Magnetism and Matter Class 12 Notes | CBSE Physics Chapter 5 (Free PDF)

Chapter summary

Magnetism and Matter treats a bar magnet as a magnetic dipole and works out its field, the torque, potential energy and oscillations it experiences in a uniform field, then extends the idea to Earth’s magnetism described by declination, dip and the horizontal component. It also classifies all materials as diamagnetic, paramagnetic or ferromagnetic using magnetisation, magnetic intensity and susceptibility. For NEET it is a steady source of conceptual and short numerical questions and ties directly into Moving Charges and Magnetism and electromagnetic induction.

Chapter notes

Key Concepts

1. Bar Magnet as an Equivalent Solenoid

A bar magnet behaves like a solenoid with a fixed magnetic moment. The magnetic field lines of a bar magnet are identical to those of a solenoid.

Magnetic dipole moment: m = NIA (for a solenoid/loop)

Axial field (far away): B = (μ₀/4π)(2m/r³)

Equatorial field (far away): B = (μ₀/4π)(m/r³)

2. Torque on a Magnetic Dipole

τ = m × B = mB sin θ

Potential energy: U = −m · B = −mB cos θ


3. Earth’s Magnetism

The Earth behaves like a giant bar magnet. The geographic north pole is near the magnetic south pole (field lines enter there).

Elements of Earth’s Magnetic Field

ElementSymbolDescription
DeclinationδAngle between geographic north and magnetic north at a place
Dip (Inclination)IAngle between the total magnetic field and the horizontal
Horizontal componentBHBH = B cos I (component along the surface)

Total field: B² = BH² + BV²; tan I = BV/BH

At magnetic poles: I = 90° (BH = 0); At magnetic equator: I = 0° (BV = 0)


4. Classification of Magnetic Materials

PropertyDiamagneticParamagneticFerromagnetic
Response to fieldWeakly repelledWeakly attractedStrongly attracted
Susceptibility (χ)Small, negativeSmall, positiveVery large, positive
Relative permeability (μr)Slightly < 1Slightly > 1>> 1 (10² to 10⁵)
ExamplesBismuth, copper, diamond, waterAluminium, sodium, oxygen, platinumIron, cobalt, nickel, gadolinium
Temperature effectIndependentχ ∝ 1/T (Curie’s law)Above Curie temp → paramagnetic

Key Terms

  • Magnetisation (M): Magnetic moment per unit volume; M = χH
  • Magnetic susceptibility (χ): Measures how easily a material is magnetised
  • Magnetic permeability (μ): μ = μ₀(1 + χ) = μ₀μr
  • Curie temperature: Temperature above which ferromagnetic becomes paramagnetic
  • Hysteresis: Lagging of B behind H when a ferromagnet is magnetised and demagnetised

Hysteresis Loop

  • Retentivity: B remaining when H is reduced to zero
  • Coercivity: Reverse H needed to reduce B to zero
  • Area of hysteresis loop = energy lost per cycle
  • Soft iron: narrow loop (electromagnets, transformers)
  • Steel: wide loop (permanent magnets)

Important Definitions

TermDefinition
Magnetic dipole momentm = NIA - product of current, area, and number of turns
DeclinationAngle between geographic and magnetic meridians at a place
DipAngle of Earth’s field with horizontal
DiamagneticMaterials weakly repelled by magnets (χ < 0)
ParamagneticMaterials weakly attracted by magnets (χ > 0, small)
FerromagneticMaterials strongly attracted by magnets (χ >> 0)
Curie temperatureTemperature above which ferromagnets lose their ferromagnetism
HysteresisLagging of magnetisation behind the applied field in ferromagnets

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Solved Examples

Example 1

At a place, BH = 0.3 G and dip angle = 60°. Find the total magnetic field.

Answer: BH = B cos I → B = BH/cos I = 0.3/cos 60° = 0.3/0.5 = 0.6 G

Example 2

A bar magnet of magnetic moment 0.5 A·m² is placed at 30° to a uniform field of 0.2 T. Find the torque.

