Waves Class 11 Notes | CBSE Physics Chapter 14 (Free PDF)

Chapter summary

Waves explains how energy and momentum travel through a medium without the medium itself moving along, covering transverse and longitudinal waves, the master relation v = f times lambda, and the speed of waves on strings and of sound in gases. It then builds to superposition, standing waves with nodes and antinodes, harmonics in strings and air columns, beats, and the Doppler effect. For NEET it is a steady-scoring chapter where standing waves, organ pipes, beats, and Doppler regularly appear, so getting the formulas and sign conventions right is what separates a clean answer from a careless slip.

Chapter notes

Table of Contents


Key Concepts

1. What is a Wave?

A wave is a disturbance that travels through a medium, transporting energy and momentum from one point to another without any net transport of the medium itself. Drop a stone in a pond - the ripple spreads outward, but a floating leaf only bobs up and down; it does not move with the ripple.

Mechanical waves (water waves, sound, waves on a string) need a material medium to travel. Electromagnetic waves (light, radio) need no medium. This chapter deals mainly with mechanical waves.


2. Transverse and Longitudinal Waves

Waves are classified by the direction in which the particles of the medium vibrate relative to the direction the wave travels.

Transverse WaveLongitudinal Wave
Particles vibrate perpendicular to the direction of wave propagationParticles vibrate parallel to the direction of wave propagation
Made of crests and troughsMade of compressions and rarefactions
Example: wave on a string, ripples on water, lightExample: sound waves in air, waves in a spring (pushed lengthwise)
Can travel only in solids and on liquid surfacesCan travel in solids, liquids and gases

[DIAGRAM: A horizontal string showing crests and troughs (transverse) above a slinky showing alternating compressions and rarefactions (longitudinal), both with the wave-travel direction marked by an arrow.]

Key idea: Sound in air is always longitudinal because gases cannot sustain the shearing stress needed for a transverse wave.


3. Terms Used to Describe a Wave

  • Amplitude (A): maximum displacement of a particle from its mean position.
  • Wavelength (λ): distance between two consecutive points in the same phase (crest to crest, or compression to compression). SI unit: metre.
  • Time period (T): time taken for one complete oscillation. Frequency f = 1/T, SI unit hertz (Hz).
  • Angular frequency: ω = 2πf = 2π/T. Wave number: k = 2π/λ.
  • Wave velocity (v): the speed at which the disturbance travels: v = fλ = ω/k.

4. Displacement Relation for a Progressive Wave

A progressive (travelling) wave moves continuously in one direction, carrying energy with it. For a sinusoidal wave travelling along the positive x-direction, the displacement y of a particle at position x and time t is:

y(x, t) = A sin(kx − ωt + φ)

  • A = amplitude, k = 2π/λ = angular wave number, ω = 2πf = angular frequency, φ = initial phase (phase constant).
  • For a wave travelling in the negative x-direction: y(x, t) = A sin(kx + ωt + φ).
  • The term (kx − ωt) is the phase of the wave.

Phase difference and path difference: a path difference of one wavelength λ corresponds to a phase difference of 2π. So phase difference Δφ = (2π/λ) × path difference.


5. Speed of a Travelling Wave

The speed of a wave is fixed by the properties of the medium, not by how the wave was produced. The general result is v = fλ.

Speed of a Transverse Wave on a String

For a stretched string, the wave speed depends on the tension and how heavy the string is:

v = √(T/μ)

where T is the tension in the string and μ is the linear mass density (mass per unit length, kg/m). A tighter, lighter string carries waves faster - that is how a guitar is tuned.

Speed of a Longitudinal Wave

For a longitudinal wave in a medium of bulk modulus B and density ρ: v = √(B/ρ). In a solid rod (Young’s modulus Y): v = √(Y/ρ).


6. Speed of Sound - Newton’s Formula and Laplace’s Correction

Sound is a longitudinal wave, so its speed in a gas is v = √(B/ρ). The question is which bulk modulus B to use.

Newton’s Formula

Newton assumed that sound travels through air under isothermal conditions (constant temperature). Then B equals the pressure P, giving:

v = √(P/ρ)

For air at STP this gives about 280 m/s - but the measured value is about 332 m/s. Newton’s formula is roughly 15% too low.

