Classification of Elements and Periodicity in Properties Class 11 Notes | CBSE Chemistry Chapter 3

Chapter summary

This chapter explains how the modern periodic law arranges all elements by atomic number into 7 periods, 18 groups and the s, p, d and f blocks, and how an element’s electronic configuration fixes its exact position. It then tracks the periodic trends that flow from this layout, namely atomic and ionic radii, ionization enthalpy, electron gain enthalpy, electronegativity, valence and the acidic or basic nature of oxides. For NEET it is a high-yield, almost fully fact-and-trend based chapter where most questions test the direction and the common exceptions of these periodic properties.

Chapter notes

Table of Contents


Key Concepts

1. Genesis of Periodic Classification

Long before the modern table, chemists kept trying to group elements with similar properties so the subject would be easier to learn. Each attempt got a little closer to the truth.

  • Döbereiner’s Triads (1829): elements arranged in groups of three where the atomic mass of the middle element was roughly the average of the other two (e.g. Li, Na, K). Failed because very few such triads existed.
  • Newlands’ Law of Octaves (1865): when elements were arranged by increasing atomic mass, every eighth element had properties similar to the first - like the eighth note of a musical octave. Worked only up to calcium.
  • Lothar Meyer (1869): plotted atomic volume against atomic mass and obtained a periodic curve, showing properties repeat at intervals.

2. Mendeleev’s Periodic Law

Dmitri Mendeleev (1869) gave the first widely accepted table. His periodic law states: the physical and chemical properties of elements are a periodic function of their atomic masses.

He arranged 63 known elements in order of increasing atomic mass into horizontal periods and vertical groups of similar elements.

Merits of Mendeleev’s Table

  • He left gaps for undiscovered elements and predicted their properties (eka-aluminium = gallium, eka-silicon = germanium) with remarkable accuracy.
  • He placed elements by property even when it broke the mass order (e.g. he predicted corrected atomic masses).

Defects of Mendeleev’s Table

  • Anomalous pairs: some elements with higher atomic mass came before lower ones (Ar before K; Co before Ni).
  • Position of isotopes could not be explained (same element, different masses).
  • Hydrogen had no fixed position (resembles both Group 1 and Group 17).

3. Modern Periodic Law and Present Form of the Table

Henry Moseley (1913) showed from X-ray studies that atomic number (Z), not atomic mass, is the fundamental property of an element. This corrected all of Mendeleev’s anomalies.

Modern Periodic Law: the physical and chemical properties of elements are a periodic function of their atomic numbers.

Features of the Long Form Table

  • 7 periods (horizontal rows) = number of principal energy shells; period number = value of n for the outermost shell.
  • 18 groups (vertical columns) = elements with the same outer electronic configuration and similar properties.
  • The number of elements in each period (2, 8, 8, 18, 18, 32, 32) is fixed by how many electrons fill the available subshells (2n² rule).

4. Electronic Configuration and Types of Elements (s, p, d, f Blocks)

The table is divided into four blocks based on the subshell into which the last (differentiating) electron enters.

BlockGroupsOuter ConfigurationExamples
s-block1 & 2ns¹⁻²Alkali & alkaline earth metals (Na, Ca)
p-block13–18ns² np¹⁻⁶B, C, N, O, halogens, noble gases
d-block3–12(n−1)d¹⁻¹⁰ ns⁰⁻²Transition metals (Fe, Cu, Zn)
f-blockplaced below(n−2)f¹⁻¹⁴Lanthanoids & actinoids
  • s- and p-block together form the representative (normal) elements.
  • d-block = transition elements; f-block = inner transition elements.
  • Group 18 = noble gases (ns² np⁶, fully filled, very stable).

Tip to locate an element: the period = highest value of n; for s/p-block the group = (outer electrons) or (10 + outer electrons) for p-block; for d-block group = (n−1)d + ns electrons.


5. Atomic and Ionic Radius

Atomic radius is the distance from the centre of the nucleus to the outermost shell of electrons. We use covalent, van der Waals, or metallic radii depending on the bonding.