Answer: τ = mB sin θ = 0.5 × 0.2 × sin 30° = 0.1 × 0.5 = 0.05 N·m


Important Questions for Board Exams

1-Mark

  1. Define magnetic declination.
  2. What is the Curie temperature?

3-Mark

  1. Classify magnetic materials into three categories. Give properties and examples of each.
  2. Define the three elements of Earth’s magnetic field. How are they related?
  3. What is a hysteresis loop? What do retentivity and coercivity represent?

5-Mark

  1. Distinguish between diamagnetic, paramagnetic, and ferromagnetic materials with examples. Explain the concept of Curie temperature and hysteresis.

Quick Revision Points

  • Bar magnet ≈ magnetic dipole; m = NIA; τ = mB sin θ; U = −mB cos θ
  • Earth’s field: Declination (δ), Dip (I), Horizontal component BH = B cos I
  • Diamagnetic: χ < 0, repelled (Cu, Bi, H₂O); Paramagnetic: χ > 0, weak attraction (Al, O₂)
  • Ferromagnetic: χ >> 0, strong attraction (Fe, Co, Ni); above Curie temp → paramagnetic
  • Curie’s law (paramagnetic): χ ∝ 1/T
  • Hysteresis: retentivity (B at H=0), coercivity (H to make B=0)
  • Soft iron: easy to magnetise/demagnetise (electromagnets); Steel: permanent magnets

Previous: Ch 4 - Moving Charges and Magnetism
Next: Ch 6 - Electromagnetic Induction

🃏 Flash Cards: Magnetism and Matter

Class 12 Physics · Chapter 5 – swipe through all 8 cards to understand the whole chapter.

🧲Start here1/8

Bar Magnet as a Magnetic Dipole

A bar magnet is two equal-and-opposite poles, behaving exactly like a magnetic dipole.

m = m_pole · 2l (unit: A·m2)

2l is the magnetic length (~0.84 of geometric length); moment points S → N.

  • Pole strength m_pole has unit A·m; moment m has unit A·m2
  • No magnetic monopoles — cutting a magnet gives two smaller dipoles
  • Equivalent to a solenoid: m = N I A; field lines are closed loops
📡Core field2/8

Field of a Magnetic Dipole

Reuse electric-dipole results by swapping p → m and 1/(4πε0) → μ0/4π.

B_axial = (μ0/4π)·2m/r3 , B_equator = (μ0/4π)·m/r3

Valid for a short magnet (r ≫ size); μ0/4π = 10⁻7 T·m/A.

  • Axial field is twice the equatorial: B_axial = 2 B_equator
  • Axial B is along m; equatorial B is opposite to m
  • Both fall off as 1/r3 — the dipole signature
🔄Core law3/8

Torque on a Dipole

A uniform field can’t pull a dipole, but it twists it toward alignment.

τ = m B sinθ (vector: τ = m × B)

Net force is zero in a uniform field — only torque acts.

  • Maximum τ = mB at θ = 90°
  • τ = 0 at θ = 0° (stable) and θ = 180° (unstable)
  • A net translational force needs a non-uniform field
Energy4/8

Potential Energy of a Dipole

Aligning with the field is the relaxed, low-energy state; opposing it costs energy.

U = −m B cosθ (vector: U = −m·B)

Work to rotate θ1 → θ2 is W = mB(cosθ1 − cosθ2).

  • Minimum U = −mB at θ = 0° (stable equilibrium)
  • Maximum U = +mB at θ = 180° (unstable)
  • U = 0 at θ = 90° (dipole perpendicular to field)
⏱️Oscillations5/8

Oscillations in a Field

A magnet nudged from alignment swings like a torsional pendulum.

T = 2π √(I / m B)

I is the moment of inertia; used to compare B or m experimentally.

  • Period depends on inertia I, moment m and field B
  • Stronger field or larger moment → faster oscillation
  • Standard NEET method to find m or compare field strengths
🌍Earth’s field6/8

Earth’s Magnetism

Earth acts like a giant tilted bar magnet, fixed by three field elements.

B_H = B_E cos I , B_V = B_E sin I , tan I = B_V / B_H

Magnetic S-pole lies near geographic North; axis tilted ~11.3°.