Laplace’s Correction

Laplace pointed out that compressions and rarefactions happen so fast that there is no time for heat to flow - the process is adiabatic, not isothermal. The relevant bulk modulus is then γP, where γ = C_p/C_v is the ratio of specific heats (γ = 1.4 for air).

v = √(γP/ρ)

This gives about 332 m/s, matching experiment. Factors affecting speed of sound: it increases with temperature (v ∝ √T in kelvin), increases with humidity, but is independent of pressure (at constant temperature) and of frequency.


7. Principle of Superposition of Waves

When two or more waves travel through the same medium at the same time, the resultant displacement at any point is the vector sum of the displacements due to each individual wave.

y = y₁ + y₂ + y₃ + …

This single principle explains interference, standing waves, and beats. After they cross, each wave continues as if the other was never there.


8. Reflection of Waves

When a wave hits a boundary, part of it is reflected. What happens to the phase depends on the boundary.

  • Reflection from a rigid (fixed) boundary: the wave is reflected with a phase change of π (180°). A crest returns as a trough. (Example: string fixed to a wall.)
  • Reflection from a free (open) boundary: the wave is reflected with no phase change. A crest returns as a crest. (Example: open end of an organ pipe.)

9. Standing (Stationary) Waves

When two identical waves of the same frequency and amplitude travel in opposite directions and superpose, they form a standing wave - a pattern that appears to stand still instead of travelling.

The resultant of y₁ = A sin(kx − ωt) and y₂ = A sin(kx + ωt) is:

y = 2A sin(kx) cos(ωt)

  • Nodes: points of permanently zero displacement, where 2A sin(kx) = 0. They occur at x = 0, λ/2, λ, … (spacing λ/2).
  • Antinodes: points of maximum displacement (amplitude 2A). They occur halfway between nodes (spacing λ/2).
  • Distance between a node and the nearest antinode is λ/4.
  • A standing wave does not transport energy along the medium - energy stays trapped between the boundaries.

[DIAGRAM: A standing wave on a string showing fixed nodes (N) at the ends and along the string, with antinodes (A) bulging between them; node-to-node spacing labelled λ/2.]


10. Normal Modes of a Stretched String

A string fixed at both ends can vibrate only at certain frequencies, called its normal modes or harmonics, because both ends must be nodes.

For a string of length L, the allowed wavelengths are λ = 2L/n (n = 1, 2, 3…), so the frequencies are:

fₙ = n·v/2L = (n/2L)√(T/μ), where n = 1, 2, 3, …

  • n = 1: fundamental frequency (first harmonic), f₁ = v/2L.
  • n = 2: second harmonic (first overtone), f₂ = 2f₁.
  • A string produces all harmonics - both even and odd - so its overtones are 2f₁, 3f₁, 4f₁, …

11. Normal Modes in Air Columns (Organ Pipes)

Sound waves form standing waves inside pipes. An open end is an antinode (free to vibrate) and a closed end is a node (cannot vibrate).

Open Pipe (open at both ends)

Both ends are antinodes. The allowed frequencies are:

fₙ = n·v/2L (n = 1, 2, 3, …)

An open pipe gives all harmonics (1f, 2f, 3f, …), which is why it sounds richer.

Closed Pipe (closed at one end)

The closed end is a node and the open end an antinode. The allowed frequencies are:

fₙ = n·v/4L (n = 1, 3, 5, … only odd)

A closed pipe gives only odd harmonics (1f, 3f, 5f, …). Its fundamental v/4L is half that of an open pipe of the same length.

PipeFundamentalHarmonics present
Open pipev/2LAll (1, 2, 3, 4…)
Closed pipev/4LOnly odd (1, 3, 5…)

12. Beats

When two sound waves of slightly different frequencies superpose, the loudness rises and falls periodically. These periodic variations in intensity are called beats.

The number of beats heard per second equals the difference of the two frequencies:

Beat frequency = |f₁ − f₂|

  • Beats are audible only if |f₁ − f₂| is less than about 10 Hz (the ear cannot resolve faster fluctuations).
  • Used to tune musical instruments - when the beats vanish, the two notes are identical.

13. The Doppler Effect

The Doppler effect is the apparent change in the frequency (pitch) of a sound when the source, the observer, or both are moving relative to each other. An approaching ambulance sounds higher-pitched; as it moves away the pitch drops.