  • Across a period (left → right): atomic radius decreases, because nuclear charge increases while electrons enter the same shell, pulling them inward.
  • Down a group (top → bottom): atomic radius increases, because a new shell is added in each period.

Ionic Radius

  • A cation is smaller than its parent atom (it loses a shell / has higher effective nuclear charge per electron).
  • An anion is larger than its parent atom (added electrons increase repulsion).
  • Isoelectronic species (same number of electrons): radius decreases as nuclear charge increases. Order: N³⁻ > O²⁻ > F⁻ > Na⁺ > Mg²⁺ > Al³⁺.

6. Ionization Enthalpy (IE)

Ionization enthalpy is the minimum energy required to remove the most loosely bound electron from an isolated gaseous atom in its ground state.

M(g) + IE₁ → M⁺(g) + e⁻

  • Across a period: IE generally increases (nuclear charge rises, size falls).
  • Down a group: IE decreases (size increases, shielding increases).
  • Successive ionization enthalpies always increase: IE₁ < IE₂ < IE₃.

Exceptions (very important for exams): Be has higher IE than B (stable fully filled 2s²), and N has higher IE than O (stable half-filled 2p³ configuration).


7. Electron Gain Enthalpy (ΔₑgH)

Electron gain enthalpy is the energy change when an electron is added to an isolated gaseous atom to form an anion.

X(g) + e⁻ → X⁻(g) + ΔₑgH

  • More negative ΔₑgH means the atom releases more energy and accepts the electron more readily.
  • Across a period: becomes more negative (atoms get smaller, more eager for electrons).
  • Down a group: becomes less negative (size increases).
  • Halogens have the most negative electron gain enthalpies.

Exception: ΔₑgH of chlorine is more negative than fluorine, because F is so small that incoming electrons face high repulsion in its compact 2p shell.


8. Electronegativity

Electronegativity is the tendency of an atom in a molecule to attract the shared pair of electrons towards itself. Unlike IE and ΔₑgH, it is a relative property with no units.

  • Across a period: electronegativity increases (size decreases, nuclear pull increases).
  • Down a group: electronegativity decreases.
  • Fluorine is the most electronegative element (Pauling value 4.0).

Electronegativity decides bond polarity, the metallic/non-metallic character, and the acidic/basic nature of oxides.


9. Valence (Valency)

Valence is the combining capacity of an element, decided by the number of valence electrons.

  • Across a period: valence towards hydrogen rises 1→4 then falls 4→1 (CH₄, NH₃, H₂O, HF).
  • Down a group: valence usually stays constant (same outer configuration).
  • For oxides, the highest valence often equals the group number for representative elements.

10. Periodic Trends in Chemical Properties

The physical trends above translate directly into chemical behaviour.

  • Metallic character increases down a group and decreases across a period (metals lose electrons easily - low IE).
  • Non-metallic character increases across a period and decreases down a group.
  • Nature of oxides: metallic oxides are basic (Na₂O), non-metallic oxides are acidic (SO₃, Cl₂O₇), and oxides of borderline elements are amphoteric (Al₂O₃, ZnO).
  • Reactivity of metals increases down a group; reactivity of non-metals decreases down a group.

[DIAGRAM: A periodic table with arrows - atomic radius and metallic character increasing down/left; ionization enthalpy, electronegativity and non-metallic character increasing up/right towards fluorine.]


11. Diagonal Relationship

Some elements of period 2 resemble the period-3 element placed diagonally to the right (Li–Mg, Be–Al, B–Si). This happens because the diagonal pair has similar charge/size ratios and similar electronegativities.


12. Nomenclature of Elements with Z > 100

To avoid naming disputes for newly synthesised superheavy elements, IUPAC gives a temporary systematic name based on the digits of the atomic number, using numerical roots, with the suffix -ium.

Digit0123456789
Rootnilunbitriquadpenthexseptoctenn
  • Z = 101 → Unnilunium (Unu), Md
  • Z = 104 → Unnilquadium (Unq), Rf
  • Z = 120 → Unbinilium (Ubn)

Rule: write the roots for each digit in order, add -ium, and the symbol is the first letter of each root. If “i” of “bi”/”tri” is followed by “ium”, one “i” is dropped; “enn” + “nil” drops one “n”.