  • Three elements: Declination D, Dip/Inclination I, Horizontal component B_H
  • Magnetic equator: I = 0° → field horizontal, B_V = 0
  • Magnetic poles: I = 90° → field vertical, B_H = 0; B_E = √(B_H2 + B_V2)
🧪Matter inside7/8

Magnetisation, H & Susceptibility

Inside matter, the applied field, the material’s response and the total field stay separate.

B = μ0(H + M) , M = χ H , μᵣ = 1 + χ

H and M share the unit A/m; χ and μᵣ are dimensionless; μ = μ0μᵣ.

  • H = applied magnetising field, M = magnetisation (moment per volume)
  • χ small negative → dia; small positive → para; large positive → ferro
  • μᵣ < 1 (dia), slightly > 1 (para), ≫ 1 (ferro)
🔬Classification8/8

Dia, Para & Ferromagnetism

Bring a magnet near a material: repelled, weakly pulled, or fiercely pulled sorts all matter.

Para: χ = C/T ; Ferro above T_c: χ = C/(T − T_c)

Memory hook: Dia = away, Para = pulled, Ferro = fiercely pulled.

  • Diamagnetic (Bi, Cu, water): χ < 0, temp-independent; superconductor χ = −1
  • Paramagnetic (Al, Na, O2): χ small +, obeys Curie’s law χ = C/T
  • Ferromagnetic (Fe, Co, Ni): χ ≫ 0, domains & hysteresis; → paramagnetic above T_c
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📝 Practice Magnetism and Matter — 10 NEET PYQs
Real previous-year questions · with answers & solutions
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Tap an option to check your answer and see the worked solution. Every question is a real NEET previous-year question.
Q1NEET 2021
A uniform conducting wire of length 12a and resistance R is wound into a current-carrying coil first as (1) an equilateral triangle of side a and then as (2) a square of side a. The magnetic dipole moments of the coil carrying current I in the two cases are respectively:
Correct answer: A. Triangle: perimeter 3a, so number of turns n = 12a/3a = 4; area = (√(3))/(4)a². Moment M₁ = nIA = 4 × I × (√(3))/(4)a² = √(3) Ia². Square: perimeter 4a, so n = 12a/4a = 3; area = a². Moment M₂ = 3 × I × a² = 3 Ia².
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Q2NEET 2020
An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A·m⁻¹. Taking μ₀ = 4π×10⁻⁷ T·m·A⁻¹, the permeability of the material of the rod is:
Correct answer: D. μ = μ₀(1+χ) = 4π×10⁻⁷(1 + 599) = 4π×10⁻⁷×600 = 2400π×10⁻⁷ = 2.4π×10⁻⁴ T·m·A⁻¹. (The magnetising field value is not needed.)
🔎 See the full step-by-step solution in the app →
Q3NEET 2020
A wire of length L carrying a current I is bent into the form of a single circular loop. Its magnetic moment is:
Correct answer: D. The wire forms a circle of circumference L = 2π R, so R = (L)/(2π). Magnetic moment M = I A = I π R² = Iπ((L)/(2π))² = (Iπ L²)/(4π²) = (IL²)/(4π).
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Q4NEET 2019
At a point A on Earth’s surface the angle of dip is δ = +25°, and at a point B it is δ = -25°. We can interpret that:
Correct answer: B. The angle of dip is taken positive in the northern hemisphere (north-seeking end of a freely suspended needle dips downward) and negative in the southern hemisphere. A positive dip (+25°) means A is in the northern hemisphere; a negative dip (−25°) means B is in the southern hemisphere.
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Q5NEET 2019
If H, V and δ are the horizontal component, vertical component and angle of dip, and B_E is the total magnetic field of Earth, the correct relations are:
Correct answer: B. Resolving the total field B_E along the horizontal and vertical using the dip angle δ: the horizontal component H = B_Ecosδ and the vertical component V = B_Esinδ. (Check: tanδ = V/H, consistent.)
🔎 See the full step-by-step solution in the app →
Q6NEET 2018
A thin diamagnetic rod is placed vertically between the poles of an electromagnet. When the current is switched on, the rod is pushed up, out of the horizontal magnetic field, gaining gravitational potential energy. The work required to do this comes from:
Correct answer: C. A diamagnetic substance is repelled from a strong field toward a weaker one, so the rod is pushed up. As it rises, the change in flux through the circuit opposes the current (Lenz’s law), so the external current source must supply the extra energy to keep the current flowing. Hence the work done (the gain in gravitational PE) ultimately comes from the current source.
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Q7NEET 2017
A 250-turn rectangular coil of length 2.1 cm and width 1.25 cm carries a current of 85 μA and is placed in a magnetic field of 0.85 T. The work done in rotating the coil by 180° against the torque is:
Correct answer: A. Magnetic moment M = NIA = 250 × (85×10⁻⁶) × (0.021 × 0.0125) = 5.58×10⁻⁶ A·m². Work to rotate from 0° to 180°: W = MB(cos0° – cos180°) = 2MB = 2 × 5.58×10⁻⁶ × 0.85 = 9.48×10⁻⁶ J ≈ 9.5 μJ. Closest option is 9.1 μJ.
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Q8NEET 2016
A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equilibrium. The energy required to rotate it through 60° is W. The torque required to hold the magnet in this new position is:
Correct answer: B. Work to rotate from 0° to 60°: W = MB(cos0° – cos60°) = MB(1 – (1)/(2)) = (MB)/(2), so MB = 2W. Torque at 60°: τ = MBsin60° = 2W × (√(3))/(2) = √(3) W.
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Q9NEET 2016
Magnetic susceptibility is negative for:
Correct answer: D. Susceptibility χ = μᵣ – 1. For diamagnetic materials μᵣ < 1, so χ is negative. Paramagnetic and ferromagnetic materials have μᵣ > 1, so their χ is positive. Hence χ is negative for diamagnetic materials only.
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Q10NEET 1998
For protecting a sensitive equipment from an external magnetic field, it should be:
Correct answer: B. Iron is ferromagnetic with very high permeability, so it draws the external magnetic field lines into its walls and leaves the interior nearly field-free (magnetic shielding). Hence the equipment is protected by enclosing it in an iron can. Aluminium and copper (non-ferromagnetic) cannot redirect a static magnetic field.
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Frequently Asked Questions

