Oscillations Class 11 Notes | CBSE Physics Chapter 13 (Free PDF)

Chapter summary

Oscillations introduces periodic and to-and-fro motion, with simple harmonic motion (SHM) at its core, where the restoring force is proportional to displacement and acceleration follows a = minus omega squared times x. It covers displacement, phase, velocity, acceleration and energy in SHM, plus standard systems like the spring-mass and simple pendulum, and finishes with damped, forced oscillations and resonance. It is a high-yield NEET chapter whose formulas and graphs also feed directly into Waves and AC circuits.

Chapter notes

Table of Contents


Key Concepts

1. Periodic and Oscillatory Motion

Periodic motion is any motion that repeats itself after a fixed interval of time, called the time period (T). The hands of a clock, the Earth around the Sun, and a vibrating string are all periodic.

Oscillatory (or vibratory) motion is a special kind of periodic motion in which a body moves to and fro about a fixed mean (equilibrium) position. Every oscillatory motion is periodic, but not every periodic motion is oscillatory - the Earth’s orbit is periodic but not oscillatory.

  • Time period (T): time for one complete oscillation. SI unit: second.
  • Frequency (ν): number of oscillations per second; ν = 1/T. SI unit: hertz (Hz).
  • Angular frequency (ω): ω = 2πν = 2π/T. SI unit: rad/s.

2. Simple Harmonic Motion (SHM)

Simple harmonic motion is the simplest oscillatory motion, in which the restoring force on the body is directly proportional to its displacement from the mean position and is always directed towards that mean position.

The displacement of a particle in SHM is described by:

y = A sin(ωt + φ₀)   or   y = A cos(ωt + φ₀)

  • A = amplitude - the maximum displacement from the mean position.
  • ω = angular frequency.
  • (ωt + φ₀) = phase; φ₀ = initial phase (epoch).

A particle moving in a circle at constant speed, when projected on a diameter, traces SHM - this is the link between circular motion and SHM.


3. Displacement, Velocity and Acceleration in SHM

Taking displacement y = A sin ωt, we differentiate to get velocity and acceleration.

Velocity: v = dy/dt = Aω cos ωt = ω√(A² − y²)

Acceleration: a = dv/dt = −Aω² sin ωt = −ω²y

  • Velocity is maximum at the mean position (y = 0): v_max = Aω.
  • Velocity is zero at the extreme positions (y = ±A).
  • Acceleration is zero at the mean position and maximum at the extremes: a_max = Aω².

[DIAGRAM: Three curves on the same time axis - displacement (sine), velocity (cosine, leading by 90°), and acceleration (negative sine, opposite to displacement).]


4. Phase in SHM

The phase (ωt + φ₀) of an oscillating particle specifies its state of motion - both its position and direction - at any instant. It is measured as an angle in radians.

The initial phase or epoch (φ₀) is the phase at t = 0; it fixes the starting point of the oscillation. Two SHMs of the same frequency may differ in phase, and the phase difference tells how much one leads or lags the other.

  • Velocity leads displacement by a phase of π/2.
  • Acceleration leads displacement by a phase of π (they are exactly out of phase).

5. Force Law for SHM

From a = −ω²y and Newton’s second law F = ma, the force in SHM is:

F = −mω²y = −ky, where k = mω² is the force constant.

The negative sign shows the force is a restoring force - always opposite to displacement, pulling the body back to the mean position. From k = mω² we get the central result:

ω = √(k/m)   and   T = 2π√(m/k)

Key idea: Any system whose restoring force is proportional to displacement (F ∝ −y) executes SHM.


6. Energy in SHM

An oscillator continuously exchanges energy between kinetic and potential forms, but its total mechanical energy stays constant (for an ideal, undamped system).

Kinetic energy: KE = ½mv² = ½mω²(A² − y²)

Potential energy: PE = ½ky² = ½mω²y²

Total energy: E = KE + PE = ½mω²A² = ½kA²

  • KE is maximum at the mean position (y = 0); PE is zero there.
  • PE is maximum at the extreme positions (y = ±A); KE is zero there.
  • Total energy is independent of y and proportional to the square of the amplitude (E ∝ A²) and the square of the frequency.

[DIAGRAM: KE and PE plotted against displacement y - KE an inverted parabola peaking at the centre, PE an upright parabola, their sum a flat horizontal line equal to total energy E.]


