Principles of Inheritance and Variation Class 12 Notes - CBSE Biology Chapter 5

Chapter summary

Principles of Inheritance and Variation explains how traits pass from parents to offspring, starting with Mendel’s laws of dominance, segregation and independent assortment in pea plants. It then covers deviations like incomplete dominance, codominance, multiple alleles (ABO blood groups), gene interactions, linkage and recombination, sex determination, and human genetic disorders. It is a high-yield Class 12 genetics chapter that delivers several direct NEET questions every year and underpins the chapters on molecular genetics and evolution.

Chapter notes

Table of Contents

Key Concepts

1. Mendel and the Garden Pea

Gregor Mendel worked on the garden pea (Pisum sativum) for seven years and gave the first scientific laws of inheritance. The pea was a smart choice: it has clear contrasting traits, is naturally self-pollinating, has a short life cycle, and produces many offspring, so ratios could be counted reliably.

He studied seven pairs of contrasting characters (for example tall vs dwarf plants, round vs wrinkled seeds, yellow vs green seeds, violet vs white flowers). Before results make sense, fix these terms:

  • Gene: a unit of inheritance controlling a character. Allele: one of the alternative forms of a gene (T for tall, t for dwarf).
  • Genotype: the genetic make-up (TT, Tt, tt). Phenotype: the visible trait (tall or dwarf).
  • Homozygous: identical alleles (TT or tt). Heterozygous: different alleles (Tt).
  • Dominant allele expresses in the heterozygote (T); the masked recessive allele (t) shows only when homozygous.

2. Monohybrid Cross and Mendel's First Two Laws

A monohybrid cross follows a single character. Crossing pure tall (TT) with pure dwarf (tt) gives an all-tall F₁ (Tt). Selfing the F₁ gives an F₂ in a 3 tall : 1 dwarf phenotypic ratio and a 1 TT : 2 Tt : 1 tt genotypic ratio.

TtTtTTTtTttt
Monohybrid cross Tt × Tt gives a 1:2:1 genotypic ratio and a 3:1 phenotypic ratio (3 tall : 1 dwarf).

Law of Dominance: in a heterozygote, one allele (dominant) expresses and masks the other (recessive). Law of Segregation (Law of Purity of Gametes): the two alleles of a pair separate during gamete formation, so each gamete carries only one allele. This law has no exception.

Test cross: to find whether a tall plant is TT or Tt, cross it with a recessive dwarf (tt). All tall offspring means TT; a 1:1 tall:dwarf ratio means the parent was Tt. A back cross is a cross of the F₁ with either parent.

3. Incomplete Dominance and Codominance

Incomplete dominance: the heterozygote shows an intermediate phenotype. In snapdragon (Antirrhinum) and the 4 o'clock plant, red (RR) × white (rr) gives pink (Rr). The F₂ ratio is 1 red : 2 pink : 1 white, so here the phenotypic and genotypic ratios are the same (1:2:1).

Codominance: both alleles express fully and independently in the heterozygote. Human ABO blood groups show this: allele Iᴬ and Iᵇ are codominant, so genotype IᴬIᵇ gives blood group AB (both A and B antigens appear).

4. ABO Blood Groups (Multiple Alleles)

The ABO gene has three alleles - Iᴬ, Iᵇ and i - a case of multiple allelism. Iᴬ and Iᵇ are dominant over i and codominant with each other.

Blood group (phenotype)Possible genotypesAntigen on RBC
AIᴬIᴬ, IᴬiA
BIᵇIᵇ, IᵇiB
ABIᴬIᵇA and B
Oiinone

5. Dihybrid Cross and the Law of Independent Assortment

A dihybrid cross follows two characters together, for example seed shape (round R dominant over wrinkled r) and colour (yellow Y dominant over green y). Crossing RRYY × rryy gives round-yellow F₁ (RrYy). Selfing gives an F₂ phenotypic ratio of 9 round-yellow : 3 round-green : 3 wrinkled-yellow : 1 wrinkled-green (9:3:3:1).

RYRYRyRyrYrYryryRRYYRRYyRrYYRrYyRRYyRRyyRrYyRryyRrYYRrYyrrYYrrYyRrYyRryyrrYyrryy
Dihybrid cross (RrYy × RrYy). The 16 boxes give the classic 9:3:3:1 phenotypic ratio; purple = both dominant traits, pink = one dominant trait, white = both recessive.