The general formula for the observed frequency f′ is:

f′ = f · (v ± v₀)/(v ∓ v_s)

where v is the speed of sound, v₀ the observer’s speed and v_s the source’s speed.

Sign Convention

  • Take all velocities positive along the direction from source to observer.
  • Use the top sign when source and observer move towards each other (frequency increases).
  • Use the bottom sign when they move away from each other (frequency decreases).

Note: for light the Doppler shift gives the “red shift” of receding stars, but the sound formula above is not symmetric in v₀ and v_s - moving the source is not the same as moving the observer.


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Weightage in Board & Entrance Exams

ExamTypical WeightageMost-Tested Areas
CBSE Board (Class 11)6–8 marksProgressive wave equation, organ pipes, beats, Doppler effect
JEE Main / Advanced1–2 questionsStanding waves, string & pipe harmonics, Doppler numericals
NEET1–2 questionsSpeed of sound, beats, Doppler effect, wave equation

[TABLE: Question-type split - VSA (1 mark): wave types, definitions, beat frequency; SA (2–3 marks): wave equation, Newton-Laplace, pipe harmonics; LA (5 marks): standing-wave derivation, Doppler-effect derivation.]


Important Definitions

TermDefinition
WaveA disturbance that transfers energy through a medium without net transfer of matter
Transverse waveParticles vibrate perpendicular to the direction of propagation (crests and troughs)
Longitudinal waveParticles vibrate parallel to propagation (compressions and rarefactions)
Wavelength (λ)Distance between two consecutive points in the same phase
Wave velocitySpeed at which the disturbance travels: v = fλ
Progressive waveA wave that travels continuously transporting energy: y = A sin(kx − ωt)
Laplace’s correctionSound propagates adiabatically, so v = √(γP/ρ)
Standing wavePattern formed by two opposite waves: y = 2A sin(kx) cos(ωt); no energy transport
Node / AntinodePoint of zero displacement / maximum displacement in a standing wave
BeatsPeriodic rise and fall of loudness when two close frequencies superpose; rate = |f₁ − f₂|
Doppler effectApparent change in frequency due to relative motion of source and observer

Solved Examples

Example 1

A wave has frequency 500 Hz and wavelength 0.66 m. Find its speed.

Answer: v = fλ = 500 × 0.66 = 330 m/s.

Example 2

A string of linear mass density 2 g/m is stretched with a tension of 80 N. Find the speed of a transverse wave on it.

Answer: μ = 2 g/m = 0.002 kg/m. v = √(T/μ) = √(80/0.002) = √40000 = 200 m/s.

Example 3

For a progressive wave y = 0.05 sin(20x − 600t) (SI units), find the amplitude, wave number, angular frequency, wavelength and speed.

Answer: A = 0.05 m; k = 20 rad/m; ω = 600 rad/s. λ = 2π/k = 2π/20 = 0.314 m. v = ω/k = 600/20 = 30 m/s.

Example 4

A pipe closed at one end has length 0.5 m. Taking the speed of sound as 340 m/s, find its fundamental frequency.

Answer: Closed pipe fundamental f = v/4L = 340/(4 × 0.5) = 340/2 = 170 Hz.

Example 5

Two tuning forks of frequencies 256 Hz and 260 Hz are sounded together. Find the beat frequency.

Answer: Beat frequency = |f₁ − f₂| = |256 − 260| = 4 Hz (4 beats per second).

Example 6

A source emitting sound of frequency 500 Hz moves towards a stationary observer at 30 m/s. Taking v = 330 m/s, find the apparent frequency.

Answer: Source approaching: f′ = f·v/(v − v_s) = 500 × 330/(330 − 30) = 500 × 330/300 = 550 Hz.


Important Questions for Board Exams

1-Mark Questions (VSA)

  1. Why can transverse waves not travel through gases?
  2. What is the phase difference corresponding to a path difference of one wavelength?
  3. State the relation between wave velocity, frequency and wavelength.
  4. Why does a closed organ pipe produce only odd harmonics?
  5. Two sound waves of frequencies 400 Hz and 404 Hz are sounded together. How many beats are heard per second?