7. Simple Pendulum

A simple pendulum is an ideal point mass (bob) suspended by a weightless, inextensible string from a rigid support. For small angular displacements (θ < about 4°), its motion is SHM.

The restoring force is the tangential component of gravity, mg sin θ ≈ mg θ for small angles, which leads to:

T = 2π√(L/g)

  • The time period depends only on length L and acceleration due to gravity g.
  • It is independent of the mass of the bob and of the amplitude (for small angles).
  • A pendulum clock runs slow in summer (L increases) and fast in winter (L decreases).

Seconds pendulum: a pendulum with T = 2 s; its length on Earth is about 1 m.


8. Oscillations of a Spring

A mass m attached to a spring of force constant (spring constant) k executes SHM when displaced and released. The spring provides the restoring force F = −kx.

T = 2π√(m/k)

The time period is independent of the value of g, so a spring-mass oscillator keeps the same period on the Moon as on the Earth.

Springs in Series and Parallel

CombinationEffective spring constantEffect on T
Series1/k_eff = 1/k₁ + 1/k₂ (k_eff smaller)T increases (softer)
Parallelk_eff = k₁ + k₂ (k_eff larger)T decreases (stiffer)

Cutting a spring into n equal parts makes each piece n times stiffer (k becomes nk), so its period falls.


9. Damped Oscillations

Real oscillators lose energy to friction and air resistance, so their amplitude gradually decreases with time. This is damped oscillation.

The damping force is proportional to velocity, F_d = −bv, where b is the damping constant. The displacement becomes:

x(t) = A e^(−bt/2m) cos(ω′t + φ)

  • The amplitude decays exponentially as A e^(−bt/2m).
  • The angular frequency of damped motion ω′ = √(k/m − b²/4m²) is slightly less than the natural frequency.
  • The energy of the oscillator also decreases exponentially with time.

10. Free, Forced Oscillations and Resonance

Free oscillations occur at a body’s own natural frequency (ω₀) once it is disturbed and left to itself - with no external driving force and (ideally) no damping.

Forced oscillations occur when an external periodic force of frequency ω_d is continuously applied. The body then oscillates at the driving frequency ω_d, not its natural frequency.

Resonance is the special case of forced oscillation when the driving frequency equals the natural frequency (ω_d = ω₀). The amplitude then becomes very large.

  • Resonance lets a singer’s voice shatter a glass and a child pump a swing higher with small timed pushes.
  • Soldiers break step on a bridge to avoid resonance (the Tacoma Narrows bridge collapse is the classic example).
  • Greater damping gives a smaller, broader resonance peak.

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Weightage in Board & Entrance Exams

ExamTypical WeightageMost-Tested Areas
CBSE Board (Class 11)6–8 marks (Unit: Oscillations & Waves)SHM equations, energy in SHM, pendulum & spring T
JEE Main / Advanced1–2 questionsSpring combinations, energy, phase, damped/forced SHM
NEET1–2 questionsTime period of pendulum/spring, velocity-acceleration in SHM, resonance

[TABLE: Question-type split - VSA (1 mark): definitions, ω–T–ν relations; SA (2–3 marks): velocity/acceleration of SHM, energy, spring combinations; LA (5 marks): pendulum/spring time-period derivations, energy of SHM derivation.]


Important Definitions

TermDefinition
Periodic motionMotion that repeats after a fixed time interval (the time period)
Oscillatory motionTo-and-fro periodic motion about a fixed mean position
Simple harmonic motionOscillation where restoring force ∝ displacement and is directed to the mean position: F = −ky
Amplitude (A)Maximum displacement of the particle from its mean position
Time period (T)Time for one complete oscillation; T = 2π/ω
Frequency (ν)Number of oscillations per second; ν = 1/T (unit: hertz)
PhaseThe quantity (ωt + φ₀) that fixes the state of the oscillating particle
Restoring forceForce directed towards the mean position: F = −ky
Damped oscillationOscillation whose amplitude decreases with time due to resistive forces
ResonanceLarge-amplitude forced oscillation when driving frequency = natural frequency

Solved Examples

Example 1

A particle executes SHM of amplitude 5 cm and time period 2 s. Find its maximum velocity and maximum acceleration.

Answer: ω = 2π/T = 2π/2 = π rad/s. v_max = Aω = 0.05 × π = 0.157 m/s. a_max = Aω² = 0.05 × π² = 0.493 m/s².