Law of Independent Assortment: during gamete formation the alleles of one gene pair segregate independently of another gene pair. This holds only for genes on different chromosomes (unlinked genes).

6. Epistasis, Pleiotropy and Polygenic Inheritance

  • Epistasis: one gene masks the expression of another gene at a different locus (for example coat colour in Labradors; recessive epistasis can change the 9:3:3:1 ratio to 9:3:4).
  • Pleiotropy: a single gene affects multiple traits. In sickle cell anaemia one mutated gene affects RBC shape, anaemia, spleen and more; in phenylketonuria one gene affects mental development and pigment.
  • Polygenic inheritance: a trait controlled by many genes, each adding a small effect, giving a continuous range. Examples are human skin colour and height; the phenotype also depends on the environment.

7. Linkage and Recombination

Thomas Hunt Morgan, working on Drosophila, found that genes on the same chromosome tend to be inherited together and do not assort independently - this is linkage. Linked genes give far fewer recombinant types than expected.

The exchange of segments between homologous chromosomes during meiosis is crossing over, which produces recombinants. Genes that are close together are tightly linked (low recombination); genes far apart recombine more. Recombination frequency is used to map genes on a chromosome.

8. Chromosomal Theory and Sex Determination

Sutton and Boveri's chromosomal theory of inheritance linked Mendel's factors to chromosome behaviour during meiosis. Sex is decided by sex chromosomes:

  • XX-XY (humans, Drosophila): female XX, male XY. Males are heterogametic.
  • XX-XO (grasshopper): female XX, male XO (one X, no Y).
  • ZZ-ZW (birds): male ZZ, female ZW. Here the female is heterogametic.
  • Haplodiploidy (honeybee): females (diploid) develop from fertilised eggs, males (haploid drones) from unfertilised eggs by parthenogenesis.
Mother XXFather XYXXYXX – Girl (50%)XY – Boy (50%)The father's sperm (X or Y) decides the child's sex.
Human sex determination is XX-XY. Females are XX (homogametic), males are XY (heterogametic).

9. Pedigree Analysis

A pedigree is a family tree that tracks a trait across generations. Squares are males, circles are females, and filled symbols are affected individuals. Pedigrees help predict whether a trait is dominant or recessive and whether it is autosomal or sex-linked.

unaffectedcarrieraffected
A typical autosomal-recessive pedigree: two unaffected carriers can have an affected child (1 in 4 risk). Squares are males, circles are females.

Clues: an autosomal recessive trait can skip generations and appears in both sexes equally; an X-linked recessive trait (haemophilia, colour blindness) is far more common in males because they have a single X.

10. Mendelian and Chromosomal Disorders

Mendelian disorders arise from a change in a single gene and follow Mendelian inheritance.

DisorderTypeKey point
HaemophiliaX-linked recessiveBlood fails to clot; mostly affects males
Colour blindnessX-linked recessiveCannot distinguish red and green
Sickle cell anaemiaAutosomal recessiveHbS due to Glu→Val at position 6 of the β-globin chain
ThalassemiaAutosomal recessiveReduced synthesis of globin chains
PhenylketonuriaAutosomal recessiveLacks enzyme to convert phenylalanine; causes mental retardation

Chromosomal disorders arise from an extra or missing chromosome (aneuploidy), usually from non-disjunction during meiosis.

DisorderChromosome changeKey features
Down syndromeTrisomy 21 (extra 21)Short stature, mental retardation, small round head
Klinefelter syndrome47, XXY (extra X in males)Male with some feminine features, usually sterile
Turner syndrome45, X0 (one X missing)Sterile female, short stature, underdeveloped ovaries

Weightage in Board & Entrance Exams

ExamTypical WeightageMost-Tested Areas
CBSE Board (Class 12)6–8 marksDihybrid ratio, pedigree problems, sex determination, blood groups
NEET2–3 questionsMendelian disorders, linkage, pedigree, incomplete dominance vs codominance
Genetics numericalsHigh frequencyRatios from crosses, probability of offspring, test cross outcomes

Important Definitions

  • Allele: an alternative form of a gene.
  • Test cross: a cross of an organism showing the dominant trait with a homozygous recessive to reveal its genotype.
  • Codominance: both alleles express fully in the heterozygote (blood group AB).
  • Pleiotropy: a single gene controlling several phenotypic traits.
  • Aneuploidy: gain or loss of one or more chromosomes due to non-disjunction.
  • Recombination: the formation of new allele combinations through crossing over.