Read the rest of the chapter →Hide the rest ↑

Weightage in Board & Entrance Exams

ExamTypical WeightageMost-Tested Areas
CBSE Board (Class 11)6–8 marksPeriodic trends, IE exceptions, electronic configuration, blocks
JEE Main / Advanced1–2 questionsIsoelectronic radii, IE order, electronegativity, nomenclature
NEET2–3 questionsAtomic/ionic radius, IE & ΔₑgH exceptions, metallic character

[TABLE: Question-type split - VSA (1 mark): definitions, blocks, most electronegative element; SA (2–3 marks): trend reasoning, IE exceptions; LA (5 marks): compare across period/group, predict properties, nomenclature.]


Important Definitions

TermDefinition
Modern periodic lawProperties of elements are a periodic function of their atomic numbers
PeriodHorizontal row; equals the number of the outermost principal shell (n)
GroupVertical column of elements with the same outer electronic configuration
Atomic radiusDistance from the nucleus to the outermost electron shell
Isoelectronic speciesAtoms/ions with the same number of electrons (e.g. O²⁻, F⁻, Na⁺)
Ionization enthalpyEnergy to remove the outermost electron from a gaseous atom
Electron gain enthalpyEnergy change when an electron is added to a gaseous atom
ElectronegativityTendency of an atom to attract a shared electron pair in a bond
Representative elementss- and p-block elements (Groups 1, 2 and 13–18)
Diagonal relationshipSimilarity between an element and the one diagonally right below it

Solved Examples

Example 1

An element has the electronic configuration 1s² 2s² 2p⁶ 3s² 3p³. Identify its block, group, and period.

Answer: Last electron enters the 3p subshell → p-block. Highest n = 3 → Period 3. Outer electrons = 2 + 3 = 5 → group = 10 + 5 = Group 15. The element is phosphorus (Z = 15).

Example 2

Arrange the isoelectronic species N³⁻, O²⁻, F⁻, Na⁺, Mg²⁺ in increasing order of ionic radius.

Answer: All have 10 electrons; radius decreases as nuclear charge rises. Increasing order: Mg²⁺ < Na⁺ < F⁻ < O²⁻ < N³⁻.

Example 3

Why is the first ionization enthalpy of nitrogen greater than that of oxygen?

Answer: Nitrogen has a stable, exactly half-filled 2p³ configuration which is hard to disturb, so removing an electron needs more energy. Oxygen (2p⁴) loses one electron to reach the stable half-filled state, so its IE₁ is lower.

Example 4

The electron gain enthalpy of chlorine is more negative than that of fluorine. Explain.

Answer: Fluorine is very small, so its compact 2p shell causes strong electron–electron repulsion when an extra electron is added, reducing the energy released. Chlorine is larger (3p shell), repulsion is less, so its ΔₑgH is more negative.

Example 5

Which of Be and B has the higher first ionization enthalpy, and why?

Answer: Beryllium. Be has a stable fully filled 2s² configuration, so its outer electron is tightly held. Boron’s single 2p electron is at higher energy and easier to remove, so B has a lower IE₁.

Example 6

Write the IUPAC systematic name and symbol for the element with atomic number 105.

Answer: Digits 1-0-5 → un-nil-pent + ium = Unnilpentium, symbol Unp (now named Dubnium, Db).


Important Questions for Board Exams

1-Mark Questions (VSA)

  1. State the modern periodic law.
  2. Name the most electronegative element in the periodic table.
  3. Which block do transition elements belong to?
  4. Why is the size of a cation smaller than its parent atom?
  5. Write the IUPAC name of the element with Z = 120.

2–3-Mark Questions (SA)

  1. Why does atomic radius decrease across a period but increase down a group? Explain.
  2. Explain why the first ionization enthalpy of N is greater than that of O.
  3. Arrange O²⁻, F⁻, Na⁺, Mg²⁺ in increasing order of size and justify.
  4. Distinguish between ionization enthalpy and electron gain enthalpy with one example each.