Example 2

The displacement of a particle is y = 4 sin(2πt) cm. Find its amplitude, time period and frequency.

Answer: Comparing with y = A sin ωt: A = 4 cm, ω = 2π rad/s, so T = 2π/ω = 1 s and ν = 1/T = 1 Hz.

Example 3

A spring of force constant 200 N/m carries a mass of 2 kg. Find the time period of oscillation.

Answer: T = 2π√(m/k) = 2π√(2/200) = 2π√0.01 = 2π × 0.1 = 0.628 s.

Example 4

Find the length of a seconds pendulum (T = 2 s) at a place where g = 9.8 m/s².

Answer: T = 2π√(L/g) ⇒ L = gT²/(4π²) = (9.8 × 4)/(4 × 9.87) = 39.2/39.48 ≈ 0.993 m.

Example 5

A particle in SHM has amplitude 10 cm and angular frequency 4 rad/s. Find its velocity when the displacement is 6 cm.

Answer: v = ω√(A² − y²) = 4√(0.10² − 0.06²) = 4√(0.01 − 0.0036) = 4√0.0064 = 4 × 0.08 = 0.32 m/s.

Example 6

A body of mass 0.5 kg executes SHM of amplitude 0.1 m and angular frequency 10 rad/s. Find its total energy.

Answer: E = ½mω²A² = ½ × 0.5 × 10² × 0.1² = ½ × 0.5 × 100 × 0.01 = 0.25 J.


Important Questions for Board Exams

1-Mark Questions (VSA)

  1. Define simple harmonic motion.
  2. What is the phase relation between displacement and acceleration in SHM?
  3. Write the relation between time period, frequency and angular frequency.
  4. Does the time period of a simple pendulum depend on the mass of the bob?
  5. At what position in SHM is the kinetic energy maximum?

2–3-Mark Questions (SA)

  1. Show that the velocity of a particle in SHM is v = ω√(A² − y²) and find where it is maximum.
  2. Derive expressions for the kinetic and potential energy of a particle in SHM and show that total energy is constant.
  3. Two springs of constants k₁ and k₂ are joined (a) in series and (b) in parallel to a mass m. Find the time period in each case.
  4. What is resonance? Give two everyday examples and explain why soldiers break step on a bridge.

5-Mark Questions (LA)

  1. Define SHM and derive the expressions for displacement, velocity and acceleration of a particle executing SHM.
  2. Derive an expression for the time period of a simple pendulum and state the assumptions made.
  3. Show that the oscillation of a loaded spring is simple harmonic and derive T = 2π√(m/k). Discuss damped and forced oscillations.

Quick Revision Points

  • Oscillatory motion is periodic to-and-fro motion about a mean position
  • ω = 2πν = 2π/T; frequency ν = 1/T (unit: hertz)
  • SHM: F = −ky, a = −ω²y; restoring force ∝ displacement, towards mean position
  • Displacement y = A sin(ωt + φ₀); velocity v = ω√(A² − y²); acceleration a = −ω²y
  • v is max at mean position (Aω); a is max at extremes (Aω²)
  • Velocity leads displacement by π/2; acceleration is π out of phase with displacement
  • Energy: KE = ½mω²(A² − y²), PE = ½mω²y², total E = ½mω²A² = ½kA² (constant, ∝ A²)
  • Simple pendulum: T = 2π√(L/g); independent of mass and amplitude (small angles)
  • Spring-mass: T = 2π√(m/k); independent of g
  • Springs in series: k smaller, T larger; in parallel: k larger, T smaller
  • Damped SHM: amplitude decays as A e^(−bt/2m); resonance when ω_d = ω₀

Next Chapter: Chapter 14 - Waves

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Class 11 Physics · Chapter 14 – swipe through all 10 cards to understand the whole chapter.

🔁Start here1/10

Periodic vs Oscillatory Motion

Motion that repeats after a fixed time, and the special to-and-fro kind about a mean position.

f = 1/T · ω = 2πf = 2π/T

T in seconds, f in hertz (Hz), ω in rad/s

  • Periodic = repeats after fixed time; oscillatory = to-and-fro about a mean position
  • Every oscillation is periodic, but not every periodic motion oscillates (e.g. Earth’s orbit)
  • f and ω differ by a factor of 2π, not 1
🎯Defining law2/10

Simple Harmonic Motion (SHM)

The cleanest oscillation: restoring force is proportional to displacement and points back toward the mean.