Solved Examples

Example 1

Q. A tall pea plant is crossed with a dwarf. The offspring are 50% tall and 50% dwarf. What is the genotype of the tall parent?

A. A 1:1 ratio is the result of a test cross, so the tall parent is heterozygous Tt (Tt × tt gives 1 Tt : 1 tt).

Example 2

Q. In snapdragon, red (RR) is crossed with white (rr). Give the F₁ and F₂ phenotypic ratios.

A. This is incomplete dominance. F₁ is all pink (Rr). F₂ is 1 red : 2 pink : 1 white.

Example 3

Q. A man of blood group AB marries a woman of blood group O. What blood groups can the children have?

A. IᴬIᵇ × ii gives Iᴬi (group A) and Iᵇi (group B). Children can be A or B, never AB or O.

Example 4

Q. A colour-blind man marries a normal homozygous woman. Describe the children.

A. Colour blindness is X-linked recessive. XᶜY × XᶜXᶜ (using Xᶜ = normal): all daughters are carriers, all sons are normal. No child is colour-blind.

Example 5

Q. What phenotypic ratio is expected in the F₂ of a dihybrid cross of two independently assorting genes?

A. 9:3:3:1. It comes from combining two independent 3:1 monohybrid ratios (3:1 × 3:1).

Important Questions for Board Exams

1-Mark Questions (VSA)

  • Define codominance with one example.
  • Why is the pea plant suitable for genetic studies? Give one reason.
  • What is a test cross?

2–3-Mark Questions (SA)

  • Differentiate between incomplete dominance and codominance with examples.
  • Explain the Law of Segregation and why it is called the law of purity of gametes.
  • How is sex determined in honeybees?

5-Mark Questions (LA)

  • Work out a dihybrid cross and explain the Law of Independent Assortment with a Punnett square.
  • Describe the inheritance and symptoms of any two Mendelian disorders in humans.

Quick Revision Points

  • Monohybrid F₂: 3:1 phenotype, 1:2:1 genotype. Dihybrid F₂: 9:3:3:1.
  • Law of Segregation has no exception; Law of Independent Assortment applies only to unlinked genes.
  • Incomplete dominance gives 1:2:1 phenotype; codominance shows both alleles (blood group AB).
  • ABO blood group is an example of multiple alleles and codominance.
  • Linked genes are inherited together; crossing over produces recombinants.
  • Humans are XX-XY; the sperm decides sex. Birds are ZZ-ZW; honeybees use haplodiploidy.
  • Down = trisomy 21, Klinefelter = XXY, Turner = X0. Haemophilia and colour blindness are X-linked recessive.
🃏 Flash Cards: Principles of Inheritance and Variation

Class 12 Biology · Botany – swipe through all 9 cards to understand the whole chapter.

🌱Start here1/9

Mendel & the Garden Pea

Genetics began with Gregor Mendel tracking how traits pass from parents to offspring in pea plants.

Pisum sativum · 7 pairs of contrasting traits · true-breeding lines

Pea chosen for easy self/cross-pollination and a short life cycle.

  • Allele = an alternative form of a gene
  • Homozygous (TT/tt) vs heterozygous (Tt)
  • Dominant allele masks the recessive one in a heterozygote
🔢Core laws2/9

Monohybrid Cross & First Two Laws

A one-character cross (Tall TT × dwarf tt) gives all-tall F1, and selfing reveals Mendel’s laws.

F2 phenotype 3:1 · F2 genotype 1:2:1

Law of Dominance + Law of Segregation (purity of gametes).

  • Dominance: only the dominant allele shows in a heterozygote
  • Segregation: the two alleles separate, so each gamete gets only one
  • Alleles do not blend or contaminate each other
🟡Two characters3/9

Dihybrid Cross & Independent Assortment

Following two characters at once gives the classic 9:3:3:1 F2 ratio.

F2 = 9:3:3:1 · gamete types = 2ⁿ · test cross = 1:1:1:1

9:3:3:1 is just (3:1) × (3:1) — each gene still 3:1.

  • RrYy makes 4 gamete types: RY, Ry, rY, ry (equal)
  • Independent assortment: one gene pair sorts independent of another
  • RrYy × rryy test cross gives a 1:1:1:1 ratio
🌸Beyond dominance4/9

Incomplete Dominance & Codominance

Some heterozygotes are intermediate, or show both alleles together — breaking simple dominance.