5-Mark Questions (LA)

  1. Discuss the variation of atomic radius, ionization enthalpy, electron gain enthalpy, and electronegativity across a period and down a group, with reasons.
  2. What are the defects of Mendeleev’s periodic table, and how does the modern periodic law remove them?
  3. Explain the trend in metallic and non-metallic character and the acidic/basic nature of oxides across period 3.

Quick Revision Points

  • Döbereiner triads → Newlands octaves → Mendeleev (atomic mass) → Modern law (atomic number)
  • Modern periodic law: properties are a periodic function of atomic number Z
  • Long form: 7 periods, 18 groups; period = outermost shell n
  • Blocks: s (Gp 1–2), p (Gp 13–18), d (Gp 3–12, transition), f (inner transition)
  • Atomic radius: decreases across a period, increases down a group
  • Cation < atom < anion; isoelectronic radius falls as nuclear charge rises
  • IE: increases across a period, decreases down a group; exceptions Be > B, N > O
  • ΔₑgH: most negative for halogens; exception Cl more negative than F
  • Electronegativity: increases across a period, decreases down a group; F is highest (4.0)
  • Metallic character ↓ across, ↑ down; oxides: metal = basic, non-metal = acidic, borderline = amphoteric
  • Z > 100 nomenclature: nil-un-bi-tri-quad-pent-hex-sept-oct-enn + ium

Next Chapter: Chapter 4 - Chemical Bonding and Molecular Structure

🃏 Flash Cards: Classification of Elements and Periodicity in Properties

Class 11 Chemistry · Chapter 3 – swipe through all 9 cards to understand the whole chapter.

🧭Start here1/9

The Modern Periodic Law

Element properties repeat in a regular cycle as atomic number rises — that one idea organises the whole chapter.

Properties = periodic function of atomic number (Z)

Mendeleev used atomic MASS; Moseley proved Z is the true key.

  • Z (proton count), not mass, fixes an element’s place
  • Trap: ‘atomic mass’ answer belongs to Mendeleev, not the modern law
  • Moseley used X-ray frequencies: √ν = a(Z − b)
🗂️Table layout2/9

Periods, Groups & Blocks

The long-form table has 7 rows, 18 columns, and 4 blocks named after the subshell being filled.

Period 1→2, 2&3→8, 4&5→18, 6&7→32 elements

f-block (lanthanoids/actinoids) parked below the main table.

  • Period no. = principal shell n; group = similar valence config
  • Blocks = s, p, d, f (last subshell filled)
  • Period 6 has 32 (don’t forget the 14 lanthanoids)
📮Find the address3/9

Configuration → Position

Read an element’s block, group and period straight off its electronic configuration.

p-block group = 10 + (ns + np); d-block group = (n−1)d + ns

Period = highest n; block = subshell getting the last electron.

  • s-block group = number of ns electrons (1 or 2)
  • Cl (…3s23p5): valence 7 → group 10+7 = 17, period 3
  • Don’t count a buried, filled 3d10 as valence — it’s core
📏Master trend4/9

Atomic & Ionic Radii

Size shrinks across a period and grows down a group — and most other trends just follow size.

→ radius ↓ (Zeff ↑) ; ↓ radius ↑ (new shells)

Cation < parent atom; anion > parent atom.

  • Across: same shell + more protons → tighter, smaller
  • Na⁺ < Na (lost a shell); Cl⁻ > Cl (added repulsion)
  • Ga ≈ Al, even slightly smaller (poor 3d shielding)
🟰NEET favourite5/9

Isoelectronic Species

Same electron count, different proton count — more protons squeeze the cloud smaller.

O2⁻ > F⁻ > Na⁺ > Mg2⁺ > Al3⁺ (all 10 e⁻)

Compare PROTONS, not electrons (electrons are equal).