F = −k x ⇒ a = −ω2 x

The minus sign (restoring) is the whole idea: a ∝ −x

  • Any motion with a ∝ −x is SHM
  • Force always pulls the body back toward equilibrium
  • a = −ω2x is both the test for SHM and the fastest way to read ω
📐Core equation3/10

Displacement, Phase & Amplitude

SHM is the projection of uniform circular motion on a diameter.

x = A cos(ωt + φ)

Period depends only on ω, NOT on amplitude A

  • A = amplitude (max displacement); (ωt + φ) = phase; φ = initial phase
  • Start at mean → x = A sin(ωt); start at extreme → x = A cos(ωt)
  • In phase if phase difference is 0 or 2π; opposite if it is π
🏃Key relation4/10

Velocity in SHM

Speed is greatest at the mean position and zero at the extremes.

v = ±ω √(A2 − x2) · v_max = A ω

Velocity leads displacement by π/2

  • v is maximum at the mean position (x = 0)
  • v = 0 at the extremes (x = ±A), where the body turns around
  • Keep x and A in the same units before squaring
Key relation5/10

Acceleration in SHM

Acceleration is greatest at the extremes and zero at the mean position.

a = −ω2 x · a_max = A ω2

Acceleration is π out of phase (opposite) to displacement

  • a is maximum at the extremes (x = ±A); zero at the mean
  • Where speed is greatest, acceleration is zero, and vice-versa
  • v_max ∝ ω (one power); a_max ∝ ω2 (two powers) — don’t swap them
🔋Energy6/10

Energy in SHM

KE and PE swap continuously while the total energy stays constant (no friction).

E = ½ m ω2 A2 · KE = ½ m ω2(A2 − x2) · PE = ½ m ω2 x2

E ∝ A2: doubling amplitude makes energy ×4

  • Mean position: all KE (PE = 0); extremes: all PE (KE = 0)
  • KE and PE oscillate at twice the frequency (2f)
  • KE = PE when x = A/√2 ≈ 0.707A; KE = ¾E when x = A/2
🌀Key system7/10

Spring–Mass System

A mass on a spring of stiffness k executes SHM with a period set by m and k.

T = 2π √(m / k)

No g in the formula — same period on the Moon

  • Heavier mass → slower; stiffer spring → faster
  • Series springs are softer: 1/k_s = 1/k1 + 1/k2
  • Parallel springs are stiffer: k_p = k1 + k2; cutting into n pieces gives k → n k each
🕰️Key system8/10

Simple Pendulum

A bob on a light string swinging through small angles executes SHM.

T = 2π √(L / g)

Valid only for small angles (< ~10°); no mass, no amplitude

  • Depends on L and g only — not on bob mass or amplitude
  • Seconds pendulum: T = 2 s (L ≈ 1 m on Earth)
  • Smaller g (altitude, equator) or larger L → larger T → clock runs slow
📉Real world9/10

Damped Oscillations

Real oscillators lose energy to friction, so amplitude decays over time.

A(t) = A0 e^(−bt/2m) · E ∝ e^(−bt/m)

Damping force F = −b v; energy decays as amplitude2

  • Amplitude decays exponentially, not linearly
  • Damped angular frequency ω′ = √(ω02 − (b/2m)2) is slightly less than ω0
  • Energy fades faster than amplitude (the square)
📣Most-tested10/10

Forced Oscillation & Resonance

An external periodic force drives the system; amplitude peaks when frequencies match.

