemistry Chapter 14 (Free PDF)

Chapter summary

Biomolecules studies the chemistry of the molecules of life: carbohydrates, proteins and amino acids, enzymes and vitamins, nucleic acids, hormones and lipids. You learn how glucose and fructose are built, how sugars link through glycosidic bonds, how amino acids fold into proteins, and how DNA and RNA store genetic information. It is a high-yield, fact-dense NEET chapter that rewards memory of structures, reducing or non-reducing sugars, vitamin deficiencies and base pairing.

Chapter notes
🃏 Flash Cards: Biomolecules

Class 12 Chemistry · Chapter 14 – swipe through all 10 cards to understand the whole chapter.

🍚Start here1/10

Carbohydrates: Classification

Carbohydrates are optically active polyhydroxy aldehydes or ketones (or yield them on hydrolysis).

Cₓ(H2O)ᵧ · aldose (–CHO) vs ketose (C=O)

The Cₓ(H2O)ᵧ rule is loose — sugars like rhamnose break it.

  • Mono- (glucose), oligo-/di- (sucrose), poly- (starch) by hydrolysis
  • Sugars = sweet, soluble; non-sugars = polysaccharides, insoluble
  • Glucose = aldohexose, fructose = ketohexose
🔬Core structure2/10

Glucose & Fructose Structure

Classic chemical tests fix glucose as a straight-chain D-(+)-aldohexose, C6H12O6.

Br2 water → gluconic acid (mono) · HNO3 → saccharic acid (di)

Pentaacetate ⇒ 5 –OH; HI → n-hexane ⇒ straight 6-C chain; 1 HCN ⇒ one –CHO.

  • Fructose = ketohexose at C-2 but still a reducing sugar
  • Glucose closes to a 6-ring pyranose; fructose to a 5-ring furanose
  • C-1 –OH (anomeric C) α (down) or β (up) → two anomers
🔄Key effect3/10

Mutarotation

Pure α- and β-glucose slowly interconvert through the open chain to a fixed rotation.

α +111° ⇌ open chain ⇌ β +19.2° → settles +52.7°

Rotation changes, molecular formula does not; equilibrium ≈ 36% α, 64% β.

  • Anomers differ only at the anomeric C-1, not at C-4 (that’s an epimer)
  • 0.36(111) + 0.64(19.2) ≈ 52° matches observed +52.7°
  • Caused by ring repeatedly opening and re-closing
🔗Core process4/10

Di- & Polysaccharides

A glycosidic linkage (C–O–C, loss of water) joins sugars; the α/β angle decides digestibility.

Sucrose = α-glucose + β-fructose (C1–C2) → non-reducing

Sucrose hydrolysis → invert sugar; rotation flips +66.5° → −39.7°.

  • Maltose (2 α-glucose, C1–C4) & lactose (β-gal + glucose) are reducing
  • Starch = amylose (linear α-1,4) + amylopectin (branched α-1,4 & α-1,6)
  • α-links = digestible storage; β-1,4 = tough structural cellulose
🧬Core building block5/10

Amino Acids & the Zwitterion

α-Amino acids carry –NH2 and –COOH on the same carbon and exist as dipolar ions.

H3N⁺–CHR–COO⁻ (zwitterion) · net charge = 0 at pI

Essential ones (valine, leucine, lysine) come from diet; rest are non-essential.

  • Zwitterion ⇒ high melting, water-soluble, salt-like
  • All except glycine are optically active (chiral α-carbon)
  • Peptide bond = amide link –CO–NH– between two amino acids
🧶Key structure6/10

Four Levels of Protein Structure

A protein’s function comes from how its amino-acid chain folds.

Primary → Secondary (α-helix / β-sheet) → Tertiary → Quaternary

Denaturation breaks secondary/tertiary structure; primary sequence stays intact.

  • Secondary held by H-bonds; tertiary adds –S–S– disulphide bridges
  • Quaternary = ≥2 subunits, e.g. haemoglobin (4 chains)
  • Egg white / curdled milk = denaturation in action
⚙️Key facts7/10

Enzymes & Vitamins

Enzymes are protein biocatalysts; vitamins are trace micronutrients you must eat.