  • Protons: O 8, F 9, Na 11, Mg 12, Al 13
  • Fewer protons → weakest pull → biggest size
  • Reverse the list for increasing order of size
Core property6/9

Ionization Enthalpy

Energy to pull the loosest electron off an isolated gaseous atom — always endothermic.

M(g) → M⁺(g) + e⁻ ; IE1 < IE2 < IE3

Across → IE ↑ (smaller, higher Zeff); down ↓ IE ↓. Units kJ/mol.

  • Dips: B < Be and O < N (half/full-filled stability of Be 2s2, N 2p3)
  • Same dips repeat in period 3: Al < Mg, S < P
  • A sudden big jump in successive IE reveals the group number
🧲Electron hunger7/9

Electron Gain Enthalpy

Enthalpy change when a gaseous atom gains an electron — usually negative (energy released).

X(g) + e⁻ → X⁻(g) ; order Cl > F > Br > I

Noble gases: large POSITIVE values (electron must start a new shell).

  • More negative across a period, less negative down a group
  • Cl beats F: F’s tiny 2p shell crowds the incoming electron
  • Halogens have the most negative ΔegH
🎯Bond pull8/9

Electronegativity

An atom’s tendency, inside a bond, to attract the shared electron pair — a relative, unitless number.

EN: across ↑, down ↓ ; F = 4.0 (highest)

Bigger EN difference → more polar bond (e.g. H–F more polar than H–Cl).

  • Fluorine is the most electronegative element (Pauling 4.0)
  • Rises across (Zeff ↑), falls down a group (bigger atoms)
  • F has highest EN, but Cl has the more negative ΔegH — don’t mix them
🧪Cash it in9/9

Chemical Trends & Oxides

Valence, metallic character and oxide nature all march in periodic step — the most-tested payoff.

Metal oxide → basic · non-metal oxide → acidic · diagonal → amphoteric

Acidic character of oxides increases across a period.