What is a magnetic dipole and what is magnetic moment?

A magnetic dipole is a pair of equal and opposite magnetic poles separated by a small distance, and a bar magnet behaves exactly like one. Its magnetic moment m equals pole strength times the magnetic length 2l, has unit ampere metre squared, and points from the south pole to the north pole.

What are the axial and equatorial field formulas for a short bar magnet?

On the axial line the field is B = (mu0 / 4pi) times 2m / r cubed, and on the equatorial line it is B = (mu0 / 4pi) times m / r cubed, so the axial field is twice the equatorial field. Both fall off as 1 over r cubed, which is the signature of a dipole.

What is the torque and potential energy of a magnetic dipole in a uniform field?

The torque is tau = mB sin theta, which is maximum at 90 degrees and zero when the dipole is aligned or anti-aligned with the field. The potential energy is U = minus mB cos theta, minimum at 0 degrees (stable equilibrium) and maximum at 180 degrees (unstable).

What is the difference between diamagnetic, paramagnetic and ferromagnetic materials?

Diamagnetic materials (like bismuth and copper) have a small negative susceptibility and are weakly repelled, paramagnetic materials (like aluminium and oxygen) have a small positive susceptibility and are weakly attracted and obey Curie’s law, and ferromagnetic materials (like iron, cobalt and nickel) have a very large positive susceptibility, show domains and hysteresis, and become paramagnetic above the Curie temperature.

Is Magnetism and Matter important for NEET?

Yes, it is part of the Class 12 NEET physics syllabus and usually contributes one question, mostly conceptual or short numerical, on torque, potential energy, Earth’s magnetic elements, or the dia, para and ferro classification. It is best prepared together with Moving Charges and Magnetism.

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