Fat-soluble = A, D, E, K (stored) · Water-soluble = B-complex, C

B12 is the water-soluble vitamin that IS stored (in the liver).

  • Enzymes = globular proteins, lock-and-key, names end in -ase
  • Maltase→maltose, invertase→sucrose, zymase→glucose to ethanol
  • C→scurvy, A→night blindness, D→rickets, K→poor clotting
🧪Core polymer8/10

Nucleic Acids (DNA & RNA)

Nucleic acids are polymers of nucleotides that store and transfer genetic information.

Nucleoside = sugar + base · Nucleotide = sugar + base + phosphate

Backbone = 3′–5′ phosphodiester bonds; strands held by H-bonds.

  • DNA: deoxyribose + thymine; RNA: ribose + uracil
  • Purines A, G (2 rings); pyrimidines C, T, U (1 ring)
  • Pairing A=T (2 H-bonds), G≡C (3 H-bonds); strands antiparallel
📊Exam tool9/10

Chargaff’s Rule

In double-stranded DNA each base pairs with its complement, so percentages are linked.

%A = %T , %G = %C → %G = (100 − (%A + %T)) / 2

Use only for double-stranded DNA, not single-stranded RNA.

  • If %A = 30, then %T = 30, so %G = %C = 20
  • G≡C-rich DNA is more stable (3 H-bonds, needs more heat)
  • Know one strand ⇒ you can write the complementary strand
💊Biological roles10/10

Hormones, Lipids & Metabolism

Hormones are chemical messengers; lipids build membranes; metabolism runs on hydrolysis and glycolysis.

Insulin ↓ glucose (glucose→glycogen) · glucagon/adrenaline ↑ glucose

Thyroxine = the iodine-containing hormone; Co in B12, Fe in haemoglobin, Mg in chlorophyll.