  • Amphoteric oxides: Al2O3, ZnO, BeO (react with acid AND base)
  • Hydride valence (higher p-block) = 8 − outer electrons → N is 3 in NH3
  • Diagonal pairs: Li–Mg, Be–Al, B–Si (similar charge/size ratio)
Swipe Click a card to focus 9 cards
📝 Practice Classification of Elements and Periodicity in Properties — 10 NEET PYQs
Real previous-year questions · with answers & solutions
Start →Close ✕
Tap an option to check your answer and see the worked solution. Every question is a real NEET previous-year question.
Q1NEET 2021
From the following pairs of ions, which one is NOT an iso-electronic pair?
Correct answer: D. Iso-electronic species have equal electron counts. O²⁻=10, F=10 (pair). Na=10, Mg²⁺=10 (pair). Mn²⁺=23, Fe³⁺=23 (pair). But Fe²⁺=24 while Mn²⁺=23, so Fe²⁺ and Mn²⁺ are NOT iso-electronic.
🔎 See the full step-by-step solution in the app →
Q2NEET 2018
The correct order of atomic radii in group 13 elements is:
Correct answer: D. Radii increase down the group, but gallium shows an anomaly: the poorly shielding 3d¹⁰ electrons make Ga smaller than Al. Thus B (85 pm) < Ga (135 pm) < Al (143 pm) < In (167 pm) < Tl (170 pm).
🔎 See the full step-by-step solution in the app →
Q3NEET 2017
The element with atomic number Z = 114 (recently discovered) will belong to which family and have which electronic configuration?
Correct answer: B. Rn has Z=86. Adding 5f¹⁴(14) + 6d¹⁰(10) + 7s²(2) + 7p²(2) = 28 gives Z=114. The outer ns²np² configuration places it in group 14, the carbon family (a p-block element of period 7).
🔎 See the full step-by-step solution in the app →
Q4NEET 2015
The species Ar, K and Ca²⁺ contain the same number of electrons. In which order do their radii increase?
Correct answer: C. All three are iso-electronic with 18 electrons. Nuclear charge: Ar(18) < K(19) < Ca(20). For iso-electronic species, more protons means a smaller radius, so Ca²⁺ < K < Ar.
🔎 See the full step-by-step solution in the app →
Q5NEET 2012
Identify the WRONG statement among the following.
Correct answer: A. For iso-electronic species, a larger positive charge means more protons pulling the same electrons, giving a SMALLER radius. So statement (a) has the relation backwards (smaller positive charge gives a larger, not smaller, radius) and is wrong. (b), (c), (d) are all correct trends.
🔎 See the full step-by-step solution in the app →
Q6NEET 2010
Which of the following represents the correct order of increasing electron gain enthalpy (with negative sign) for the elements O, S, F and Cl?
Correct answer: B. Electron gain enthalpy magnitude generally increases across a period, but second-period O and F have unusually high inter-electronic repulsion in their compact 2p shell, so S > O and Cl > F. The increasing (magnitude) order is O < S < F < Cl.
🔎 See the full step-by-step solution in the app →
Q7NEET 2009
Which one of the elements with the following outer-orbital configurations may exhibit the largest number of oxidation states?
Correct answer: C. The maximum number of oxidation states for a d-block element equals the sum of (n-1)d and ns electrons. (a) 3+2=5; (b) 5+1=6; (c) 5+2=7; (d) 2+2=4. The 3d4s² (manganese) configuration gives 7, the largest.
🔎 See the full step-by-step solution in the app →
Q8NEET 2009
Amongst the elements with the following electronic configurations, which one may have the highest ionisation energy?
Correct answer: A. [Ne]3s²3p³ (phosphorus) has an exactly half-filled 3p subshell, which is extra stable, so removing an electron is hardest. Across a period IE rises and down a group it falls, so the period-3 half-filled 3p³ has the highest IE of these.
🔎 See the full step-by-step solution in the app →
Q9NEET 1996
The element with atomic number 118 will be a/an:
Correct answer: B. Z=118 completes period 7 with outermost configuration 7s²7p (a fully filled valence shell), so it is a noble gas.
🔎 See the full step-by-step solution in the app →
Q10NEET 1993
If the atomic number of an element is 33, it will be placed in the periodic table in the:
Correct answer: C. Z=33 (As) has outer configuration 4s²4p³ = 5 valence electrons, placing it in group VA (the fifth group, old notation), i.e. group 15.
🔎 See the full step-by-step solution in the app →
View 20+ more practice questions, gamified →
Free · no signup · works in your browser
Studying this chapter? Track it - saved on this device, no login.

Frequently Asked Questions

What is the modern periodic law?

The modern periodic law states that the physical and chemical properties of elements are a periodic function of their atomic numbers. This corrected Mendeleev’s earlier law, which was based on atomic mass, after Moseley showed that atomic number (Z), not mass, is the fundamental property of an element.

How do you find an element’s block, group and period from its electronic configuration?

The period equals the highest principal quantum number (n) in the configuration, and the block is the subshell that receives the last electron (s, p, d or f). For groups, an s-block group equals the number of valence electrons, while a p-block group equals 10 plus the number of valence electrons; for example chlorine ending in 3s2 3p5 has 7 valence electrons, so it is group 17, period 3, p-block.

How do atomic radius and ionization enthalpy vary across a period and down a group?

Across a period atomic radius decreases and ionization enthalpy increases, because the nuclear charge rises while electrons fill the same shell, raising the effective nuclear charge. Down a group atomic radius increases and ionization enthalpy decreases, because new shells are added and shielding grows.

Is this chapter important for NEET and what is its weightage?

Yes, Classification of Elements and Periodicity is part of the NEET Class 11 Chemistry syllabus and is regularly examined, usually contributing about 1 to 2 questions per paper. It is considered scoring because most questions test periodic trends, exceptions and the position of an element rather than lengthy calculations.

What is the difference between ionization enthalpy and electron gain enthalpy?

Ionization enthalpy is the energy needed to remove the most loosely bound electron from a gaseous atom and is always positive (endothermic). Electron gain enthalpy is the enthalpy change when a gaseous atom gains an electron and is usually negative (energy released), being most negative for the halogens.

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top