Incomplete dom → 1:2:1 (RR red × rr white = Rr pink)

Antirrhinum/Mirabilis pink; here F2 phenotype ratio = genotype ratio.

  • Incomplete dominance: heterozygote is intermediate (pink)
  • Codominance: both alleles fully expressed → blood group AB
  • Codominant ABO alleles: Iᴬ and Iᴮ
🩸Multiple alleles5/9

ABO Blood Groups

One gene can have more than two alleles in a population, though each person carries only two.

Alleles Iᴬ, Iᴮ, i · Iᴬ & Iᴮ dominant over i

Gene codes a sugar-adding enzyme on the RBC surface.

  • Group A = Iᴬ Iᴬ or Iᴬ i; Group B = Iᴮ Iᴮ or Iᴮ i
  • Group AB = Iᴬ Iᴮ (codominance); Group O = ii
  • Iᴬ vs i shows complete dominance, Iᴬ vs Iᴮ shows codominance
🔗Gene interactions6/9

Epistasis, Pleiotropy & Polygeny

Genes interact, modifying the classic Mendelian ratios in three distinct ways.

Epistasis: 12:3:1 · 9:3:4 · duplicate dominant 15:1

Epistatic gene masks; hypostatic gene is masked.

  • Pleiotropy: one gene affects many traits (e.g. PKU)
  • Polygeny: many genes add up → continuous variation (skin colour)
  • Each affects the 9:3:3:1 dihybrid ratio differently
🧬Same chromosome7/9

Linkage & Recombination

Genes on the same chromosome tend to be inherited together, violating independent assortment.

Map distance (cM) = (recombinants / total) × 100

1% recombination = 1 centimorgan (1 map unit); Morgan in Drosophila.

  • Tightly linked genes → low recombination; loosely linked → high
  • Recombination comes from crossing over in meiosis I
  • Chromosomal Theory (Sutton & Boveri): genes lie on chromosomes
Sex determination8/9

How Sex Is Decided

Different organisms use different chromosome systems to determine sex.

XX-XY (human) · XX-XO (grasshopper) · ZZ-ZW (birds)

In humans the father’s sperm (X or Y) decides the child’s sex.

  • Human male is heterogametic (XY), female homogametic (XX)
  • Grasshopper male is XO (one X, no Y)
  • Birds: female is heterogametic (ZW), male is ZZ
🩺Genetic disorders9/9

Mendelian & Chromosomal Disorders

Genetic disorders come from single-gene defects or whole-chromosome number changes.

Sickle-cell: Glu → Val at 6th position of β-globin (HbS)

Down’s, Klinefelter’s, Turner’s arise from non-disjunction.