  • Steroid (testosterone), peptide (insulin), amine (adrenaline, thyroxine)
  • Phospholipid = glycerol + 2 fatty acids + 1 phosphate → cell membranes
  • Glycolysis: glucose → 2 pyruvate (+ATP); digestion = hydrolysis
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📝 Practice Biomolecules — 10 NEET PYQs
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Q1NEET 2020
The reaction of concentrated sulphuric acid with a carbohydrate such as sucrose (C₁₂H₂₂O₁₁), which leaves a black mass of carbon, is an example of:
Correct answer: A. Concentrated H₂SO₄ is a powerful dehydrating agent: it removes the elements of water from the carbohydrate, C₁₂H₂₂O₁₁ arrow 12 C + 11 H₂O, leaving a charred black mass of carbon. No change in oxidation state of carbon is required, so it is dehydration, not oxidation/reduction or sulphonation.
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Q2NEET 2020
Which one of the following is a basic amino acid?
Correct answer: C. An amino acid is basic when its side chain carries an extra –NH (more amino than carboxyl groups). Lysine, H₂N–(CH)–CH(NH)–COOH, has two amino groups against one –COOH, so it is basic. Alanine and serine are neutral; tyrosine is essentially neutral (phenolic). Hence lysine.
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Q3NEET 2020
Deficiency of which vitamin causes osteomalacia?
Correct answer: B. Vitamin D deficiency causes rickets in children and osteomalacia (softening of bones) in adults. Vitamin A deficiency arrow xerophthalmia/night blindness, vitamin E arrow fragility of RBCs/muscle weakness, vitamin K arrow increased clotting time. Hence vitamin D.
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Q4NEET 2020
Which one of the following statements is NOT true about glucose?
Correct answer: D. Glucose (C₆H₁₂O₆) is a six-carbon aldose, i.e. an aldohexose — not an aldopentose (5 carbons). It has five –OH groups (shown by pentaacetate formation), a free –CHO that makes it a reducing sugar. Hence the false statement is that it is an aldopentose.
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Q5NEET 2018
The difference between amylose and amylopectin is that:
Correct answer: C. Amylose is a long unbranched chain of α-D-glucose units joined only by C₁C₄ (α-1,4) glycosidic bonds. Amylopectin is branched: α-1,4 links along the chain plus α-1,6 links at the branch points. Both are all-glucose (no galactose), and all the storage links are α, not β.
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Q6NEET 2016
The correct statement regarding the sugar component in RNA and DNA respectively is:
Correct answer: A. RNA contains the sugar ribose (with an –OH at C-2′), whereas DNA contains 2′-deoxyribose (an H instead of –OH at C-2′). Arabinose is not a nucleic-acid sugar. Hence ribose in RNA and 2′-deoxyribose in DNA.
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Q7NEET 2014
Which hormone is produced under stress and stimulates glycogenolysis in the liver of human beings?
Correct answer: C. Adrenaline (epinephrine) is the stress hormone; it raises pulse rate and stimulates glycogenolysis, releasing glucose from liver glycogen for an emergency energy supply. Insulin lowers blood sugar, thyroxine sets metabolic rate, and estradiol is a sex steroid. Hence adrenaline.
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Q8NEET 2012
Which one of the following sets of monosaccharides forms sucrose?
Correct answer: B. Sucrose is built from α-D-glucopyranose and β-D-fructofuranose joined by an α,β-1,2 glycosidic linkage between C-1 of glucose and C-2 of fructose. Glucose adopts the six-membered pyranose ring and fructose the five-membered furanose ring.
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Q9NEET 2004
The number of chiral (asymmetric) carbon atoms in β-D-(+)-glucose (open-chain form) is:
Correct answer: D. Open-chain glucose, OHC–CHOH–CHOH–CHOH–CHOH–CHOH, has carbons C-1 (–CHO) and C-6 (–CHOH) that are not chiral. The four middle carbons C-2, C-3, C-4 and C-5 each bear four different groups and are asymmetric. Hence there are four chiral carbons.
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Q10NEET 2000
α-D-(+)-glucose and β-D-(+)-glucose are best described as:
Correct answer: A. Diastereomers that differ only in the configuration at the anomeric carbon (C-1) are called anomers. Epimers differ at a carbon other than the anomeric one; enantiomers are non-superimposable mirror images; geometrical (cis/trans) isomerism needs a C=C or ring restricting rotation. So α– and β-D-glucose are anomers.
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Frequently Asked Questions

What are biomolecules in chemistry?

Biomolecules are the organic molecules that make up and run living cells, mainly carbohydrates, proteins, nucleic acids, lipids, enzymes, vitamins and hormones. In Class 12 Chemistry the chapter focuses on their structure, classification and biological roles.

What is a zwitterion and why are amino acids high melting?

An amino acid carries an acidic –COOH and a basic –NH2 group on the same carbon, so a proton shifts to form a dipolar ion called a zwitterion, written as H3N+ –CHR–COO-. This salt-like ionic nature makes amino acids high melting and water soluble, and at the isoelectric point (pI) the net charge is zero.

What is the difference between a reducing and a non-reducing sugar?

A reducing sugar has a free aldehyde or ketone (free anomeric –OH) and can reduce Tollens or Fehling reagent, like glucose, fructose, maltose and lactose. Sucrose is non-reducing because both anomeric carbons are locked in the glycosidic linkage between glucose and fructose.

What is mutarotation of glucose?

Mutarotation is the slow change in optical rotation when pure alpha-D-glucose (+111 degrees) or beta-D-glucose (+19.2 degrees) is dissolved in water, until both reach an equilibrium rotation of about +52.7 degrees. It happens because the cyclic ring keeps opening to the open chain and re-closing, interconverting the two anomers.

Is Biomolecules an important chapter for NEET?

Yes, Biomolecules is part of the NEET Class 12 Chemistry syllabus and is a scoring chapter because most questions are direct and memory based. Commonly tested points are reducing or non-reducing sugars, vitamin deficiency diseases, DNA versus RNA, base pairing and types of hormones.

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