2–3-Mark Questions (SA)

  1. State Newton’s formula for the speed of sound in air and explain Laplace’s correction.
  2. Distinguish between transverse and longitudinal waves with one example each.
  3. Derive the expression for the frequency of the nth harmonic of a string fixed at both ends.
  4. What are beats? Write the expression for beat frequency and state one use of beats.

5-Mark Questions (LA)

  1. Using the principle of superposition, derive the equation of a standing wave and obtain the positions of nodes and antinodes.
  2. Derive an expression for the apparent frequency heard by a stationary observer when the source of sound moves towards and then away from the observer (Doppler effect).
  3. Compare the modes of vibration of an open organ pipe and a closed organ pipe, deriving the frequencies of their harmonics.

Quick Revision Points

  • Wave transfers energy, not matter; v = fλ = ω/k
  • Transverse: ⟂ vibration, crests/troughs; Longitudinal: ∥ vibration, compressions/rarefactions
  • Progressive wave: y = A sin(kx − ωt); k = 2π/λ, ω = 2πf
  • Phase difference Δφ = (2π/λ) × path difference
  • Wave on string: v = √(T/μ); longitudinal: v = √(B/ρ)
  • Speed of sound - Newton: v = √(P/ρ); Laplace (adiabatic): v = √(γP/ρ); v ∝ √T
  • Superposition: resultant displacement = sum of individual displacements
  • Rigid boundary → phase change π; free boundary → no phase change
  • Standing wave: y = 2A sin(kx) cos(ωt); node–node = λ/2, node–antinode = λ/4; no energy transport
  • String (both ends fixed): fₙ = (n/2L)√(T/μ), all harmonics
  • Open pipe: fₙ = nv/2L (all harmonics); Closed pipe: fₙ = nv/4L (odd harmonics only)
  • Beats: beat frequency = |f₁ − f₂|, audible if < ~10 Hz
  • Doppler: f′ = f(v ± v₀)/(v ∓ v_s); towards → higher pitch

Next Chapter: Class 12 Physics - Electric Charges and Fields

🃏 Flash Cards: Waves

Class 11 Physics · Chapter 15 – swipe through all 9 cards to understand the whole chapter.

🌊Start here1/9

What a Wave Is

A wave carries energy and momentum through a medium without carrying matter.

Transverse ⊥ motion · Longitudinal ∥ motion

Light is transverse; sound is longitudinal — never swap them.

  • Transverse: particles vibrate perpendicular → crests & troughs
  • Longitudinal: particles vibrate parallel → compressions & rarefactions
  • The disturbance moves; the medium just wobbles in place
📐Master equation2/9

Wave Equation & v = fλ

One relation links speed, frequency and wavelength for every wave.

v = fλ = ω/k, y = A sin(ωt − kx)

ω = 2πf, k = 2π/λ; minus sign → wave travels in +x.

  • Read ω off the t-term, k off the x-term, then v = ω/k
  • T = 1/f is the time period; A is the amplitude
  • Across a new medium frequency stays fixed; v and λ change together
🚀Core law3/9

Speed of Mechanical Waves

Wave speed is set by the medium, not by frequency or amplitude.

v = √(T/μ) on string · v = √(γP/ρ) for sound in gas

μ in kg m⁻1 — convert g/cm → kg/m (the #1 silent error).

  • String: more tension → faster; heavier string → slower
  • Sound in gas (Laplace, adiabatic): v ∝ √T, v ∝ 1/√M
  • Independent of pressure at fixed T; ≈ 332 m s⁻1 in air at 0°C
Key principle4/9

Superposition & Interference

When waves overlap, displacements add algebraically at every point.

Δφ = (2π/λ) · Δx

Phase π ↔ path difference λ/2 → perfect cancellation.

  • Constructive: path difference Δx = nλ (in phase, loud)
  • Destructive: Δx = (n + ½)λ (out of phase, silent)
  • After crossing, both waves carry on unchanged
🎚️Standing waves5/9

Nodes & Antinodes

Two identical waves in opposite directions make a wave that stands still.

y = 2A sin(kx) cos(ωt)

Adjacent nodes are λ/2 apart; node to nearest antinode is λ/4.

  • Nodes: zero amplitude, permanently at rest
  • Antinodes: maximum amplitude 2A
  • No net energy crosses a node — it only sloshes within each loop
🎸Harmonics6/9

Strings & Open Pipes

A string fixed at both ends and an open pipe sustain all integer harmonics.