Resonance at ω_d = ω0

Lighter damping → sharper, taller resonance peak

  • In steady state the body oscillates at the driving frequency, not its own ω0
  • Maximum amplitude / energy transfer occurs at ω_d = ω0
  • Examples: pushing a swing in rhythm, tuning a radio, bridge swaying
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📝 Practice Oscillations — 10 NEET PYQs
Real previous-year questions · with answers & solutions
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Q1NEET 2021
A body is executing simple harmonic motion with frequency n. The frequency of its potential energy is:
Correct answer: B. In SHM both kinetic and potential energy attain their maximum value twice in one complete oscillation (PE depends on ). Hence the frequency of PE (and KE) variation is 2n, twice the oscillation frequency.
🔎 See the full step-by-step solution in the app →
Q2NEET 2021
A spring is stretched by 5 cm by a force of 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is:
Correct answer: D. Force constant k = (F)/(x) = (10)/(0.05) = 200 N/m. T = 2π√((m)/(k)) = 2π√((2)/(200)) = 2π√(0.01) = 2π(0.1) ≈ 0.628 s.
🔎 See the full step-by-step solution in the app →
Q3NEET 2020
The phase difference between displacement and acceleration of a particle in simple harmonic motion is:
Correct answer: D. For x = asinω t, acceleration a = -ω² asinω t = ω² asin(ω t + π). So acceleration is exactly π out of phase with displacement (it always points opposite to x).
🔎 See the full step-by-step solution in the app →
Q4NEET 2020
Which of the following functions represents a periodic motion?
Correct answer: C. sinω t and cosω t are each periodic with period 2π/ω, and the sum of two periodic functions of the same period is also periodic. The exponential and logarithmic functions are not periodic.
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Q5NEET 2019
The displacement of a particle executing SHM is y = A₀ + Asinω t + Bcosω t. The amplitude of its oscillation is:
Correct answer: A. A₀ only shifts the mean position (where y is constant), it does not contribute to amplitude. Combining Asinω t + Bcosω t = Rsin(ω t + φ) with R = √(A² + B²) (since the two terms are 90° out of phase). So amplitude = √(A² + B²).
🔎 See the full step-by-step solution in the app →
Q6NEET 2019
The distance covered by a particle executing SHM of amplitude A in one complete time period is:
Correct answer: D. In one full period the particle goes mean to extreme (A), back to mean (A), to the other extreme (A), and back to mean (A). Total path length = A+A+A+A = 4A (displacement is zero, but distance is 4A).
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Q7NEET 2019
The average velocity of a particle executing SHM in one complete vibration is:
Correct answer: C. Average velocity = total displacement / time. Over one complete vibration the particle returns to its starting point, so net displacement is zero and the average velocity is zero (even though average speed is not).
🔎 See the full step-by-step solution in the app →
Q8NEET 2012
The damping force on an oscillator is directly proportional to the velocity. The units of the constant of proportionality are:
Correct answer: C. F = kv ⇒ k = (F)/(v). Units = (kg m s⁻²)/(m s⁻¹) = kg s⁻¹.
🔎 See the full step-by-step solution in the app →
Q9NEET 2007
The kinetic energy of a particle executing SHM is K₀cos²ω t. The maximum values of the potential energy and the total energy are respectively:
Correct answer: D. KE is maximum (K₀) at the mean position, where PE is zero, so total energy E = K₀. Total energy is constant, so the maximum PE (at the extremes, where KE = 0) also equals K₀. Hence both are K₀.
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Q10NEET 2003
The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (E = total energy):
Correct answer: A. U = (1)/(2)mω² x² and E = (1)/(2)mω² a². Half way to the end point, x = (a)/(2), so U = (1)/(2)mω²(a²)/(4) = (1)/(4)E.
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Frequently Asked Questions

What is simple harmonic motion (SHM)?

SHM is an oscillation in which the restoring force is directly proportional to the displacement from the mean position and always points back toward it. This gives the defining relation a = minus omega squared times x, so any motion with acceleration proportional to negative displacement is SHM.

What is the time period formula for a spring-mass system and a simple pendulum?

A mass m on a spring of stiffness k has period T = 2 pi times the square root of (m divided by k). A simple pendulum of length L has period T = 2 pi times the square root of (L divided by g), valid only for small angles below about 10 degrees.

How do velocity and acceleration vary in SHM?

Velocity is v = plus or minus omega times the square root of (A squared minus x squared), so it is maximum at the mean position and zero at the extremes. Acceleration is a = minus omega squared times x, so it is maximum at the extremes and zero at the mean position, exactly opposite to where velocity peaks.

Is Oscillations important for NEET?

Yes, Oscillations is part of the NEET Physics syllabus and is consistently asked, usually one to two questions per paper. SHM energy, the velocity and acceleration relations, and the spring and pendulum periods are the most frequently tested ideas.

What is the difference between damped and forced oscillations?

In damped oscillations the system loses energy to friction so the amplitude decays exponentially over time on its own. In forced oscillations an external periodic force keeps driving the system, and when the driving frequency matches the natural frequency the amplitude becomes very large, which is called resonance.

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