  • X-linked recessive: haemophilia, colour blindness
  • Autosomal recessive: sickle-cell anaemia, PKU, thalassemia
  • Down’s = trisomy 21 · Klinefelter’s = XXY · Turner’s = XO
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📝 Practice Principles of Inheritance and Variation — 10 NEET PYQs
Real previous-year questions · with answers & solutions
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Tap an option to check your answer and see the worked solution. Every question is a real NEET previous-year question.
Q1NEET 2021
The production of gametes by the parents, and the formation of the zygote, can be understood from a diagram called:
Correct answer: C. A Punnett square (devised by Reginald C. Punnett) is a checker-board that lists all possible gamete combinations of two parents and predicts offspring genotypes/phenotypes. The other three names are fictitious distractors.
🔎 See the full step-by-step solution in the app →
Q2NEET 2021
In a cross between a male and female, both heterozygous for the sickle-cell anaemia gene, what percentage of the progeny will be diseased (suffer from sickle-cell anaemia)?
Correct answer: C. Sickle-cell anaemia is autosomal recessive (HbS HbS). Carrier x carrier (HbA HbS x HbA HbS) gives 1 HbA HbA : 2 HbA HbS : 1 HbS HbS. Only the homozygous HbS HbS (25%) actually suffers the disease.
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Q3NEET 2020
The best example for pleiotropy is:
Correct answer: B. Phenylketonuria is the classic pleiotropic disorder: a single defective gene (phenylalanine hydroxylase deficiency) causes multiple effects – mental retardation plus reduced hair and skin pigmentation. Skin colour is polygenic, not pleiotropic.
🔎 See the full step-by-step solution in the app →
Q4NEET 2020
The chromosomal theory of inheritance was proposed independently around 1902 by which pair of scientists?
Correct answer: A. Walter Sutton and Theodor Boveri independently (around 1902) proposed the chromosomal theory of inheritance, noting that chromosome behaviour during meiosis parallels Mendel’s factors. Morgan later verified it experimentally.
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Q5NEET 2020
How many true-breeding pea plant varieties did Mendel select as pairs, which were similar except for one character with contrasting traits?
Correct answer: B. Mendel studied 7 characters, each with a pair of contrasting true-breeding varieties (e.g. tall and dwarf), so 7 x 2 = 14 true-breeding varieties in total. Don’t confuse this with the 7 characters themselves.
🔎 See the full step-by-step solution in the app →
Q6NEET 2020
When a single gene influences more than one trait, it is called pleiotropy. Which of the following is a correctly matched example?
Correct answer: A. Phenylketonuria is the standard example of pleiotropy (one gene, many effects). Skin colour is polygenic (not epistasis or codominance), so only A is correctly matched.
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Q7NEET 2019
In a marriage between a male with blood group A and a female with blood group B, the progeny had either blood group AB or B. What are the possible genotypes of the parents?
Correct answer: A. Progeny are only AB and B (no A and no O), so the mother must contribute only I^B (she is I^B I^B) and the father must be able to give i (to make B) and I^A (to make AB), i.e. father is I^A i. I^A i x I^B I^B gives I^A I^B (AB) and I^B i (B) only.
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Q8NEET 2019
In Antirrhinum (snapdragon), a red flower was crossed with a white flower and the F1 generation produced pink flowers. When pink flowers were selfed, the F2 showed red, pink and white flowers. The incorrect statement about this is:
Correct answer: C. This is incomplete dominance: F1 is pink (intermediate) and F2 is 1 red : 2 pink : 1 white. The law of SEGREGATION still applies (red and white reappear in F2), so the statement that segregation does not apply is the INCORRECT one.
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Q9NEET 2016
A tall true-breeding garden pea plant is crossed with a dwarf true-breeding garden pea plant. When the F1 plants were selfed, the resulting genotypes in the F2 were in the ratio:
Correct answer: D. TT x tt gives F1 Tt (all tall). Selfing Tt x Tt gives the F2 GENOTYPIC ratio 1 TT : 2 Tt : 1 tt = 1 tall homozygous : 2 tall heterozygous : 1 dwarf. (Options A and D state the same correct genotypic ratio; the keyed option is the genotypic 1:2:1, not the 3:1 phenotypic ratio.)
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Q10NEET 2007
A human male produces sperms with the genotypes AB, Ab, aB and ab pertaining to two diallelic characters in equal proportions. What is the corresponding genotype of this person?
Correct answer: A. Four equally frequent gamete types (AB, Ab, aB, ab) require both gene pairs to be heterozygous, i.e. genotype AaBb (2² = 4 gametes). Any homozygous pair would reduce the number of gamete types.
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Frequently Asked Questions

What is the Law of Segregation in simple terms?

It states that the two alleles of a gene separate during gamete formation so that each gamete carries only one allele of a pair. Because the alleles stay pure and never blend, a recessive trait hidden in the F1 can reappear in the F2 generation.

What are the key Mendelian ratios I must remember?

A monohybrid cross gives an F2 phenotypic ratio of 3:1 and a genotypic ratio of 1:2:1. A dihybrid cross gives a 9:3:3:1 phenotypic ratio, and a test cross of a dihybrid gives 1:1:1:1.

Is Principles of Inheritance and Variation important for NEET?

Yes, it is one of the highest-yield Class 12 Biology chapters and usually contributes around 2 to 4 questions in NEET. Pedigree analysis, blood group genetics, Mendelian ratios and genetic disorders are frequently tested.

What is the difference between incomplete dominance and codominance?

In incomplete dominance the heterozygote shows an intermediate or blended phenotype, such as a pink flower from red and white parents. In codominance both alleles are fully and separately expressed in the heterozygote, as in the AB blood group where both A and B antigens appear.

How is sex determined in humans and who decides the baby’s sex?

Humans follow the XX-XY system where the female is XX (homogametic) and the male is XY (heterogametic). Since the mother always provides an X, it is the father’s sperm carrying either an X or a Y that decides the child’s sex.

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