String fₙ = (n/2L)√(T/μ) · Open pipe fₙ = nv/2L

Fixed/closed end = node; free/open end = antinode.

  • Fundamental f1 = v/2L; all harmonics 1f, 2f, 3f… present
  • Rich tone (flute, guitar) from the full harmonic series
  • For a string f ∝ √T — quadruple tension, frequency only doubles
🎺Closed pipe7/9

Closed-Pipe Harmonics

A pipe closed at one end keeps only the odd harmonics.

fₙ = (2n − 1)v/4L, f1 = v/4L

Closed-pipe denominator is 4L, not 2L.

  • Only odd harmonics 1f, 3f, 5f… → hollow, pure tone
  • Open pipe’s fundamental is twice a closed pipe’s of equal length
  • End correction ≈ 0.6r per open end raises effective length
🔊Beats8/9

Beats

Two nearly-equal frequencies make loudness swell and fade periodically.

f_beat = |f1 − f2|, f_heard = (f1 + f2)/2

Audible only if the gap ≤ ~10 Hz; same-direction waves.

  • Unknown fork = f ± n — always two candidates
  • Filing raises frequency; loading (wax) lowers it
  • Fix the sign by whether beats grow or shrink after the change
🚑Doppler effect9/9

Doppler Effect

Relative motion of source and observer shifts the perceived frequency.

f’ = f (v ± v0)/(v ∓ vₛ)

Source speed always in the denominator; sanity-check approach → f’ > f.

  • Approach raises pitch; recession lowers it
  • v0: + toward source, − away · vₛ: − toward observer, + away
  • Not symmetric for sound (medium fixes a frame); add wind w to v
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📝 Practice Waves — 10 NEET PYQs
Real previous-year questions · with answers & solutions
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Q1NEET 2020
The length of the string of a musical instrument is 90 cm and it has a fundamental frequency of 120 Hz. Where should it be pressed to produce a fundamental frequency of 180 Hz?
Correct answer: B. For a fixed string under constant tension, f∝(1)/(l). So l₂=l₁(f₁)/(f₂)=90×(120)/(180)=60 cm.
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Q2NEET 2020
In a guitar, two strings A and B made of the same material are slightly out of tune and produce beats of frequency 6 Hz. When the tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be:
Correct answer: A. The unknown f_B=530±6=536 or 524 Hz. Decreasing the tension in B lowers f_B. Since the beat frequency increased (gap widened), B must already have been below A, so f_B=530-6=524 Hz (lowering it further widens the gap to 7).
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Q3NEET 2019
A tuning fork of frequency 800 Hz produces resonance in a resonance column tube with upper end open and lower end closed by a water surface. Successive resonances are observed at lengths 9.75 cm, 31.25 cm and 52.75 cm. The speed of sound in air is:
Correct answer: C. The difference between successive resonance lengths equals (λ)/(2): 31.25-9.75=21.5 cm, so λ=43 cm =0.43 m. Speed v=fλ=800×0.43=344 m s⁻¹.
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Q4NEET 2017
Two cars moving in opposite directions approach each other with speeds 22 m s⁻¹ and 16.5 m s⁻¹ respectively. The driver of the first car blows a horn of frequency 400 Hz. The frequency heard by the driver of the second car is (velocity of sound 340 m s⁻¹):
Correct answer: D. Both are approaching, so f’=f₀(v+vₒ)/(v-vₛ) with observer (2nd car) vₒ=16.5 and source (1st car) vₛ=22: f’=400×(340+16.5)/(340-22)=400×(356.5)/(318)≈448 Hz.
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Q5NEET 2016
A uniform rope of length L and mass m₁ hangs vertically from a rigid support. A block of mass m₂ is attached to the free (lower) end of the rope. A transverse pulse of wavelength λ₁ is produced at the lower end of the rope; when it reaches the top its wavelength is λ₂. The ratio λ₂/λ₁ is:
Correct answer: A. Wave speed on a string is v=√(T/μ) and frequency f is fixed by the source, so λ=v/f∝√(T). At the lower end the tension is only the block’s weight, T₁=m₂ g; at the top the rope supports both the block and its own weight, T₂=(m₁+m₂)g. Hence (λ₂)/(λ₁)=√((T₂)/(T₁))=√((m₁+m₂)/(m₂)).
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Q6NEET 2011
Two waves are represented by y₁=asin(ω t+kx+0.57) m and y₂=acos(ω t+kx) m, where x is in metre and t in second. The phase difference between them is:
Correct answer: D. Write y₂ as a sine: cosθ=sin(θ+(π)/(2)), so y₂=asin(ω t+kx+(π)/(2)) with phase 1.57 rad. The phase of y₁ is 0.57 rad. Phase difference Δφ=1.57-0.57=1.0 rad.
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Q7NEET 2010
A transverse wave is represented by y=Asin(ω t-kx). For what value of the wavelength is the wave velocity equal to the maximum particle velocity?
Correct answer: C. Wave velocity v=(ω)/(k) and maximum particle velocity v_(p,max)=Aω. Setting them equal: (ω)/(k)=Aω⇒ k=(1)/(A). Since k=(2π)/(λ), λ=2π A.
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Q8NEET 2009
A wave in a string has an amplitude of 2 cm. The wave travels in the +x direction with a speed of 128 m s⁻¹ and it is noted that 5 complete waves fit in 4 m length of the string. The equation describing the wave is:
Correct answer: D. Amplitude A=2 cm =0.02 m. Five waves in 4 m gives λ=(4)/(5)=0.8 m, so k=(2π)/(0.8)=7.85 rad m⁻¹. Then ω=vk=128×7.85=1005 rad s⁻¹. A +x travelling wave is y=Asin(kx-ω t), giving y=0.02sin(7.85x-1005t).
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Q9NEET 2008
Two periodic waves of intensities I₁ and I₂ pass through a region at the same time in the same direction. The sum of the maximum and minimum intensities is:
Correct answer: D. Since I∝ a², the amplitudes are √(I₁),√(I₂). Maximum intensity (in phase) I_(max)=(√(I₁)+√(I₂))² and minimum (out of phase) I_(min)=(√(I₁)-√(I₂))². Their sum =2(I₁+I₂).
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Q10NEET 2004
The phase difference between two waves represented by y₁=10⁻⁶sin[100t+((x)/(50))+0.5] m and y₂=10⁻⁶cos[100t+((x)/(50))] m, where x is in metre and t in second, is approximately:
Correct answer: A. Write y₂ as a sine: cosθ=sin(θ+(π)/(2)), so y₂=10⁻⁶sin[100t+(x)/(50)+(π)/(2)] with phase (π)/(2)=1.57 rad. The phase of y₁ is 0.5 rad. Phase difference =1.57-0.5=1.07 rad.
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Frequently Asked Questions

What is the difference between transverse and longitudinal waves?

In a transverse wave the particles of the medium vibrate perpendicular to the direction the wave travels, forming crests and troughs, as in waves on a string or light. In a longitudinal wave the particles vibrate parallel to the direction of travel, forming compressions and rarefactions, as in sound waves in air.

What is the wave equation v = f lambda and when do these quantities change?

For any wave the speed equals frequency times wavelength, v = f times lambda, which can also be written v = omega divided by k. When a wave passes from one medium into another its frequency stays fixed, while its speed and wavelength change together.

How does the speed of sound depend on temperature and pressure in a gas?

Using Laplace’s adiabatic correction, the speed of sound in a gas is v = square root of (gamma times P divided by rho), and it is proportional to the square root of absolute temperature. It is independent of pressure at a fixed temperature, and in air at 0 degrees Celsius it is about 332 metres per second.

What is the difference between an open pipe and a closed pipe in terms of harmonics?

An open pipe (open at both ends) supports all integer harmonics with fundamental frequency v divided by 2L, while a pipe closed at one end supports only the odd harmonics with fundamental v divided by 4L. As a result, an open pipe of a given length sounds an octave higher than a closed pipe of the same length.

Is Waves important for NEET and which topics carry the most weight?

Yes, Waves is part of the NEET Physics syllabus and usually contributes a question or two each year, making it a reliable scoring chapter. The most frequently tested topics are standing waves in strings and organ pipes, beats, and the Doppler effect, so practising sign conventions in the Doppler formula and the closed-versus-open pipe distinction pays off.

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